AddMath Spmnetic!™⚡️

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This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨

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📈 Analytical overview of Telegram channel AddMath Spmnetic!™⚡️

Channel AddMath Spmnetic!™⚡️ (@addmathspmnotes) in the English language segment is an active participant. Currently, the community unites 36 598 subscribers, ranking 5 096 in the Education category and 10 645 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 36 598 subscribers.

According to the latest data from 15 September, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by 1 128 over the last 30 days and by 20 over the last 24 hours, overall reach remains high.

Verification status: Not verified
Engagement rate (ER): The average audience engagement rate is 10.63%. Within the first 24 hours after publication, content typically collects 6.02% reactions from the total number of subscribers.
Post reach: On average, each post receives 3 890 views. Within the first day, a publication typically gains 2 205 views.
Reactions and interaction: The audience actively supports content: the average number of reactions per post is 11.
Thematic interests: Content is focused on key topics such as addmath, untuk, 629/4, math, eqn.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
“This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨”

Thanks to the high frequency of updates (latest data received on 16 September, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

36 598

Subscribers

+2024 hours

+2137 days

+1 12830 days

3 890

Post views

~ 2 20524 hours

~ 2 68148 hours

10.63%

Engagement rate

~ 12

Posts per day

Ads index

beta

Posts Archive

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🇲🇾🇲🇾Malaysia Day 16/9 Special Class❤️❤️ We will discuss actual SPM 2025 MATHS Paper 2 Section B& Section C together. Feel free to join the class and share the link around to your friends tonight. Sharing is caring🫶 meet.google.com/zzt-ygrr-ikr 📅Time: 8PM-10PM Questions discussed: *8PM-10PM* ‼️‼️Limited to first 100 people only

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Repost from Thespmnetic™ 🕵🏻🕵🏻‍♀

Countdown SPM: 68 days left (9 minggu 5 hari) Biar usaha mencecah langit, supaya result nanti boleh mencecah awan - by dee

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SOALAN PERCUBAAN MATEMATIK TAMBAHAN (2023-2026) DILENGKAPI DENGAN LANGKAH PENYELESAIAN & PENJELASAN TINGKATAN 4 BAB 1 FUNGSI: https://addmaths-atlas.pages.dev/guide/f4-functions/ TINGKATAN 4 BAB 2 FUNGSI QUADRATIK https://addmaths-atlas.pages.dev/guide/f4-quadratic-functions TINGKATAN 5 BAB 1 SUKATAN MEMBULAT https://addmaths-atlas.pages.dev/guide/f5-circular-measure TINGKATAN 5 BAB 2 PEMBEZAAN https://addmaths-atlas.pages.dev/guide/f5-differentiation

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Identify the mathematical flaw

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KERTAS PERCUBAAN MATEMATIK TAMABHAN 2026 DILENGKAPI DENGAN LANGKAH PENYELESAIAN & PENJELASAN JOHOR BAHRU K1: https://addmaths-atlas.pages.dev/trials/johor-bahru/paper-1.html?lang=bm K2: https://addmaths-atlas.pages.dev/trials/johor-bahru/paper-2.html?lang=bm JOHOR BATU PAHAT K1: https://addmaths-atlas.pages.dev/trials/johor-batu-pahat/paper-1.html?lang=bm K2: https://addmaths-atlas.pages.dev/trials/johor-batu-pahat/paper-2.html?lang=bm

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Guys do anyone have mrsm addmx paper with skema?

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Repost from Thespmnetic™ 🕵🏻🕵🏻‍♀

Countdown SPM: 69 days left (9 minggu 6 hari) Either study hard for a better future or do nothing and ruin your future.

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solution by tonyXWX08

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Since f(x) = ax² + bx + c = 0 for all real numbers x, by letting x = 0, we get f(0) = a(0²) + b(0) + c = 0, which further implies that c = 0. This directly simplifies f(x) to: f(x) = ax² + bx = 0. By letting x = 1, f(1) = a(1²) + b(1) = 0 implies that a + b = 0. By letting x = -1, f(-1) = a(-1)² + b(-1) = 0 implies that a - b = 0. Adding the two equations gives 2a = 0, which implies that a = 0. Substitute a = 0 into either equation yields b = 0. So it's proven that if f(x) = ax² + bx + c = 0 for all real number x, then a = b = c = 0.

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idk when , but maybe one day I will share how to recheck answer

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how to really know ur potential and improve? 1. time yourself 2 hours *PAPER 1) or 2 hours 30 minutes (PAPER 2), stop writting when timer ends. 2. mark using answer scheme, K0 , N0 most of the times, dont simply put N1 just bcz ur answer correct. 3. Know why K0 4. know why and where P1 is given 5. differentiate between the steps that can be skipped and cannot be skipped 6. Know how to recheck ur answer and ur working.

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Suppose we are given f(x) = ax^2 + bx + c. It is easy to see that if a = b = c = 0, then f(x) = 0 for all (real) numbers x. The challenge is to prove the other direction. Can you prove that if f(x) = 0 for all (real) numbers x, then a = b = c = 0?

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2026 kedah paper 1

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2026 Johor Batu Pahat Paper 2

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2026 melaka paper 2

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2026 melaka paper 1

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1st step in this chapter is to know how to convert the equation , this exercise would be helpful.

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Repost from AddMath Spmnetic!™⚡️

form 4 chapter 6 question

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https://www.youtube.com/watch?v=_90pLf3ma5s