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ACCENTURE EXAM SOLUTIONS

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🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

Ko'proq ko'rsatish

Hindiston28 425 Taʼlim14 501...

📈 Telegram kanali ACCENTURE EXAM SOLUTIONS analitikasi

ACCENTURE EXAM SOLUTIONS (@coding_are) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 14 046 obunachidan iborat bo'lib, Taʼlim toifasida 14 501-o'rinni va Hindiston mintaqasida 28 425-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 14 046 obunachiga ega bo‘ldi.

11 Oktabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -105 ga, so‘nggi 24 soatda esa 0 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

Tasdiqlash holati: Tasdiqlanmagan
Jalb etish (ER): Auditoriya o‘rtacha 3.68% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.83% ini tashkil etuvchi reaksiyalarni to‘playdi.
Post qamrovi: Har bir post o‘rtacha 518 marta ko‘riladi; birinchi sutkada odatda 257 ta ko‘rish yig‘iladi.
Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 2 ta reaksiya keladi.
Tematik yo‘nalishlar: Kontent placement, gaurntee, suree, capgemini, infosy kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...”

Yuqori yangilanish chastotasi (oxirgi ma’lumot 13 Oktabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

14 046

Obunachilar

Ma'lumot yo'q24 soatlar

-387 kun

-10530 kun

518

Post ko'rishlar

~ 25724 soatlar

~ 32348 soatlar

3.68%

Muloqot nisbati

~ 5

Kuniga postlar

Ads index

beta

Postlar arxiv

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#include<bits/stdc++.h> using namespace std; const int N=500005; typedef long long ll; int T,n,k,t,h[N]; ll dp[N][2]; struct edge{ int ver,net; ll val; }f[N*2]; void add(int x,int y,int z){ f[++t].net=h[x]; h[x]=t,f[t].ver=y; f[t].val=z; } void dfs(int x,int fa){ dp[x][0]=dp[x][1]=0; priority_queue<ll> q; for(int i=h[x];i;i=f[i].net){ int y=f[i].ver; if(y==fa) continue; dfs(y,x); dp[x][0]+=dp[y][0]; q.push(dp[y][1]+f[i].val-dp[y][0]); } dp[x][1]=dp[x][0]; int p=k; while(p--&&q.size()&&q.top()>0){ if(p) dp[x][1]+=q.top(); dp[x][0]+=q.top(); q.pop(); } } int main(){ scanf("%d",&T); while(T--){ int x,y,z;t=0; scanf("%d%d",&n,&k); for(int i=1;i<n;++i){ scanf("%d%d%d",&x,&y,&z); add(x,y,z),add(y,x,z); } dfs(1,0); printf("%lld\n",dp[1][0]); for(int i=1;i<=n;++i) h[i]=0,dp[i][0]=dp[i][1]=0; } return 0; } Good edage

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14 046

Do 6.5

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#include <bits/stdc++.h> using namespace std; #define ll long long ll dp[10005][2]; const int mod = (1e9 + 7); ll solve(ll i, ll o, ll n, ll k, vector<ll> &v) { if (i > n) { return 0; } if (dp[i][o] != -1) return dp[i][o]; ll ans = 0; if (o == 0) { for (int j = i; j < min(n + 1, i + k); j++) { ans = max(ans, solve(j + 1, 1 - o, n, k, v)) % mod; } } else { ll ta = 0; ll mx = 0; for (int j = i; j < min(n + 1, i + k); j++) { if (ta + v[j] >= 0) { ta += v[j]; mx = max(mx, ta); } else { ta = 0; } ll c = solve(j + 1, 1 - o, n, k, v) % mod; ans = max(ans, ((j - i + 1) * mx) % mod + c % mod); } } return dp[i][o] = ans; } int main() { ll n, k; cin >> n >> k; vector<ll> v; ll neg = 0; for (int i = 0; i < n; i++) { ll x; cin >> x; v.push_back(x); if (x <= 0) neg++; } if (neg == v.size()) { cout << 0 << endl; return 1; } memset(dp, -1, sizeof(dp)); cout << max(solve(0, 0, v.size() - 1, k, v), solve(0, 1, v.size() - 1, k, v)) << endl; } Array segment

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Now check every one

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