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MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

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🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

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📈 Telegram kanali MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer analitikasi

MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer (@coding_are) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 13 236 obunachidan iborat bo'lib, Taʼlim toifasida 15 345-o'rinni va Hindiston mintaqasida 32 011-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 13 236 obunachiga ega bo‘ldi.

19 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -137 ga, so‘nggi 24 soatda esa -4 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 2.81% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.07% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 372 marta ko‘riladi; birinchi sutkada odatda 142 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 2 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent placement, gaurntee, suree, capgemini, infosy kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...

Yuqori yangilanish chastotasi (oxirgi ma’lumot 20 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

13 236
Obunachilar
-424 soatlar
-407 kunlar
-13730 kunlar
Postlar arxiv
#include<bits/stdc++.h> using namespace std; using ll = long long; vector<string> read(){     vector<string> strs;     string line;     getline(cin , line);     istringstream iss(line);     copy(istream_iterator<string>(iss), istream_iterator<string>(), back_inserter(strs));     return strs; } map<string , vector<string>> graph; map<string , ll> mask , id; map<string , string> open; ll ans = 0; ll dfs1(string &u){     ll curr = id.count(u) ? 1LL << id[u] : 0;     for(string &v : graph[u]) curr |= dfs1(v);     return mask[u] = curr; } void dfs2(string &u , int bit){     if(id[u] == bit){         open[u] = u;         return;     }     for(string &v : graph[u]){         if(mask[v] >> bit & 1){             if(open[u] != v) ans++ , open[u] = v;             return dfs2(v , bit);         }     } } int main(){     ll N ; cin >> N;     cin.ignore();     while(N--){         vector<string> children = read();         reverse(children.begin() , children.end());         string parent = children.back();         children.pop_back();         graph[parent] = children;     }     ll cid = 0;     vector<string> colors = read();     for(string &color : colors) if(!id.count(color)) id[color] = ++cid;     string u = "source";     dfs1(u);     for(string &color : colors) dfs2(u , id[color]);     cout << ans;     return 0; } Route the balls

Next code uploaded sooon with proofs 👇👇👇👇👇

JustifyWords def max_words_fitted(k, words, n, m): words = [word for word in words if len(word) <= m] def backtrack(index, lines): if index == len(words): return sum(len(line.split()) for line in lines) max_words = 0 word = words[index] for i in range(len(lines)): if len(lines[i]) + len(word) + (1 if lines[i] else 0) <= m: original_line = lines[i] lines[i] = lines[i] + (' ' if lines[i] else '') + word max_words = max(max_words, backtrack(index + 1, lines)) lines[i] = original_line if len(lines) < n: lines.append(word) max_words = max(max_words, backtrack(index + 1, lines)) lines.pop() return max_words return backtrack(0, []) # Input k = int(input().strip()) words = [input().strip() for _ in range(k)] n, m = map(int, input().strip().split()) print(max_words_fitted(k, words, n, m))

1)Flight Optimization TCS CodeVita accepted 2)magic stars intensity ac 3)Sofa problem done with private 4)Faulty sankes and ladders 5)Frenkitsen wala Codevita These code are Allredy uploaded with 💯 correct answer Dance rev 100% Working

