C Programming Language || Hands On Coding
Hands-on C programming language challenges for beginners. Learn building logic by solving programs. Owner: @Pradeep_saii
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C Programming Language || Hands On Coding (@c_programming_language_coding) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 12 814 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 9 567-o'rinni va Hindiston mintaqasida 30 989-o'rinni egallagan.
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Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“Hands-on C programming language challenges for beginners. Learn building logic by solving programs.
Owner: @Pradeep_saii”
Yuqori yangilanish chastotasi (oxirgi ma’lumot 30 Avgust, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.
#include <stdio.h>
int main() {
int rows, number = 1;
printf("Enter the number of rows: ");
scanf("%d", &rows);
for (int i = 1; i <= rows; i++) {
for (int j = 1; j <= i; j++) {
printf("%d ", number);
number++;
}
printf("\n");
}
return 0;
}#include <stdio.h>
void printPyramid(int rows) {
for (int i = 1; i <= rows; i++) {
for (int j = 1; j <= rows - i; j++) {
printf(" ");
}
for (int k = 1; k <= 2 * i - 1; k++) {
printf("*");
}
printf("\n");
}
}
void printInvertedPyramid(int rows) {
for (int i = rows; i >= 1; i--) {
for (int j = 1; j <= rows - i; j++) {
printf(" ");
}
for (int k = 1; k <= 2 * i - 1; k++) {
printf("*");
}
printf("\n");
}
}
void printDiamond(int rows) {
printPyramid(rows);
printInvertedPyramid(rows - 1);
}
int main() {
int rows;
printf("Enter the number of rows: ");
scanf("%d", &rows);
printf("\nPyramid:\n");
printPyramid(rows);
printf("\nInverted Pyramid:\n");
printInvertedPyramid(rows);
printf("\nDiamond:\n");
printDiamond(rows);
return 0;
}#include <stdio.h>
int countDigits(int n) {
int count = 0;
if (n == 0) return 1;
while (n != 0) {
n /= 10;
count++;
}
return count;
}
int main() {
int num;
printf("Enter an integer: ");
scanf("%d", &num);
printf("Number of digits: %d\n", countDigits(num));
return 0;
}#include <stdio.h>
int main() {
int num, sum = 0, m;
scanf("%d", &num);
while (num > 0) {
m = num % 10;
sum = sum + m;
num = num / 10;
}
printf("%d", sum);
return 0;
}#include <stdio.h>
int main() {
int n;
printf("Enter a positive integer: ");
scanf("%d", &n);
printf("Using for loop:\n");
for (int i = 1; i <= n; i++) {
printf("%d ", i);
}
printf("\n");
printf("Using while loop:\n");
int j = 1;
while (j <= n) {
printf("%d ", j);
j++;
}
printf("\n
");
printf("Using do-while loop:\n");
int k = 1;
do {
printf("%d ", k);
k++;
} while (k <= n);
printf("\n");
return 0;
}#include <stdio.h>
int main() {
int num, i;
printf("Enter a positive integer: ");
scanf("%d", &num);
printf("Divisors of %d are: ", num);
for (i = 1; i <= num; ++i) {
if (num % i == 0) {
printf("%d ", i);
}
}
printf("\n");
return 0;
}#include <stdio.h>
int main() {
int n, i, j;
printf("Enter the number of rows: ");
scanf("%d", &n);
for (i = 1; i <= n; i++) {
for (j = 1; j <= n; j++) {
printf("%4d", i * j);
}
printf("\n");
}
return 0;
}#include <stdio.h>
int main() {
int n, i;
long long t1 = 0, t2 = 1;
long long nextTerm = t1 + t2;
printf("Enter the number of terms: ");
scanf("%d", &n);
printf("Fibonacci Series: %lld, %lld, ", t1, t2);
for (i = 3; i <= n; ++i) {
printf("%lld, ", nextTerm);
t1 = t2;
t2 = nextTerm;
nextTerm = t1 + t2;
}
printf("\n");
return 0;
}#include <stdio.h>
#include <math.h>
int main() {
int num, originalNum, remainder, n = 0;
float result = 0.0;
printf("Enter an integer: ");
scanf("%d", &num);
originalNum = num;
while (originalNum != 0) {
originalNum /= 10;
++n;
}
originalNum = num;
while (originalNum != 0) {
remainder = originalNum % 10;
result += pow(remainder, n);
originalNum /= 10;
}
if ((int)result == num)
printf("%d is an Armstrong number.\n", num);
else
printf("%d is not an Armstrong number.\n", num);
return 0;
}#include <stdio.h>
#include <stdbool.h>
bool isPalindrome(int num) {
int reversedNum = 0, remainder, originalNum = num;
while (num != 0) {
remainder = num % 10;
reversedNum = reversedNum * 10 + remainder;
num /= 10;
}
return originalNum == reversedNum;
}
int main() {
int number;
scanf("%d", &number);
if (isPalindrome(number)) {
printf("Palindrome");
} else {
printf("Not Palindrome");
}
return 0;
}