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MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

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🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

إظهار المزيد

📈 نظرة تحليلية على قناة تيليجرام MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

تُعد قناة MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer (@coding_are) في القطاع اللغوي الإنكليزية لاعباً نشطاً. يضم المجتمع حالياً 13 236 مشتركاً، محتلاً المرتبة 15 345 في فئة التعليم والمرتبة 32 011 في منطقة الهند.

📊 مؤشرات الجمهور والحراك

منذ تأسيسه في невідомо، حقق المشروع نمواً سريعاً وجمع 13 236 مشتركاً.

بحسب آخر البيانات بتاريخ 19 يونيو, 2026، تحافظ القناة على نشاط مستقر. خلال آخر 30 يوماً تغيّر عدد الأعضاء بمقدار -137، وفي آخر 24 ساعة بمقدار -4، مع بقاء الوصول العام مرتفعاً.

  • حالة التحقق: غير موثّقة
  • معدل التفاعل (ER): يبلغ متوسط تفاعل الجمهور 2.81‎%. وخلال أول 24 ساعة من النشر يحصد المحتوى عادةً 1.07‎% من ردود الفعل نسبةً إلى إجمالي المشتركين.
  • وصول المنشورات: يحصل كل منشور على متوسط 372 مشاهدة. وخلال اليوم الأول يجمع عادةً 142 مشاهدة.
  • التفاعلات والاستجابة: يتفاعل الجمهور بانتظام؛ متوسط التفاعلات لكل منشور يبلغ 2.
  • الاهتمامات الموضوعية: يركز المحتوى على مواضيع رئيسية مثل placement, gaurntee, suree, capgemini, infosy.

📝 الوصف وسياسة المحتوى

يصف المؤلف القناة بأنها مساحة للتعبير عن الآراء الذاتية:
🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...

بفضل وتيرة التحديث المرتفعة (أحدث البيانات بتاريخ 20 يونيو, 2026) تحافظ القناة على حداثتها ومستوى وصول مرتفع. وتُظهر التحليلات تفاعلاً نشطاً من الجمهور، ما يجعلها نقطة تأثير مهمة ضمن فئة التعليم.

13 236
المشتركون
-424 ساعات
-407 أيام
-13730 أيام
أرشيف المشاركات
#include<bits/stdc++.h> using namespace std; using ll = long long; vector<string> read(){     vector<string> strs;     string line;     getline(cin , line);     istringstream iss(line);     copy(istream_iterator<string>(iss), istream_iterator<string>(), back_inserter(strs));     return strs; } map<string , vector<string>> graph; map<string , ll> mask , id; map<string , string> open; ll ans = 0; ll dfs1(string &u){     ll curr = id.count(u) ? 1LL << id[u] : 0;     for(string &v : graph[u]) curr |= dfs1(v);     return mask[u] = curr; } void dfs2(string &u , int bit){     if(id[u] == bit){         open[u] = u;         return;     }     for(string &v : graph[u]){         if(mask[v] >> bit & 1){             if(open[u] != v) ans++ , open[u] = v;             return dfs2(v , bit);         }     } } int main(){     ll N ; cin >> N;     cin.ignore();     while(N--){         vector<string> children = read();         reverse(children.begin() , children.end());         string parent = children.back();         children.pop_back();         graph[parent] = children;     }     ll cid = 0;     vector<string> colors = read();     for(string &color : colors) if(!id.count(color)) id[color] = ++cid;     string u = "source";     dfs1(u);     for(string &color : colors) dfs2(u , id[color]);     cout << ans;     return 0; } Route the balls

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Next code uploaded sooon with proofs 👇👇👇👇👇

JustifyWords def max_words_fitted(k, words, n, m): words = [word for word in words if len(word) <= m] def backtrack(index, lines): if index == len(words): return sum(len(line.split()) for line in lines) max_words = 0 word = words[index] for i in range(len(lines)): if len(lines[i]) + len(word) + (1 if lines[i] else 0) <= m: original_line = lines[i] lines[i] = lines[i] + (' ' if lines[i] else '') + word max_words = max(max_words, backtrack(index + 1, lines)) lines[i] = original_line if len(lines) < n: lines.append(word) max_words = max(max_words, backtrack(index + 1, lines)) lines.pop() return max_words return backtrack(0, []) # Input k = int(input().strip()) words = [input().strip() for _ in range(k)] n, m = map(int, input().strip().split()) print(max_words_fitted(k, words, n, m))

1)Flight Optimization TCS CodeVita accepted 2)magic stars intensity ac 3)Sofa problem done with private 4)Faulty sankes and ladders 5)Frenkitsen wala Codevita These code are Allredy uploaded with 💯 correct answer Dance rev 100% Working

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// Flight Optimization TCS CodeVita accepted

