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allcoding1_official

allcoding1_official

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📈 Telegram 频道 allcoding1_official 的分析概览

频道 allcoding1_official (@allcoding1_official) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 85 523 名订阅者,在 技术与应用 类别中位列第 1 507,并在 印度 地区排名第 3 480

📊 受众指标与增长动态

невідомо 创建以来,项目保持高速增长,吸引了 85 523 名订阅者。

根据 24 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -1 369,过去 24 小时变化为 -35,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 2.60%。内容发布后 24 小时内通常能获得 0.55% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 2 222 次浏览,首日通常累积 474 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 3
  • 主题关注点: 内容集中在 dsa, stack, namaste, javascript, dev 等核心主题上。

📝 描述与内容策略

尚未提供频道描述。

凭借高频更新(最新数据采集于 25 六月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。

85 523
订阅者
-3524 小时
-2687
-1 36930
帖子存档
long findSum(long cum[], int l, int r, int n) {     if (l == 0)     {         return cum[r];     }     return cum[r] - cum[l - 1]; } long getThreeNonOverLappingIntervals(vector starting, vector ending) {     vector> vp;     int n = starting.size();     for (int i = 0; i < n; i++)     {         vp.push_back({starting[i], ending[i]});     }     sort(vp.begin(), vp.end());     long dp[n];     dp[n - 1] = 0;     for (int i = n - 2; i >= 0; i--)     {         int l = i + 1;         int r = n - 1;         int pos = n;         while (l <= r)         {             int mid = l + (r - l) / 2;             if (vp[mid].first > vp[i].second)             {                 pos = min(pos, mid);                 r = mid - 1;             }             else             {                 l = mid + 1;             }         }         dp[i] = n - pos;     }     long dp1[n];     dp1[n - 1] = 0;     dp1[n - 2] = 0;     long ans = 0;     long cum[n];     cum[0] = dp[0];     for (int i = 1; i < n; i++)     {         cum[i] = cum[i - 1] + dp[i];     }     for (int i = n - 3; i >= 0; i--)     {         int l = i + 1;         int r = n - 1;         int pos = n;         while (l <= r)         {             int mid = l + (r - l) / 2;             if (vp[mid].first > vp[i].second)             {                 pos = min(pos, mid);                 r = mid - 1;             }             else             {                 l = mid + 1;             }         }         if(pos==n)         {             continue;         }         ans+=findSum(cum,pos,n-1,n);     }     return ans; } Non overlapping intervals

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int maximizeRatings(vector rating) {     int n=rating.size();     int ans=0;     for(int i=0;i=0;i--)     {         dp[i]=min(rating[i]+dp[i+2],dp[i+1]);     }     return ans-dp[0]; } Movie ratings

int countBracketSequence(string s) {     int sum = 0;     int n = s.size();     for (int i = 0; i < n; i++)     {         if (s[i] == '(')         {             sum++;         }         else         {             sum--;         }     }     int ans;     if(sum!=1 && sum!=-1)     {         return 0;     }     if (sum < 0)     {         sum = 0;         for (int i = 0; i < n; i++)         {             if (s[i] == '(')             {                 sum++;             }             else             {                 sum--;             }             if (sum < 0)             {                 ans = i + 1;                 break;             }         }     }     else     {         sum = 0;         int cnt = 0;         for (int i = n - 1; i >= 0; i--)         {             if (s[i] == ')')             {                 sum++;             }             else             {                 sum--;             }             if (sum < 0)             {                 ans = cnt + 1;                 break;             }             cnt++;         }     }     return ans; } Bracket Sequence

#include struct Triangle { &nbsp;&nbsp;&nbsp; int side1; &nbsp;&nbsp;&nbsp; int side2; &nbsp;&nbsp;&nbsp; int side3; }; int I
#include <stdio.h> struct Triangle {     int side1;     int side2;     int side3; }; int IdentifyTriangle(struct Triangle list[], int n) {     if (list == NULL) {         return -1;     }     int scaleneCount = 0;     int isoscelesCount = 0;     int notTriangleCount = 0;     for (int i = 0; i < n; i++) {         int s1 = list[i].side1;         int s2 = list[i].side2;         int s3 = list[i].side3;         if ((s1 + s2 > s3) && (s1 + s3 > s2) && (s2 + s3 > s1)) {             if (s1 != s2 && s2 != s3 && s1 != s3) {                 scaleneCount++;             }             else if (s1 == s2 s2 == s3 s1 == s3) {                 isoscelesCount++;             }         } else {             notTriangleCount++;         }     }     return (3 * scaleneCount) - (isoscelesCount + notTriangleCount); } Identify triangles

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