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allcoding1

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allcoding1 (@allcoding1) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 22 561 obunachidan iborat bo'lib, Taʼlim toifasida 8 836-o'rinni va Hindiston mintaqasida 19 517-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 22 561 obunachiga ega bo‘ldi.

13 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -442 ga, so‘nggi 24 soatda esa -20 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 6.17% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.25% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 1 394 marta ko‘riladi; birinchi sutkada odatda 283 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 2 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, learning kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 14 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

22 561
Obunachilar
-2024 soatlar
-897 kunlar
-44230 kunlar
Postlar arxiv
Only conclusion I follow

Husband

Cat : feline

F

Accenture exam Answer 2/4/24 @allcoding1 1) I got sick, I have _ As) an 2) A) but everyone B) government C) an should D) global.. As) DBAC 3) ocean : shallow As) infinite 4) I comb my hair.... As) I used to 5) antonym word " ACCURATE " As) invalid 6) Continue As) prolong 7) we felt____missing the farewell party As) didn't feel good @allcoding1 8) horizontal bar represent As) date input/output 9) charvi is the mother of sara... As) sister in law 10) by the time we arrived they____ (to leave) As) had left 11) 1) it is possible to determine.... 2) no other mobile brand.... As) both conclusion follow Telegram:- @allcoding1

Accenture exam Answer 2/4/24 Accenture exam Answer 2/4/24 1) I got sick, I have _ As) an 2) A) but everyone      B) government      C) an should      D) global.. As) DBAC 3) ocean : shallow As) infinite 4) I comb my hair.... As) I used to 5) antonym word " ACCURATE " As) invalid 6)  Continue As) prolong 7) we felt____missing the farewell party As) didn't feel good @allcoding1_official 8) horizontal bar represent As) date input/output 9) charvi is the mother of sara... As) sister in law 10) by the time we arrived they____ (to leave) As) had left 11) 1) it is possible to determine....    2) no other mobile brand.... As) both conclusion follow Telegram:- @allcoding1 1) I got sick, I have _ As) an 2) A) but everyone B) government C) an should D) global.. As) DBAC 3) ocean : shallow As) infinite 4) I comb my hair.... As) I used to 5) antonym word " ACCURATE " As) invalid 6) Continue As) prolong 7) we felt____missing the farewell party As) didn't feel good @allcoding1 8) horizontal bar represent As) date input/output 9) charvi is the mother of sara... As) sister in law 10) by the time we arrived they____ (to leave) As) had left 11) 1) it is possible to determine.... 2) no other mobile brand.... As) both conclusion follow Telegram:- @allcoding1

Diverse Deputations Python 3
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Diverse Deputations Python 3

#include using namespace std; typedef long long LL; #define max_v 25 bool f(double A,double B,double a,double b) {  &nbs
#include<bits/stdc++.h> using namespace std; typedef long long LL; #define max_v 25 bool f(double A,double B,double a,double b) {     double d=sqrt(a*a+b*b);     double a1=asin(A/d);     double a2=asin(b/d)*2.0;     double h=cos(a1-a2)*d;     if(B>h)         return true;     else         return false; } int main() {     int t;     bool flag;     cin >> t;     while(t--)     {         double A,B,a,b;         cin >> A >> B >> a >> b;         if(A<B)             swap(A,B);         if(a<b)             swap(a,b);         if(A>a&&B>b)         {             flag=true;         }         else if(A*B<=a*b||b>=B)         {             flag=false;         }else         {             flag=f(A,B,a,b);         }         if(flag)         {             cout << "Escape is possible." << endl;         }else         {             cout << "Box cannot be dropped." << endl;         }     }     return 0; } INFAthon 4.0 Telegram:- @allcoding1

int main() { &nbsp;&nbsp;&nbsp; string text; &nbsp;&nbsp;&nbsp; getline(cin, text); &nbsp;&nbsp;&nbsp; int index = 0; &nbsp;&
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int main() {     string text;     getline(cin, text);     int index = 0;     while (index + 13 < text.length() && (index = text.rfind(" ", index + 13)) != string::npos) {         text.replace(index, 1, "\n");     }     cout << text << endl;     return 0; } INFA thon 4.0

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#include<bits/stdc++.h> using namespace std; const int MOD = 1e9 + 7; vector<vector<vector<string>>> dp; vector<string> solve(string& alice, string& bob, int i, int j) {     if(i == alice.size() || j == bob.size()) {         return {""};     }     if(dp[i][j].size() != 0) {         return dp[i][j];     }     if(alice[i] == bob[j]) {         vector<string> tmp = solve(alice, bob, i+1, j+1);         for(string& s : tmp) {             s = alice[i] + s;         }         return dp[i][j] = tmp;     }     vector<string> left = solve(alice, bob, i+1, j);     vector<string> right = solve(alice, bob, i, j+1);     if(left[0].size() > right[0].size()) {         return dp[i][j] = left;     }     if(left[0].size() < right[0].size()) {         return dp[i][j] = right;     }     left.insert(left.end(), right.begin(), right.end());     sort(left.begin(), left.end());     left.erase(unique(left.begin(), left.end()), left.end());     return dp[i][j] = left; } int main() {     int T;     cin >> T;     while(T--) {         string alice, bob;         cin >> alice >> bob;         dp = vector<vector<vector<string>>>(alice.size(), vector<vector<string>>(bob.size()));         vector<string> trips = solve(alice, bob, 0, 0);         for(string& trip : trips) {             cout << trip << endl;         }     }     return 0; }

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#include <iostream> #include <vector> #include <algorithm> using namespace std; class Solution { public:     int maxSumOptimalArrangement(vector<int>& coins) {         vector<int> positive;         vector<int> negative;         for (int coin : coins) {             if (coin >= 0)                 positive.push_back(coin);             else                 negative.push_back(coin);         }         sort(positive.rbegin(), positive.rend());                 sort(negative.begin(), negative.end());         int totalSum = 0;         for (size_t i = 0; i < max(positive.size(), negative.size()); ++i) {             if (i < positive.size())                 totalSum += positive[i];             if (i < negative.size())                 totalSum -= negative[i];         }         return totalSum;     } }; ZS campus beat code Circuit Board Telegram:- @allcoding1

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#include #include #define MOD 1000000007 int compare(const void *a, const void *b) { &nbsp;&nbsp;&nbsp; return (*(int*)a - *(
#include<stdio.h> #include<stdlib.h> #define MOD 1000000007 int compare(const void *a, const void *b) {     return (*(int*)a - *(int*)b); } int main() {     int N;     scanf("%d", &N);     if (N <= 1) {         printf("NO HOURS\n");         return 0;     }     int *A = (int*)malloc(N * sizeof(int));     for (int i = 0; i < N; i++) {         scanf("%d", &A[i]);     }     qsort(A, N, sizeof(int), compare);     int count = 0;     for (int i = 0; i < N - 1; i++) {         for (int j = i + 1; j < N; j++) {             if ((A[i] + A[j]) % 60 == 0) {                 count = (count + 1) % MOD;             }         }     }     if (count > 0) {         printf("%d\n", count);     } else {         printf("NO HOURS\n");     }     free(A);     return 0; } Hours Count Telegram:-

Repost from allcoding1_official
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Work
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📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources English , 🇫🇷 All courses (100 rupees) Contact:- @meterials_available Proofs:- https://t.me/+mP2YTsMihZozNWQ1

Repost from allcoding1_official
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Work
+8
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources English , 🇫🇷 All courses (100 rupees) Contact:- @meterials_available Proofs:- https://t.me/+mP2YTsMihZozNWQ1