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Maths by Shantanu Sir channel

Maths by Shantanu Sir channel

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Welcome To Daksh Quants Family 💗

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📈 Telegram kanali Maths by Shantanu Sir channel analitikasi

Maths by Shantanu Sir channel (@mathsbyshantanusir) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 46 230 obunachidan iborat bo'lib, Taʼlim toifasida 3 814-o'rinni va Hindiston mintaqasida 8 000-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 46 230 obunachiga ega bo‘ldi.

29 Avgust, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni 5 332 ga, so‘nggi 24 soatda esa 285 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 15.43% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 7.97% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 7 124 marta ko‘riladi; birinchi sutkada odatda 3 681 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 0 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent shantanu, sir, jao, y179, jud kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
Welcome To Daksh Quants Family 💗

Yuqori yangilanish chastotasi (oxirgi ma’lumot 30 Avgust, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

46 230
Obunachilar
+28524 soatlar
+1 5967 kunlar
+5 33230 kunlar
Postlar arxiv
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Quants by Shantanu Sir Class link : 👇👇 https://www.youtube.com/live/I9uWvEDFl5g?si=3UBgZFYlTZ69qQSN

🟠🟠SBI PO Prelims 2026 Result Out

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Quants By Shantanu Sir Class Link : 👇👇 https://www.youtube.com/live/7dHy7kqvY60?si=UIOVu_7iqnn8VJmH

Video xabar00:38

🔥🔥Be ready for this Class 📈📈 Ratio https://www.youtube.com/live/7dHy7kqvY60?si=G67YpcNBgxtcBlJ_

DDPP_NO_102,_DAKASH_2026,_HCF_LCM,_NUMBER_SYSTEM_&_ALGEBRA_3,_25.pdf5.53 KB

RANKERS 2026 -SBI PO -2026, CLASS-2, LCM-HCF, 25 AUG.pptx5.12 MB

R = 2 => x = 3/13 [Not possible] R = 3 => x = 22/13 [Not possible] R = 4 => x = 59/13 [Not possible] R = 5 => x = 120/13 [Not possible] R = 6 => x = 211/13 [Not possible] R = 7 => x = 26 [Possible] R = 8 => x = 39 [Possible] R = 9 => x = 724/13 [Not possible] R = 10 => x = 995/13 [Not possible] R = 11 => x = 102 [Possible] R = 12 => x = 1723/13 [Not possible] Possible remainder when 'N' is divided by 13 is 7, 8 and 11. When: Remainder when 'N' is divided by 13 is 7. Remainder when 'N4' is divided by 13 = Remainder when product of 5 and 7 is divided by 13 = 9 When: Remainder when 'N' is divided by 13 is 8. Remainder when 'N4' is divided by 13 = Remainder when product of 5 and 8 is divided by 13 = 1 When: Remainder when 'N' is divided by 13 is 11. Remainder when 'N4' is divided by 13 = Remainder when product of 5 and 11 is divided by 13 = 3 Hence, possible remainder = 9 and 1. Statement III alone is not sufficient.

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Q5.
Q5.