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LTM EXAM SOLUTIONS

LTM EXAM SOLUTIONS

رفتن به کانال در Telegram

🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

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📈 تحلیل کانال تلگرام LTM EXAM SOLUTIONS

کانال LTM EXAM SOLUTIONS (@coding_are) در بخش زبانی انگلیسی بازیگری فعال است. در حال حاضر جامعه شامل 14 105 مشترک است و جایگاه 14 118 را در دسته آموزش و رتبه 28 127 را در منطقه الهند دارد.

📊 شاخص‌های مخاطب و پویایی

از زمان ایجاد در невідомо، پروژه رشد سریعی داشته و 14 105 مشترک جذب کرده است.

بر اساس آخرین داده‌ها در تاریخ 04 اکتبر, 2026، کانال فعالیت پایداری دارد. در ۳۰ روز گذشته تغییر اعضا برابر -108 و در ۲۴ ساعت گذشته برابر -5 بوده و همچنان دسترسی گسترده‌ای حفظ شده است.

  • وضعیت تأیید: تأیید نشده
  • نرخ تعامل (ER): میانگین تعامل مخاطب 3.62% است و در ۲۴ ساعت نخست پس از انتشار، محتوا معمولاً 1.74% واکنش نسبت به کل مشترکان کسب می‌کند.
  • دسترسی پست‌ها: هر پست به طور میانگین 511 بازدید دریافت می‌کند. در اولین روز معمولاً 246 بازدید جمع‌آوری می‌شود.
  • واکنش‌ها و تعامل: مخاطبان به‌طور فعال حمایت می‌کنند؛ میانگین واکنش به هر پست 2 است.
  • علایق موضوعی: محتوا بر موضوعات کلیدی مانند placement, gaurntee, suree, capgemini, infosy تمرکز دارد.

📝 توضیح و سیاست محتوایی

نویسنده این فضا را محل بیان دیدگاه‌های شخصی توصیف می‌کند:
“🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...”

به لطف به‌روزرسانی‌های پرتکرار (آخرین داده در تاریخ 05 اکتبر, 2026)، کانال همواره به‌روز و دارای دسترسی بالاست. تحلیل‌ها نشان می‌دهد مخاطبان به‌طور فعال با محتوا تعامل دارند و آن را به نقطه اثرگذاری مهم در دسته آموزش تبدیل کرده‌اند.

14 100
مشترکین
-524 ساعت
-247 روز
-10830 روز
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def is_modest(number): str_num = str(number) length = len(str_num) for i in range(1, length): left_part = int(str_num[:i]) right_part = int(str_num[i:]) if right_part != 0 and number % right_part == left_part: return True return False def find_modest_numbers(M, N): modest_numbers = [] for number in range(M, N + 1): if is_modest(number): modest_numbers.append(number) return modest_numbers M, N = map(int, input().split()) modest_numbers = find_modest_numbers(M, N) if modest_numbers: print(" ".join(map(str, modest_numbers))) else: print("No modest numbers found within the range")

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