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Maths by Shantanu Sir channel

Maths by Shantanu Sir channel

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📈 Analytical overview of Telegram channel Maths by Shantanu Sir channel

Channel Maths by Shantanu Sir channel (@mathsbyshantanusir) in the English language segment is an active participant. Currently, the community unites 46 230 subscribers, ranking 3 814 in the Education category and 8 000 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 46 230 subscribers.

According to the latest data from 29 August, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by 5 332 over the last 30 days and by 285 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 15.43%. Within the first 24 hours after publication, content typically collects 7.97% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 7 124 views. Within the first day, a publication typically gains 3 681 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 0.
  • Thematic interests: Content is focused on key topics such as shantanu, sir, jao, y179, jud.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
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Thanks to the high frequency of updates (latest data received on 30 August, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

46 230
Subscribers
+28524 hours
+1 5967 days
+5 33230 days
Posts Archive
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Quants by Shantanu Sir Class link : 👇👇 https://www.youtube.com/live/I9uWvEDFl5g?si=3UBgZFYlTZ69qQSN

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Quants By Shantanu Sir Class Link : 👇👇 https://www.youtube.com/live/7dHy7kqvY60?si=UIOVu_7iqnn8VJmH

Video message00:38

🔥🔥Be ready for this Class 📈📈 Ratio https://www.youtube.com/live/7dHy7kqvY60?si=G67YpcNBgxtcBlJ_

DDPP_NO_102,_DAKASH_2026,_HCF_LCM,_NUMBER_SYSTEM_&_ALGEBRA_3,_25.pdf5.53 KB

RANKERS 2026 -SBI PO -2026, CLASS-2, LCM-HCF, 25 AUG.pptx5.12 MB

R = 2 => x = 3/13 [Not possible] R = 3 => x = 22/13 [Not possible] R = 4 => x = 59/13 [Not possible] R = 5 => x = 120/13 [Not possible] R = 6 => x = 211/13 [Not possible] R = 7 => x = 26 [Possible] R = 8 => x = 39 [Possible] R = 9 => x = 724/13 [Not possible] R = 10 => x = 995/13 [Not possible] R = 11 => x = 102 [Possible] R = 12 => x = 1723/13 [Not possible] Possible remainder when 'N' is divided by 13 is 7, 8 and 11. When: Remainder when 'N' is divided by 13 is 7. Remainder when 'N4' is divided by 13 = Remainder when product of 5 and 7 is divided by 13 = 9 When: Remainder when 'N' is divided by 13 is 8. Remainder when 'N4' is divided by 13 = Remainder when product of 5 and 8 is divided by 13 = 1 When: Remainder when 'N' is divided by 13 is 11. Remainder when 'N4' is divided by 13 = Remainder when product of 5 and 11 is divided by 13 = 3 Hence, possible remainder = 9 and 1. Statement III alone is not sufficient.

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