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Maths by Shantanu Sir channel

Maths by Shantanu Sir channel

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📈 Telegram 频道 Maths by Shantanu Sir channel 的分析概览

频道 Maths by Shantanu Sir channel (@mathsbyshantanusir) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 46 230 名订阅者,在 教育 类别中位列第 3 814,并在 印度 地区排名第 8 000

📊 受众指标与增长动态

невідомо 创建以来,项目保持高速增长,吸引了 46 230 名订阅者。

根据 29 八月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 5 332,过去 24 小时变化为 285,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 15.43%。内容发布后 24 小时内通常能获得 7.97% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 7 124 次浏览,首日通常累积 3 681 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 0
  • 主题关注点: 内容集中在 shantanu, sir, jao, y179, jud 等核心主题上。

📝 描述与内容策略

作者将该频道定位为表达主观观点的平台:
Welcome To Daksh Quants Family 💗

凭借高频更新(最新数据采集于 30 八月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 教育 类别中的关键影响点。

46 230
订阅者
+28524 小时
+1 5967
+5 33230
帖子存档
Bachcho Mai ek personal experience share karna chah rha hu … Baat bahot gahri (deep) hai … sab kuch likh Nahi sakta … Since I am a music & literature lover … Mai pahle ekdm fall in love type ka ho gya 💗 … fir dhyan se dekha to pta chla ki ye to mere Rishank ki mummy h 😂😂 https://www.instagram.com/reel/DclwUnjA5xJ/?igsi=N2hnd3Rkc3pjdDl4

Quants by Shantanu Sir Class link : 👇👇 https://www.youtube.com/live/I9uWvEDFl5g?si=3UBgZFYlTZ69qQSN

🟠🟠SBI PO Prelims 2026 Result Out

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Quants By Shantanu Sir Class Link : 👇👇 https://www.youtube.com/live/7dHy7kqvY60?si=UIOVu_7iqnn8VJmH

视频消息00:38

🔥🔥Be ready for this Class 📈📈 Ratio https://www.youtube.com/live/7dHy7kqvY60?si=G67YpcNBgxtcBlJ_

DDPP_NO_102,_DAKASH_2026,_HCF_LCM,_NUMBER_SYSTEM_&_ALGEBRA_3,_25.pdf5.53 KB

RANKERS 2026 -SBI PO -2026, CLASS-2, LCM-HCF, 25 AUG.pptx5.12 MB

R = 2 => x = 3/13 [Not possible] R = 3 => x = 22/13 [Not possible] R = 4 => x = 59/13 [Not possible] R = 5 => x = 120/13 [Not possible] R = 6 => x = 211/13 [Not possible] R = 7 => x = 26 [Possible] R = 8 => x = 39 [Possible] R = 9 => x = 724/13 [Not possible] R = 10 => x = 995/13 [Not possible] R = 11 => x = 102 [Possible] R = 12 => x = 1723/13 [Not possible] Possible remainder when 'N' is divided by 13 is 7, 8 and 11. When: Remainder when 'N' is divided by 13 is 7. Remainder when 'N4' is divided by 13 = Remainder when product of 5 and 7 is divided by 13 = 9 When: Remainder when 'N' is divided by 13 is 8. Remainder when 'N4' is divided by 13 = Remainder when product of 5 and 8 is divided by 13 = 1 When: Remainder when 'N' is divided by 13 is 11. Remainder when 'N4' is divided by 13 = Remainder when product of 5 and 11 is divided by 13 = 3 Hence, possible remainder = 9 and 1. Statement III alone is not sufficient.

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Q5.
Q5.