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MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

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📈 نظرة تحليلية على قناة تيليجرام MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

تُعد قناة MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer (@coding_are) في القطاع اللغوي الإنكليزية لاعباً نشطاً. يضم المجتمع حالياً 13 236 مشتركاً، محتلاً المرتبة 15 345 في فئة التعليم والمرتبة 32 011 في منطقة الهند.

📊 مؤشرات الجمهور والحراك

منذ تأسيسه في невідомо، حقق المشروع نمواً سريعاً وجمع 13 236 مشتركاً.

بحسب آخر البيانات بتاريخ 19 يونيو, 2026، تحافظ القناة على نشاط مستقر. خلال آخر 30 يوماً تغيّر عدد الأعضاء بمقدار -137، وفي آخر 24 ساعة بمقدار -4، مع بقاء الوصول العام مرتفعاً.

  • حالة التحقق: غير موثّقة
  • معدل التفاعل (ER): يبلغ متوسط تفاعل الجمهور 2.81‎%. وخلال أول 24 ساعة من النشر يحصد المحتوى عادةً 1.07‎% من ردود الفعل نسبةً إلى إجمالي المشتركين.
  • وصول المنشورات: يحصل كل منشور على متوسط 372 مشاهدة. وخلال اليوم الأول يجمع عادةً 142 مشاهدة.
  • التفاعلات والاستجابة: يتفاعل الجمهور بانتظام؛ متوسط التفاعلات لكل منشور يبلغ 2.
  • الاهتمامات الموضوعية: يركز المحتوى على مواضيع رئيسية مثل placement, gaurntee, suree, capgemini, infosy.

📝 الوصف وسياسة المحتوى

يصف المؤلف القناة بأنها مساحة للتعبير عن الآراء الذاتية:
🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...

بفضل وتيرة التحديث المرتفعة (أحدث البيانات بتاريخ 20 يونيو, 2026) تحافظ القناة على حداثتها ومستوى وصول مرتفع. وتُظهر التحليلات تفاعلاً نشطاً من الجمهور، ما يجعلها نقطة تأثير مهمة ضمن فئة التعليم.

13 236
المشتركون
-424 ساعات
-407 أيام
-13730 أيام
أرشيف المشاركات
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import heapq from datetime import datetime class Flight:     def init(self, source, destination, departure, arrival, price):         self.source = source         self.destination = destination         self.departure = parse_time(departure)         self.arrival = parse_time(arrival)         self.price = price def parse_time(time_str):     hour = int(time_str[:2])     minute = int(time_str[3:5])     meridian = time_str[5:].strip()         if meridian == "Am" and hour == 12:         hour = 0     elif meridian == "Pm" and hour != 12:         hour += 12         return hour * 60 + minute def find_cheapest_flight():     num_flights = int(input())     flights = []     flight_map = {}     for _ in range(num_flights):         source, dest, departure, arrival, price = input().split()         price = int(price)         flight = Flight(source, dest, departure, arrival, price)         flights.append(flight)         if source not in flight_map:             flight_map[source] = []         flight_map[source].append(flight)         start, end = input().split()     earliest_departure, latest_arrival = input().split()     earliest_departure = parse_time(earliest_departure)     latest_arrival = parse_time(latest_arrival)     queue = []     for flight in flight_map.get(start, []):         if flight.departure >= earliest_departure and flight.arrival <= latest_arrival:             heapq.heappush(queue, (flight.price, flight.arrival, flight.destination))         min_cost = {}     arrival_time = {}     while queue:         cost, current_arrival, city = heapq.heappop(queue)                 if city in min_cost and (cost > min_cost[city] or (cost == min_cost[city] and current_arrival >= arrival_time[city])):             continue                 min_cost[city] = cost         arrival_time[city] = current_arrival         if city == end:             print(cost)             return         for flight in flight_map.get(city, []):             if flight.departure >= current_arrival and flight.departure >= earliest_departure and flight.arrival <= latest_arrival:                 heapq.heappush(queue, (cost + flight.price, flight.arrival, flight.destination))         print("Impossible") if name== "main":     find_cheapest_flight() Flight Optimisation Code