https://t.me/codeing_are Share the group ✅✅✅✅✅✅✅✅✅✅✅✅

// Flight Optimization TCS CodeVita accepted

#include <bits/stdc++.h> using namespace std; #define loop(i, a, n) for (lli i = (a); i < (n); ++i) #define loopD(i, a, n) for (lli i = (a); i >= (n); --i) #define all(c) (c).begin(), (c).end() #define rall(c) (c).rbegin(), (c).rend() #define sz(a) ((int)a.size()) #define YES cout << "YES" << endl; #define NO cout << "NO" << endl; #define endl '\n' #define fastio std::ios::sync_with_stdio(false), cin.tie(NULL), cout.tie(NULL); #define pb push_back #define pp pop_back() #define fi first #define si second #define v(a) vector<int>(a) #define vv(a) vector<vector<int>>(a) #define present(c, x) ((c).find(x) != (c).end()) #define set_bits __builtin_popcountll #define MOD 1000000007 #define int long long typedef long long lli; typedef vector<int> vi; typedef vector<vi> vvi; typedef pair<lli, lli> pll; typedef pair<int, int> pii; typedef unordered_map<int, int> umpi; typedef map<int, int> mpi; typedef vector<pii> vp; typedef vector<lli> vll; typedef vector<vll> vvll; struct Flight { string src; string to; int dt; int at; int cost; }; int parse_time(const string& time_str) { int hour = stoi(time_str.substr(0, 2)); int minute = stoi(time_str.substr(3, 2)); string am_pm = time_str.substr(5, 2); if (am_pm == "Am") { if (hour == 12) hour = 0; } else if (am_pm == "Pm") { if (hour != 12) hour += 12; } return hour * 60 + minute; } void solve() { int N; cin >> N; vector<Flight> fff(N); unordered_map<string, vector<Flight>> mp; for (int i = 0; i < N; ++i) { string src, to, des, arrival_str; int cost; cin >> src >> to >> des >> arrival_str >> cost; int dt = parse_time(des); int at = parse_time(arrival_str); Flight ff = {src, to, dt, at, cost}; fff[i] = ff; mp[src].push_back(ff); } string src, des; cin >> src >> des; string edes, last; cin >> edes >> last; int earliest_dt = parse_time(edes); int latest_at = parse_time(last); typedef tuple<int, int, string> State; priority_queue<State, vector<State>, greater<State>> pq; for (const auto& ff : mp[src]) { if (ff.dt >= earliest_dt) { if (ff.at <= latest_at) { pq.emplace(ff.cost, ff.at, ff.to); } } } unordered_map<string, int> ans; unordered_map<string, int> at; while (!pq.empty()) { int cost_so_far, current_at; string current_city; tie(cost_so_far, current_at, current_city) = pq.top(); pq.pop(); if (ans.find(current_city) != ans.end()) { if (cost_so_far > ans[current_city]) continue; if (cost_so_far == ans[current_city] && current_at >= at[current_city]) continue; } ans[current_city] = cost_so_far; at[current_city] = current_at; if (current_city == des) { cout << cost_so_far; return ; } for (const auto& ff : mp[current_city]) { if (ff.dt >= current_at) { if (ff.dt >= earliest_dt && ff.at <= latest_at) { int new_cost = cost_so_far + ff.cost; pq.emplace(new_cost, ff.at, ff.to); } } } } cout << "Impossible"; return ; } int32_t main() { int tc = 1; // cin >> tc; while (tc--) { solve(); } return 0; }

#include <bits/stdc++.h> using namespace std; #define loop(i, a, n) for (lli i = (a); i < (n); ++i) #define loopD(i, a, n) for (lli i = (a); i >= (n); --i) #define all(c) (c).begin(), (c).end() #define rall(c) (c).rbegin(), (c).rend() #define sz(a) ((lli)a.size()) #define YES cout << "YES" << endl; #define NO cout << "NO" << endl; #define endl '\n' #define fastio std::ios::sync_with_stdio(false), cin.tie(NULL), cout.tie(NULL); #define pb push_back #define pp pop_back() #define fi first #define si second #define v(a) vector<int>(a) #define vv(a) vector<vector<int>>(a) #define present(c, x) ((c).find(x) != (c).end()) #define set_bits __builtin_popcountll #define MOD 1000000007 #define int long long typedef long long lli; typedef vector<int> vi; typedef vector<vi> vvi; typedef pair<lli, lli> pll; typedef pair<int, int> pii; typedef unordered_map<int, int> umpi; typedef map<int, int> mpi; typedef vector<pii> vp; typedef vector<lli> vll; typedef vector<vll> vvll; struct Line { int x1, y1, x2, y2; bool vertical() const { return x1 == x2; } bool horizontal() const { return y1 == y2; } bool diagonal() const { return abs(x2 - x1) == abs(y2 - y1); } }; int N, K; vector<Line> lines; map<pair<int, int>, vector<int>> ptsMap; void add(const Line& line, int idx) { int x1 = line.x1, y1 = line.y1; int x2 = line.x2, y2 = line.y2; if (line.vertical()) { int yStart = min(y1, y2); int yEnd = max(y1, y2); for(int y = yStart; y <= yEnd; y++) { ptsMap[{x1, y}].push_back(idx); } } else if (line.horizontal()) { int xStart = min(x1, x2); int xEnd = max(x1, x2); for(int x = xStart; x <= xEnd; x++) { ptsMap[{x, y1}].push_back(idx); } } else if (line.diagonal()) { int steps = abs(x2 - x1); int dx = (x2 - x1) / steps; int dy = (y2 - y1) / steps; for(int i = 0; i <= steps; i++) { int x = x1 + i * dx; int y = y1 + i * dy; ptsMap[{x, y}].push_back(idx); } } } int ff(int x1, int y1, int x2, int y2) { if(x1 == x2) return abs(y1 - y2); if(y1 == y2) return abs(x1 - x2); if(abs(x1 - x2) == abs(y1 - y2)) return abs(x1 - x2); return 0; } int solve(const pair<int, int>& pt, const vector<int>& lst) { vector<int> d; for(auto lIdx : lst) { const Line& ln = lines[lIdx]; bool oneSided = (pt.first == ln.x1 && pt.second == ln.y1) || (pt.first == ln.x2 && pt.second == ln.y2); if(oneSided) { int ex = (pt.first == ln.x1 && pt.second == ln.y1) ? ln.x2 : ln.x1; int ey = (pt.first == ln.x1 && pt.second == ln.y1) ? ln.y2 : ln.y1; d.push_back(ff(pt.first, pt.second, ex, ey)); } else { d.push_back(ff(pt.first, pt.second, ln.x1, ln.y1)); d.push_back(ff(pt.first, pt.second, ln.x2, ln.y2)); } } return d.empty() ? 0 : *min_element(d.begin(), d.end()); } void solve() { cin >> N; lines.resize(N); for(int i = 0; i < N; i++) { cin >> lines[i].x1 >> lines[i].y1 >> lines[i].x2 >> lines[i].y2; add(lines[i], i); } cin >> K; int total = 0; for(auto &[pt, lst] : ptsMap) { if(sz(lst) == K) { total += solve(pt, lst); } } cout << total; } int32_t main() { solve(); return 0; } // magic stars intensity ac Full accepted ☺️

