SQL задачи
SQL задачи для подготовки к собеседованию. SQL тесты для проверки знаний. № 7065181110 SQL запросы к конкретной Базе данных с решением и разбором По вопросам рекламы: @anothertechrock
Show more📈 Analytical overview of Telegram channel SQL задачи
Channel SQL задачи (@sqlquestions) in the Russian language segment is an active participant. Currently, the community unites 10 058 subscribers, ranking 12 186 in the Technologies & Applications category and 64 957 in the Russia region.
📊 Audience metrics and dynamics
Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 10 058 subscribers.
According to the latest data from 20 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -30 over the last 30 days and by 0 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 13.19%. Within the first 24 hours after publication, content typically collects 5.73% reactions from the total number of subscribers.
- Post reach: On average, each post receives 1 327 views. Within the first day, a publication typically gains 576 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 5.
- Thematic interests: Content is focused on key topics such as sql, sqlquestions, шапка, order_table, архитектура.
📝 Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
“SQL задачи для подготовки к собеседованию.
SQL тесты для проверки знаний.
№ 7065181110
SQL запросы к конкретной Базе данных с решением и разбором
По вопросам рекламы: @anothertechrock”
Thanks to the high frequency of updates (latest data received on 21 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.
SELECT p.name AS product_name,
pi.count,
pi.price
FROM purchase_item pi
JOIN product p
ON p.product_id = pi.product_id
WHERE pi.price = (SELECT max(pim.price)
FROM purchase_item pim)
#задачаSELECT concat(
e.last_name, ' ',
e.first_name, ' ',
e.middle_name, ';'
) AS full_name
FROM employee e
ORDER BY full_name
#задачаSELECT c.name,
(SELECT p.name
FROM product p
WHERE p.category_id = c.category_id
ORDER BY p.name
LIMIT 1
) AS product_example
FROM category c
ORDER BY c.name
#задача
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