if (isValidRotation(grid, M, N, rotationX1, rotationY1, rotationX2, rotationY2)) { // Determine new sofa position after rotation int newX1, newY1, newX2, newY2; if (move[0] == 0) { // Vertical to horizontal newX1 = current.x1; newY1 = current.y1; newX2 = newX1 + 1; newY2 = newY1; } else { // Horizontal to vertical newX1 = current.x2; newY1 = current.y2; newX2 = newX1; newY2 = newY1 + 1; } String key = createKey(newX1, newY1, newX2, newY2); if (!visited.contains(key)) { queue.add(new State(newX1, newY1, newX2, newY2, current.steps + 1)); visited.add(key); } } } } return Integer.MAX_VALUE; // No solution found } private static boolean isValidMove(char[][] grid, int M, int N, int x1, int y1, int x2, int y2) { // Check if both positions are within bounds and are free return (x1 >= 0 && x1 < M && y1 >= 0 && y1 < N && grid[x1][y1] != 'H') && (x2 >= 0 && x2 < M && y2 >= 0 && y2 < N && grid[x2][y2] != 'H'); } private static boolean isValidRotation(char[][] grid, int M, int N, int x1, int y1, int x2, int y2) { // Check if both positions are within bounds and are free return (x1 >= 0 && x1 < M && y1 >= 0 && y1 < N && grid[x1][y1] != 'H') && (x1 >= 0 && x1 < M && y2 >= 0 && y2 < N && grid[x1][y2] != 'H') && (x2 >= 0 && x2 < M && y1 >= 0 && y1 < N && grid[x2][y1] != 'H') && (x2 >= 0 && x2 < M && y2 >= 0 && y2 < N && grid[x2][y2] != 'H'); } private static String createKey(int x1, int y1, int x2, int y2) { // Create a unique key for the sofa position return x1 + ":" + y1 + "-" + x2 + ":" + y2; } }
Sofa problem done with private

import java.util.*; public class SofaProblem { private static final int[][] MOVES = {{0, 1}, {1, 0}, {0, -1}, {-1, 0}}; // Right, Down, Left, Up private static final int[][] ROTATE_MOVES = {{0, 0}, {0, 1}, {1, 0}, {1, 1}}; // Possible rotation positions static class State { int x1, y1, x2, y2; // Positions of the sofa int steps; // Steps taken to reach this state State(int x1, int y1, int x2, int y2, int steps) { this.x1 = x1; this.y1 = y1; this.x2 = x2; this.y2 = y2; this.steps = steps; } } public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int M = scanner.nextInt(); int N = scanner.nextInt(); scanner.nextLine(); // Consume the newline character char[][] grid = new char[M][N]; int startX1 = -1, startY1 = -1, startX2 = -1, startY2 = -1; int endX1 = -1, endY1 = -1, endX2 = -1, endY2 = -1; // Input reading and initialization for (int i = 0; i < M; i++) { String line = scanner.nextLine(); grid[i] = line.replaceAll(" ", "").toCharArray(); for (int j = 0; j < N; j++) { if (grid[i][j] == 's') { if (startX1 == -1) { startX1 = i; startY1 = j; } else { startX2 = i; startY2 = j; } } else if (grid[i][j] == 'S') { if (endX1 == -1) { endX1 = i; endY1 = j; } else { endX2 = i; endY2 = j; } } } } int result = bfs(grid, M, N, startX1, startY1, startX2, startY2, endX1, endY1, endX2, endY2); System.out.print(result == Integer.MAX_VALUE ? "Impossible" : result); scanner.close(); } private static int bfs(char[][] grid, int M, int N, int startX1, int startY1, int startX2, int startY2, int endX1, int endY1, int endX2, int endY2) { Queue<State> queue = new LinkedList<>(); Set<String> visited = new HashSet<>(); State initialState = new State(startX1, startY1, startX2, startY2, 0); queue.add(initialState); visited.add(createKey(startX1, startY1, startX2, startY2)); while (!queue.isEmpty()) { State current = queue.poll(); if (current.x1 == endX1 && current.y1 == endY1 && current.x2 == endX2 && current.y2 == endY2) { return current.steps; // Found the destination } // Move the sofa for (int[] move : MOVES) { int nx1 = current.x1 + move[0]; int ny1 = current.y1 + move[1]; int nx2 = current.x2 + move[0]; int ny2 = current.y2 + move[1]; // Check if move is valid if (isValidMove(grid, M, N, nx1, ny1, nx2, ny2)) { String key = createKey(nx1, ny1, nx2, ny2); if (!visited.contains(key)) { queue.add(new State(nx1, ny1, nx2, ny2, current.steps + 1)); visited.add(key); } } } // Rotate the sofa for (int[] move : ROTATE_MOVES) { int rotationX1 = current.x1 + move[0]; int rotationY1 = current.y1 + move[1]; int rotationX2 = current.x1 + move[0] + 1; int rotationY2 = current.y1 + move[1] + 1;

Ready for answer 👇👇👇👇👇

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SofaProblem public done do u need? Give reaction ♥️
SofaProblem public done do u need? Give reaction ♥️

