ACCENTURE EXAM HELP ! CISCO EXAM !

Open in Telegram

🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

India31 490 Education15 294...

📈 Analytical overview of Telegram channel ACCENTURE EXAM HELP ! CISCO EXAM !

Channel ACCENTURE EXAM HELP ! CISCO EXAM ! (@coding_are) in the English language segment is an active participant. Currently, the community unites 13 207 subscribers, ranking 15 294 in the Education category and 31 490 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 13 207 subscribers.

According to the latest data from 30 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -144 over the last 30 days and by 6 over the last 24 hours, overall reach remains high.

Verification status: Not verified
Engagement rate (ER): The average audience engagement rate is 3.08%. Within the first 24 hours after publication, content typically collects 1.29% reactions from the total number of subscribers.
Post reach: On average, each post receives 407 views. Within the first day, a publication typically gains 170 views.
Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
Thematic interests: Content is focused on key topics such as placement, gaurntee, suree, capgemini, infosy.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
“🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...”

Thanks to the high frequency of updates (latest data received on 01 July, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

13 207

Subscribers

+624 hours

-127 days

-14430 days

407

Post views

~ 17024 hours

~ 24048 hours

3.08%

Engagement rate

~ 3

Posts per day

Ads index

beta

Posts Archive

13 206

elitmus , Deloitte (26, 27, 28, All slots), HCL, IBM, any other exams Offcampus or on campus exam help Available ✅💯 Only codeing help also available ✅ 💯% clearance guarantee and genuine help Contact @srksvk Remote access available for all exams ✅

13 206

Atkins realis exam successfully done by remote access ✅✅ Core company exam :: electrical engineering Ctc :: 15 lpa All electrical question done ✅ with 💯 correct answer ✅ Contact for placement exam @srksvk

13 206

IBM exam successfully done by laptop access ✅✅✅ Both code fully passed with all test case passed ✅✅✅ Contact for placement exams @srksvk

13 206

IBM exam successfully done by laptop access ✅✅✅ Both code fully passed with all test case passed ✅✅✅ Contact for placement exams @srksvk

13 206

IBM exam cleard 🎉🥳🥳🥳🥳🥳🥳🎉🎉🎉🎉✅💯💯 Got main next round ✅✅🎉🎉✅ Contact for placement exam help @srksvk

13 206

IBM exam successfully done by laptop access ✅✅✅ Both code fully passed with all test case passed ✅✅✅ Contact for placement exams @srksvk

13 206

int f(int i, int j, int flag, vector& arr, int sum, vector>>& dp) { if (i >= j) return 0; if (dp[i][j][flag] != -1) return dp[i][j][flag]; int firsttwo = 0; int lasttwo = 0; int firstlast = 0; if (i + 1 < arr.size() && arr[i] + arr[i + 1] == sum) { firsttwo = 1 + f(i + 2, j, flag, arr, sum, dp); } if (arr[i] + arr[j] == sum) { firstlast = 1 + f(i + 1, j - 1, flag, arr, sum, dp); } if (j >= 0 && arr[j] + arr[j - 1] == sum) { lasttwo = 1 + f(i, j - 2, flag, arr, sum, dp); } return dp[i][j][flag] = max({firsttwo, lasttwo, firstlast}); } int solution(vector& arr) { int n = arr.size(); vector>> dp(n, vector>(n, vector(3, -1))); int sum1 = arr[0] + arr[n - 1]; int sum2 = arr[0] + arr[1]; int sum3 = arr[n - 1] + arr[n - 2]; int ans1 = f(0, n - 1, 0, arr, sum1, dp); int ans2 = f(0, n - 1, 1, arr, sum2, dp); int ans3 = f(0, n - 1, 2, arr, sum3, dp); int res = max(ans1, max(ans2, ans3)); return res; }

13 206

#include <bits/stdc++.h> using namespace std; int solution(vector<int>& A) { sort(A.begin(), A.end()); if (A.size() <= 2) { return A.size(); } int maxCount = 0; unordered_map<int, int> differences[A.size()]; for (int i = 1; i < A.size(); i++) { for (int j = 0; j < i; j++) { int currentDiff = A[i] - A[j]; int currentCnt = 1; if (differences[j].count(currentDiff) != 0) { currentCnt += differences[j][currentDiff]; differences[i][currentDiff] = currentCnt; } else { differences[i][currentDiff] = 1 + currentCnt; } maxCount = max(maxCount, differences[i][currentDiff]); } } return maxCount; } task 2

13 206

Microsoft oa for sloution Join👇👇👇 https://t.me/ibmsolution

13 206

Cognizant hiring 2023 batch Off campus Apply link 👇 https://app.joinsuperset.com/join/#/signup/student/jobprofiles/f207da4e-a7e1-48a0-b6ba-5f2fd6c719ca @codeing_area

13 206

NPCI successfully done by remote access ✅✅✅ All eleminate round cleard ✅✅ All MCQ done with 100% correct answer ✅✅✅ Slot 2

13 206

NPCI successfully done by remote access ✅✅✅ All eleminate round cleard ✅✅ All MCQ done with 100% correct answer ✅✅✅ Slot 1

13 206

Python

13 206

Python

13 206

Python

13 206

Everyoneee Start you exam at 4:30 pm @codeing_area share the group now ✅ Share ✅ share ✅ share ✅

13 206

NPCI EXAM [4pmM] SOLUTION GROUP: Share your question here for free help👇👇👇 https://t.me/ibmsolution https://t.me/ibmsolution ✅ Share post in ur college Whatsapp grps.

13 206

NPCI EXAM [4pmM] SOLUTION GROUP: https://t.me/ibmsolution https://t.me/ibmsolution ✅ Share post in ur college Whatsapp grps.

13 206

𝗡𝗖𝗣𝗜 𝗘𝗫𝗔𝗠 𝗛𝗘𝗟𝗣 𝗔𝗟𝗘𝗥𝗧 🚨 SLOT: 𝟮𝟯𝗿𝗱 𝗗𝗲𝗰. 𝟰𝗽𝗺 Contact : @srksvk 𝗥𝗲𝗺𝗼𝘁𝗲 𝗔𝗰𝗰𝗲𝘀𝘀 𝗔𝘃𝗮𝗶𝗹𝗮𝗯𝗹𝗲 Full clearence Gauruntee ✅ Scroll up and check past results Note:- its paid help