#include <bits/stdc++.h> using namespace std; #define loop(i, a, n) for (lli i = (a); i < (n); ++i) #define loopD(i, a, n) for (lli i = (a); i >= (n); --i) #define all(c) (c).begin(), (c).end() #define rall(c) (c).rbegin(), (c).rend() #define sz(a) ((int)a.size()) #define YES cout << "YES" << endl; #define NO cout << "NO" << endl; #define endl '\n' #define fastio std::ios::sync_with_stdio(false), cin.tie(NULL), cout.tie(NULL); #define pb push_back #define pp pop_back() #define fi first #define si second #define v(a) vector<int>(a) #define vv(a) vector<vector<int>>(a) #define present(c, x) ((c).find(x) != (c).end()) #define set_bits __builtin_popcountll #define MOD 1000000007 #define int long long typedef long long lli; typedef vector<int> vi; typedef vector<vi> vvi; typedef pair<lli, lli> pll; typedef pair<int, int> pii; typedef unordered_map<int, int> umpi; typedef map<int, int> mpi; typedef vector<pii> vp; typedef vector<lli> vll; typedef vector<vll> vvll; struct Flight { string src; string to; int dt; int at; int cost; }; int parse_time(const string& time_str) { int hour = stoi(time_str.substr(0, 2)); int minute = stoi(time_str.substr(3, 2)); string am_pm = time_str.substr(5, 2); if (am_pm == "Am") { if (hour == 12) hour = 0; } else if (am_pm == "Pm") { if (hour != 12) hour += 12; } return hour * 60 + minute; } void solve() { int N; cin >> N; vector<Flight> fff(N); unordered_map<string, vector<Flight>> mp; for (int i = 0; i < N; ++i) { string src, to, des, arrival_str; int cost; cin >> src >> to >> des >> arrival_str >> cost; int dt = parse_time(des); int at = parse_time(arrival_str); Flight ff = {src, to, dt, at, cost}; fff[i] = ff; mp[src].push_back(ff); } string src, des; cin >> src >> des; string edes, last; cin >> edes >> last; int earliest_dt = parse_time(edes); int latest_at = parse_time(last); typedef tuple<int, int, string> State; priority_queue<State, vector<State>, greater<State>> pq; for (const auto& ff : mp[src]) { if (ff.dt >= earliest_dt) { if (ff.at <= latest_at) { pq.emplace(ff.cost, ff.at, ff.to); } } } unordered_map<string, int> ans; unordered_map<string, int> at; while (!pq.empty()) { int cost_so_far, current_at; string current_city; tie(cost_so_far, current_at, current_city) = pq.top(); pq.pop(); if (ans.find(current_city) != ans.end()) { if (cost_so_far > ans[current_city]) continue; if (cost_so_far == ans[current_city] && current_at >= at[current_city]) continue; } ans[current_city] = cost_so_far; at[current_city] = current_at; if (current_city == des) { cout << cost_so_far; return ; } for (const auto& ff : mp[current_city]) { if (ff.dt >= current_at) { if (ff.dt >= earliest_dt && ff.at <= latest_at) { int new_cost = cost_so_far + ff.cost; pq.emplace(new_cost, ff.at, ff.to); } } } } cout << "Impossible"; return ; } int32_t main() { int tc = 1; // cin >> tc; while (tc--) { solve(); } return 0; }