Hiii every I will share today also TCS codevitaa exam code in my channel
So please share the group for your frd and family and big group
https://t.me/codeing_are Join the group I will upload each every answer in free

Magic Star Intensity Code TCS CodeVita Zone 1 #include <iostream> #include <vector> #include <map> #include <set> #include <cmath> #include <algorithm> using namespace std; struct Line {     int x1, y1, x2, y2; }; int countCells(Line line, pair<int, int> star, bool split) {     if (line.x1 == line.x2) {         if (split) {             return min(abs(star.second - line.y1), abs(star.second - line.y2)) + 1;         }         else {             return abs(line.y1 - line.y2) + 1;         }     }     else {         if (split) {             return min(abs(star.first - line.x1), abs(star.first - line.x2)) + 1;         }         else {             return abs(line.x1 - line.x2) + 1;         }     } } bool intersects(Line a, Line b, pair<int, int>& intersection) {     if (a.x1 == a.x2 && b.y1 == b.y2) {         if (b.x1 <= a.x1 && a.x1 <= b.x2 && a.y1 <= b.y1 && b.y1 <= a.y2) {             intersection = {a.x1, b.y1};             return true;         }     }     if (a.y1 == a.y2 && b.x1 == b.x2) {         if (a.x1 <= b.x1 && b.x1 <= a.x2 && b.y1 <= a.y1 && a.y1 <= b.y2) {             intersection = {b.x1, a.y1};             return true;         }     }     return false; } int main() {     int N, K;     cin >> N;     vector<Line> lines(N);     for (int i = 0; i < N; ++i) {         cin >> lines[i].x1 >> lines[i].y1 >> lines[i].x2 >> lines[i].y2;         if (lines[i].x1 > lines[i].x2 || (lines[i].x1 == lines[i].x2 && lines[i].y1 > lines[i].y2)) {             swap(lines[i].x1, lines[i].x2);             swap(lines[i].y1, lines[i].y2);         }     }     cin >> K;     map<pair<int, int>, vector<Line>> stars;     for (int i = 0; i < N; ++i) {         for (int j = i + 1; j < N; ++j) {             pair<int, int> intersection;             if (intersects(lines[i], lines[j], intersection)) {                 stars[intersection].push_back(lines[i]);                 stars[intersection].push_back(lines[j]);             }         }     }     int placementlelo = 0;     for (auto& star : stars) {         if (star.second.size() / 2 == K) {             vector<int> intensities;             for (auto& line : star.second) {                 intensities.push_back(countCells(line, star.first, true));             }             placementlelo += *min_element(intensities.begin(), intensities.end());         }     }     cout << placementlelo << endl;     return 0; } Magic Star Intensity Code C++ TCS CodeVita Zone 1

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