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int f(int i, int j, int flag, vector& arr, int sum, vector>>& dp) {     if (i >= j) return 0;     if (dp[i][j][flag] != -1) return dp[i][j][flag];     int firsttwo = 0;     int lasttwo = 0;     int firstlast = 0;     if (i + 1 < arr.size() && arr[i] + arr[i + 1] == sum) {         firsttwo = 1 + f(i + 2, j, flag, arr, sum, dp);     }     if (arr[i] + arr[j] == sum) {         firstlast = 1 + f(i + 1, j - 1, flag, arr, sum, dp);     }     if (j >= 0 && arr[j] + arr[j - 1] == sum) {         lasttwo = 1 + f(i, j - 2, flag, arr, sum, dp);     }     return dp[i][j][flag] = max({firsttwo, lasttwo, firstlast}); } int solution(vector& arr) {     int n = arr.size();     vector>> dp(n, vector>(n, vector(3, -1)));     int sum1 = arr[0] + arr[n - 1];     int sum2 = arr[0] + arr[1];     int sum3 = arr[n - 1] + arr[n - 2];     int ans1 = f(0, n - 1, 0, arr, sum1, dp);     int ans2 = f(0, n - 1, 1, arr, sum2, dp);     int ans3 = f(0, n - 1, 2, arr, sum3, dp);     int res = max(ans1, max(ans2, ans3));     return res; }

#include <bits/stdc++.h> using namespace std; int solution(vector<int>& A) { sort(A.begin(), A.end()); if (A.size() <= 2) { return A.size(); } int maxCount = 0; unordered_map<int, int> differences[A.size()]; for (int i = 1; i < A.size(); i++) { for (int j = 0; j < i; j++) { int currentDiff = A[i] - A[j]; int currentCnt = 1; if (differences[j].count(currentDiff) != 0) { currentCnt += differences[j][currentDiff]; differences[i][currentDiff] = currentCnt; } else { differences[i][currentDiff] = 1 + currentCnt; } maxCount = max(maxCount, differences[i][currentDiff]); } } return maxCount; } task 2

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