allcoding1_official
前往频道在 Telegram
📈 Telegram 频道 allcoding1_official 的分析概览
频道 allcoding1_official (@allcoding1_official) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 85 523 名订阅者,在 技术与应用 类别中位列第 1 507,并在 印度 地区排名第 3 480 位。
📊 受众指标与增长动态
自 невідомо 创建以来,项目保持高速增长,吸引了 85 523 名订阅者。
根据 24 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -1 369,过去 24 小时变化为 -35,整体触达仍然可观。
- 认证状态: 未认证
- 互动率 (ER): 平均受众互动率为 2.60%。内容发布后 24 小时内通常能获得 0.55% 的反应,占订阅者总量。
- 帖子覆盖: 每篇帖子平均可获得 2 222 次浏览,首日通常累积 474 次浏览。
- 互动与反馈: 受众积极参与,单帖平均反应数为 3。
- 主题关注点: 内容集中在 dsa, stack, namaste, javascript, dev 等核心主题上。
📝 描述与内容策略
尚未提供频道描述。
凭借高频更新(最新数据采集于 25 六月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。
85 523
订阅者
-3524 小时
-2687 天
-1 36930 天
帖子存档
85 523
Deloitte exam verbal
1) CBDA
2) false
3) At( fill in the blanks 4) In a corner
5) RPQS
6) down
7)He trades both precious and non-precious elements
8) The men yelled in her face
85 523
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85 523
Repost from allcoding1_official
🎯Gap Inc. is Hiring
Role: Software Engineer
Expected CTC: 10-15 LPA
Location: Hyderabad
🔗Apply here: https://gapinc.com/en-in/jobs/w50/10/software-engineer?rx_campaign=indeed0&rx_ch=jobp4p&rx_group=116953&rx_job=R155010&rx_medium=cpc&rx_r=none&rx_source=Indeed&rx_ts=20240212T040042Z&rx_vp=cpc&src=JB-12080&rx_p=3EEOWPZGT4&rx_viewer=26bfde3e399611ee9af1415c5aa7bfbe5d6d53728456427c859a335976e41692
85 523
Repost from allcoding1_official
Seclore Hiring Trainee Product Engineer
Batch : 2023/2024
https://forms.office.com/pages/responsepage.aspx?id=p-D8QJJvrU-J5dFq-aRayJUCwLfnvYFErLS_NRtRc3pUMUFPMzY5RFNTRUhGSzFEWlRHODQxRURGRy4u
85 523
Repost from allcoding1_official
🎯Tech Mahindra Off Campus drive
Job Role Associate Software Engineer
Qualification B.E/B.Tech/MCA/M.Sc
Experience Freshers
Batch 2022/2023
Salary Rs.3.25 LPA & 5.5LPA (for super coders)
Job Location Across India
Venue Location Virtual(Online)
Last Date 4 February 2024
Apply now:- https://www.allcoding1.com/2024/02/tech-mahindra-off-campus-drive-2024.html?m=1
Telegram:- @allcoding1_official
85 523
Repost from allcoding1_official
🎯 Microsoft Bulk Hiring 2024 | For Software Engineer
Degree:- BE, B Tech, BA, B COM, BBA, BSC, BCA, ME, M Tech, MCA, MA, M COM, MSC, Any Graduate
Batch:- 2018, 2019, 2020, 2021, 2022, 2023 ,2024 & 2025
Apply now:- https://www.allcoding1.com/2024/02/microsoft-bulk-hiring-2024-for-software.html
Telegram:- @allcoding1_official
85 523
Repost from allcoding1_official
🎯SAS Off Campus Drive 2024 – Associate Software Engineer – Freshers | Rs 4-8 LPA
Job Role : Associate Software Developer
Qualification : B.E/B/Tech/M.E. / M.Tech
Experience : Freshers
Job Location : Pune
Package : Rs 4-8 LPA
Apply Now:- https://www.allcoding1.com/2024/02/sas-off-campus-drive-2024-associate_9.html?m=1
Telegram:- @allcoding1_official
85 523
Repost from allcoding1_official
🎯Atos Is Hiring
Degree:- Any Graduate
Batch:- 2019, 2020, 2021, 2022, 2023 & 2024
Apply Now:- https://www.allcoding1.com/2024/02/atos-off-campus-drive-for-any-graduate.html
Telegram:- @allcoding1_official
85 523
500 TB Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
🔹Artificial Intelligence
🔹AWS Certified
🔹Cloud
🔹BIG DATA
🔹Data Analytics
🔹BI
🔹Google Cloud Platform
🔹IT Training
🔹MBA
🔹Machine Learning
🔹Deep Learning
🔹Ethical Hacking
🔹SPSS
🔹Statistics
🔹Data Base
🔹Learning language resources ( English🏴 , French🇨🇵 , German🇩🇪 )
₹50
Contact:- @meterials_available
85 523
if not intervals:
return 0
intervals.sort(key=lambda x: x[0]) # Sort intervals based on start points
merged_intervals = [intervals[0]] # Initialize merged intervals with the first interval
for interval in intervals[1:]:
prev_interval = merged_intervals[-1]
if interval[0] <= prev_interval[1]: # If overlapping with previous interval
prev_interval[1] = max(prev_interval[1], interval[1]) # Merge intervals
else:
merged_intervals.append(interval) # Add non-overlapping interval
total_length = sum(end - start for start, end in merged_intervals)
return total_length
# Example usage:
intervals = [(1, 3), (2, 6), (8, 10), (15, 18)]
total_length_covered = merge_intervals(intervals)
print("Total length covered after merging overlapping intervals:", total_length_covered)85 523
if not intervals:
return 0
intervals.sort(key=lambda x: x[0]) # Sort intervals based on start points
merged_intervals = [intervals[0]] # Initialize merged intervals with the first interval
for interval in intervals[1:]:
prev_interval = merged_intervals[-1]
if interval[0] <= prev_interval[1]: # If overlapping with previous interval
prev_interval[1] = max(prev_interval[1], interval[1]) # Merge intervals
else:
merged_intervals.append(interval) # Add non-overlapping interval
total_length = sum(end - start for start, end in merged_intervals)
return total_length
# Example usage:
intervals = [(1, 3), (2, 6), (8, 10), (15, 18)]
total_length_covered = merge_intervals(intervals)
print("Total length covered after merging overlapping intervals:", total_length_covered)
85 523
int main() {
ll N;
cin >> N;
vector<ll> u(N);
for(ll i = 0; i < N; ++i) {
cin >> u[i];
}
ll M, X;
cin >> M >> X;
vector<vector<ll>> a(N);
for(ll i = 0; i < M; ++i) {
ll x, y;
cin >> x >> y;
a[x].push_back(y);
a[y].push_back(x);
}
vector<bool> v(N, false);
queue<ll> q;
q.push(0);
v[0] = true;
ll m = 0;
while(!q.empty()) {
ll s = q.size();
ll us = 0;
for(ll i = 0; i < s; ++i) {
ll n = q.front();
q.pop();
us += u[n];
for(ll nb : a[n]) {
if(!v[nb]) {
q.push(nb);
v[nb] = true;
}
}
}
m = max(m, us);
}
cout << m << endl;
return 0;
}
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@allcoding1_official
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