Aarav and Arjun Fully accepted And long code do carefully

Aarav and Arjun Fully accepted And long code do carefully

double area = calculateArea(lines); System.out.printf("%.2f\n", area); boolean canFormSameFigure = canRecreateShape(lines, area); System.out.println(canFormSameFigure ? "Yes" : "No"); } else { System.out.print("No"); } sc.close(); } }

import java.util.*; public class AaravAndArjun { static class Point { int x, y; Point(int x, int y) { this.x = x; this.y = y; } @Override public boolean equals(Object obj) { if (this == obj) return true; if (!(obj instanceof Point)) return false; Point p = (Point) obj; return x == p.x && y == p.y; } @Override public int hashCode() { return Objects.hash(x, y); } } static class Line { Point start, end; Line(int x1, int y1, int x2, int y2) { this.start = new Point(x1, y1); this.end = new Point(x2, y2); } Set<Point> getEndpoints() { Set<Point> endpoints = new HashSet<>(); endpoints.add(start); endpoints.add(end); return endpoints; } } private static boolean isClosedFigure(List<Line> lines) { Map<Point, Integer> endpointCount = new HashMap<>(); // Count the occurrences of each endpoint for (Line line : lines) { Set<Point> endpoints = line.getEndpoints(); for (Point point : endpoints) { endpointCount.put(point, endpointCount.getOrDefault(point, 0) + 1); } } // There must be an even count of endpoints for a closed figure for (int count : endpointCount.values()) { if (count % 2 != 0) { return false; } } return endpointCount.size() >= 3; // Must be at least a triangle } private static double calculateArea(List<Line> lines) { // Assuming the lines form a simple polygon, we can use the shoelace formula double area = 0.0; List<Point> vertices = new ArrayList<>(); // Collect vertices of the polygon from lines for (Line line : lines) { vertices.add(line.start); vertices.add(line.end); } // Remove duplicate vertices Set<Point> uniqueVertices = new HashSet<>(vertices); List<Point> vertexList = new ArrayList<>(uniqueVertices); // Sort vertices in a counter-clockwise manner around the centroid // (not implemented for simplicity) int n = vertexList.size(); for (int i = 0; i < n; i++) { Point p1 = vertexList.get(i); Point p2 = vertexList.get((i + 1) % n); area += p1.x * p2.y - p2.x * p1.y; } return Math.abs(area) / 2.0; } private static boolean canRecreateShape(List<Line> lines, double area) { // Calculate total length of leftover sticks and compare with perimeter of the shape double leftoverLength = 0.0; for (Line line : lines) { double length = Math.sqrt(Math.pow(line.end.x - line.start.x, 2) + Math.pow(line.end.y - line.start.y, 2)); leftoverLength += length; } // For this problem, we assume we can recreate the shape if we have enough leftover length return leftoverLength >= area; // This is a simplification } public static void main(String[] args) { Scanner sc = new Scanner(System.in); int N = sc.nextInt(); // Number of sticks List<Line> lines = new ArrayList<>(); for (int i = 0; i < N; i++) { int x1 = sc.nextInt(); int y1 = sc.nextInt(); int x2 = sc.nextInt(); int y2 = sc.nextInt(); lines.add(new Line(x1, y1, x2, y2)); } if (isClosedFigure(lines)) { System.out.println("Yes");

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AaravAndArjun.... this code want Give reaction ♥️

Don't worry guys I am here naa ...i will upload answers for all questions

Hiii everyone If you want more TCS code vitaa free answer Then share my answer in big groups https://t.me/codeing_are
Join the group I will upload each every answer in free

import java.util.HashMap; import java.util.Map; import java.util.Scanner; public class MinimumMoves { public static int minimumMoves(String[] instruct) { String[] directions = {"up", "down", "left", "right"}; int s = instruct.length; int[][][] dp = new int[s + 1][4][4]; for (int i = 0; i <= s; i++) { for (int j = 0; j < 4; j++) { for (int k = 0; k < 4; k++) { dp[i][j][k] = Integer.MAX_VALUE; } } } for (int i = 0; i < 4; i++) { for (int j = 0; j < 4; j++) { dp[0][i][j] = 0; } } for (int k = 1; k <= s; k++) { int instrIdx = -1; for (int i = 0; i < 4; i++) { if (directions[i].equals(instruct[k - 1])) { instrIdx = i; break; } } for (int i = 0; i < 4; i++) { for (int j = 0; j < 4; j++) { if (dp[k - 1][i][j] != Integer.MAX_VALUE) { if (instrIdx == i || instrIdx == j) { dp[k][i][j] = Math.min(dp[k][i][j], dp[k - 1][i][j]); } else { dp[k][i][j] = Math.min(dp[k][i][j], dp[k - 1][instrIdx][j] + 1); dp[k][i][j] = Math.min(dp[k][i][j], dp[k - 1][i][instrIdx] + 1); } } } } } int minimumMoves = Integer.MAX_VALUE; for (int i = 0; i < 4; i++) { for (int j = 0; j < 4; j++) { minimumMoves = Math.min(minimumMoves, dp[s][i][j]); } } return minimumMoves; } public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int m = Integer.parseInt(scanner.nextLine().trim()); String[] instruct = new String[m]; for (int i = 0; i < m; i++) { instruct[i] = scanner.nextLine().trim(); } int result = minimumMoves(instruct); System.out.print(result); scanner.close(); } } Dance rev Java 8

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MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer - إحصائيات وتحليلات قناة تيليجرام @coding_are