#include <bits/stdc++.h> using namespace std; #define loop(i, a, n) for (lli i = (a); i < (n); ++i) #define loopD(i, a, n) for (lli i = (a); i >= (n); --i) #define all(c) (c).begin(), (c).end() #define rall(c) (c).rbegin(), (c).rend() #define sz(a) ((lli)a.size()) #define YES cout << "YES" << endl; #define NO cout << "NO" << endl; #define endl '\n' #define fastio std::ios::sync_with_stdio(false), cin.tie(NULL), cout.tie(NULL); #define pb push_back #define pp pop_back() #define fi first #define si second #define v(a) vector<int>(a) #define vv(a) vector<vector<int>>(a) #define present(c, x) ((c).find(x) != (c).end()) #define set_bits __builtin_popcountll #define MOD 1000000007 #define int long long typedef long long lli; typedef vector<int> vi; typedef vector<vi> vvi; typedef pair<lli, lli> pll; typedef pair<int, int> pii; typedef unordered_map<int, int> umpi; typedef map<int, int> mpi; typedef vector<pii> vp; typedef vector<lli> vll; typedef vector<vll> vvll; struct Line { int x1, y1, x2, y2; bool vertical() const { return x1 == x2; } bool horizontal() const { return y1 == y2; } bool diagonal() const { return abs(x2 - x1) == abs(y2 - y1); } }; int N, K; vector<Line> lines; map<pair<int, int>, vector<int>> ptsMap; void add(const Line& line, int idx) { int x1 = line.x1, y1 = line.y1; int x2 = line.x2, y2 = line.y2; if (line.vertical()) { int yStart = min(y1, y2); int yEnd = max(y1, y2); for(int y = yStart; y <= yEnd; y++) { ptsMap[{x1, y}].push_back(idx); } } else if (line.horizontal()) { int xStart = min(x1, x2); int xEnd = max(x1, x2); for(int x = xStart; x <= xEnd; x++) { ptsMap[{x, y1}].push_back(idx); } } else if (line.diagonal()) { int steps = abs(x2 - x1); int dx = (x2 - x1) / steps; int dy = (y2 - y1) / steps; for(int i = 0; i <= steps; i++) { int x = x1 + i * dx; int y = y1 + i * dy; ptsMap[{x, y}].push_back(idx); } } } int ff(int x1, int y1, int x2, int y2) { if(x1 == x2) return abs(y1 - y2); if(y1 == y2) return abs(x1 - x2); if(abs(x1 - x2) == abs(y1 - y2)) return abs(x1 - x2); return 0; } int solve(const pair<int, int>& pt, const vector<int>& lst) { vector<int> d; for(auto lIdx : lst) { const Line& ln = lines[lIdx]; bool oneSided = (pt.first == ln.x1 && pt.second == ln.y1) || (pt.first == ln.x2 && pt.second == ln.y2); if(oneSided) { int ex = (pt.first == ln.x1 && pt.second == ln.y1) ? ln.x2 : ln.x1; int ey = (pt.first == ln.x1 && pt.second == ln.y1) ? ln.y2 : ln.y1; d.push_back(ff(pt.first, pt.second, ex, ey)); } else { d.push_back(ff(pt.first, pt.second, ln.x1, ln.y1)); d.push_back(ff(pt.first, pt.second, ln.x2, ln.y2)); } } return d.empty() ? 0 : *min_element(d.begin(), d.end()); } void solve() { cin >> N; lines.resize(N); for(int i = 0; i < N; i++) { cin >> lines[i].x1 >> lines[i].y1 >> lines[i].x2 >> lines[i].y2; add(lines[i], i); } cin >> K; int total = 0; for(auto &[pt, lst] : ptsMap) { if(sz(lst) == K) { total += solve(pt, lst); } } cout << total; } int32_t main() { solve(); return 0; } // magic stars intensity ac Full accepted ☺️

Hiii every I will share today also TCS codevitaa exam code in my channel
So please share the group for your frd and family and big group
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Magic Star Intensity Code TCS CodeVita Zone 1 #include <iostream> #include <vector> #include <map> #include <set> #include <cmath> #include <algorithm> using namespace std; struct Line {     int x1, y1, x2, y2; }; int countCells(Line line, pair<int, int> star, bool split) {     if (line.x1 == line.x2) {         if (split) {             return min(abs(star.second - line.y1), abs(star.second - line.y2)) + 1;         }         else {             return abs(line.y1 - line.y2) + 1;         }     }     else {         if (split) {             return min(abs(star.first - line.x1), abs(star.first - line.x2)) + 1;         }         else {             return abs(line.x1 - line.x2) + 1;         }     } } bool intersects(Line a, Line b, pair<int, int>& intersection) {     if (a.x1 == a.x2 && b.y1 == b.y2) {         if (b.x1 <= a.x1 && a.x1 <= b.x2 && a.y1 <= b.y1 && b.y1 <= a.y2) {             intersection = {a.x1, b.y1};             return true;         }     }     if (a.y1 == a.y2 && b.x1 == b.x2) {         if (a.x1 <= b.x1 && b.x1 <= a.x2 && b.y1 <= a.y1 && a.y1 <= b.y2) {             intersection = {b.x1, a.y1};             return true;         }     }     return false; } int main() {     int N, K;     cin >> N;     vector<Line> lines(N);     for (int i = 0; i < N; ++i) {         cin >> lines[i].x1 >> lines[i].y1 >> lines[i].x2 >> lines[i].y2;         if (lines[i].x1 > lines[i].x2 || (lines[i].x1 == lines[i].x2 && lines[i].y1 > lines[i].y2)) {             swap(lines[i].x1, lines[i].x2);             swap(lines[i].y1, lines[i].y2);         }     }     cin >> K;     map<pair<int, int>, vector<Line>> stars;     for (int i = 0; i < N; ++i) {         for (int j = i + 1; j < N; ++j) {             pair<int, int> intersection;             if (intersects(lines[i], lines[j], intersection)) {                 stars[intersection].push_back(lines[i]);                 stars[intersection].push_back(lines[j]);             }         }     }     int placementlelo = 0;     for (auto& star : stars) {         if (star.second.size() / 2 == K) {             vector<int> intensities;             for (auto& line : star.second) {                 intensities.push_back(countCells(line, star.first, true));             }             placementlelo += *min_element(intensities.begin(), intensities.end());         }     }     cout << placementlelo << endl;     return 0; } Magic Star Intensity Code C++ TCS CodeVita Zone 1

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