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allcoding1_official (@allcoding1_official) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 85 467 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 1 502-o'rinni va Hindiston mintaqasida 3 471-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 85 467 obunachiga ega bo‘ldi.

25 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -1 422 ga, so‘nggi 24 soatda esa -71 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 2.42% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 0.88% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 2 071 marta ko‘riladi; birinchi sutkada odatda 749 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 4 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, dev kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 26 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

85 467
Obunachilar
-7124 soatlar
-3077 kunlar
-1 42230 kunlar
Postlar arxiv
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long findSum(long cum[], int l, int r, int n) {     if (l == 0)     {         return cum[r];     }     return cum[r] - cum[l - 1]; } long getThreeNonOverLappingIntervals(vector starting, vector ending) {     vector> vp;     int n = starting.size();     for (int i = 0; i < n; i++)     {         vp.push_back({starting[i], ending[i]});     }     sort(vp.begin(), vp.end());     long dp[n];     dp[n - 1] = 0;     for (int i = n - 2; i >= 0; i--)     {         int l = i + 1;         int r = n - 1;         int pos = n;         while (l <= r)         {             int mid = l + (r - l) / 2;             if (vp[mid].first > vp[i].second)             {                 pos = min(pos, mid);                 r = mid - 1;             }             else             {                 l = mid + 1;             }         }         dp[i] = n - pos;     }     long dp1[n];     dp1[n - 1] = 0;     dp1[n - 2] = 0;     long ans = 0;     long cum[n];     cum[0] = dp[0];     for (int i = 1; i < n; i++)     {         cum[i] = cum[i - 1] + dp[i];     }     for (int i = n - 3; i >= 0; i--)     {         int l = i + 1;         int r = n - 1;         int pos = n;         while (l <= r)         {             int mid = l + (r - l) / 2;             if (vp[mid].first > vp[i].second)             {                 pos = min(pos, mid);                 r = mid - 1;             }             else             {                 l = mid + 1;             }         }         if(pos==n)         {             continue;         }         ans+=findSum(cum,pos,n-1,n);     }     return ans; } Non overlapping intervals

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int maximizeRatings(vector rating) {     int n=rating.size();     int ans=0;     for(int i=0;i=0;i--)     {         dp[i]=min(rating[i]+dp[i+2],dp[i+1]);     }     return ans-dp[0]; } Movie ratings

int countBracketSequence(string s) {     int sum = 0;     int n = s.size();     for (int i = 0; i < n; i++)     {         if (s[i] == '(')         {             sum++;         }         else         {             sum--;         }     }     int ans;     if(sum!=1 && sum!=-1)     {         return 0;     }     if (sum < 0)     {         sum = 0;         for (int i = 0; i < n; i++)         {             if (s[i] == '(')             {                 sum++;             }             else             {                 sum--;             }             if (sum < 0)             {                 ans = i + 1;                 break;             }         }     }     else     {         sum = 0;         int cnt = 0;         for (int i = n - 1; i >= 0; i--)         {             if (s[i] == ')')             {                 sum++;             }             else             {                 sum--;             }             if (sum < 0)             {                 ans = cnt + 1;                 break;             }             cnt++;         }     }     return ans; } Bracket Sequence

#include struct Triangle { &nbsp;&nbsp;&nbsp; int side1; &nbsp;&nbsp;&nbsp; int side2; &nbsp;&nbsp;&nbsp; int side3; }; int I
#include <stdio.h> struct Triangle {     int side1;     int side2;     int side3; }; int IdentifyTriangle(struct Triangle list[], int n) {     if (list == NULL) {         return -1;     }     int scaleneCount = 0;     int isoscelesCount = 0;     int notTriangleCount = 0;     for (int i = 0; i < n; i++) {         int s1 = list[i].side1;         int s2 = list[i].side2;         int s3 = list[i].side3;         if ((s1 + s2 > s3) && (s1 + s3 > s2) && (s2 + s3 > s1)) {             if (s1 != s2 && s2 != s3 && s1 != s3) {                 scaleneCount++;             }             else if (s1 == s2 s2 == s3 s1 == s3) {                 isoscelesCount++;             }         } else {             notTriangleCount++;         }     }     return (3 * scaleneCount) - (isoscelesCount + notTriangleCount); } Identify triangles

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