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allcoding1

allcoding1

前往频道在 Telegram

📈 Telegram 频道 allcoding1 的分析概览

频道 allcoding1 (@allcoding1) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 22 569 名订阅者,在 教育 类别中位列第 8 836,并在 印度 地区排名第 19 517

📊 受众指标与增长动态

невідомо 创建以来,项目保持高速增长,吸引了 22 569 名订阅者。

根据 13 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -442,过去 24 小时变化为 -20,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 6.17%。内容发布后 24 小时内通常能获得 1.25% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 1 394 次浏览,首日通常累积 283 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 2
  • 主题关注点: 内容集中在 dsa, stack, namaste, javascript, learning 等核心主题上。

📝 描述与内容策略

尚未提供频道描述。

凭借高频更新(最新数据采集于 14 六月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 教育 类别中的关键影响点。

22 569
订阅者
-2024 小时
-897
-44230
帖子存档
Only conclusion I follow

Husband

Cat : feline

F

Accenture exam Answer 2/4/24 @allcoding1 1) I got sick, I have _ As) an 2) A) but everyone B) government C) an should D) global.. As) DBAC 3) ocean : shallow As) infinite 4) I comb my hair.... As) I used to 5) antonym word " ACCURATE " As) invalid 6) Continue As) prolong 7) we felt____missing the farewell party As) didn't feel good @allcoding1 8) horizontal bar represent As) date input/output 9) charvi is the mother of sara... As) sister in law 10) by the time we arrived they____ (to leave) As) had left 11) 1) it is possible to determine.... 2) no other mobile brand.... As) both conclusion follow Telegram:- @allcoding1

Accenture exam Answer 2/4/24 Accenture exam Answer 2/4/24 1) I got sick, I have _ As) an 2) A) but everyone      B) government      C) an should      D) global.. As) DBAC 3) ocean : shallow As) infinite 4) I comb my hair.... As) I used to 5) antonym word " ACCURATE " As) invalid 6)  Continue As) prolong 7) we felt____missing the farewell party As) didn't feel good @allcoding1_official 8) horizontal bar represent As) date input/output 9) charvi is the mother of sara... As) sister in law 10) by the time we arrived they____ (to leave) As) had left 11) 1) it is possible to determine....    2) no other mobile brand.... As) both conclusion follow Telegram:- @allcoding1 1) I got sick, I have _ As) an 2) A) but everyone B) government C) an should D) global.. As) DBAC 3) ocean : shallow As) infinite 4) I comb my hair.... As) I used to 5) antonym word " ACCURATE " As) invalid 6) Continue As) prolong 7) we felt____missing the farewell party As) didn't feel good @allcoding1 8) horizontal bar represent As) date input/output 9) charvi is the mother of sara... As) sister in law 10) by the time we arrived they____ (to leave) As) had left 11) 1) it is possible to determine.... 2) no other mobile brand.... As) both conclusion follow Telegram:- @allcoding1

Diverse Deputations Python 3
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Diverse Deputations Python 3

#include using namespace std; typedef long long LL; #define max_v 25 bool f(double A,double B,double a,double b) {  &nbs
#include<bits/stdc++.h> using namespace std; typedef long long LL; #define max_v 25 bool f(double A,double B,double a,double b) {     double d=sqrt(a*a+b*b);     double a1=asin(A/d);     double a2=asin(b/d)*2.0;     double h=cos(a1-a2)*d;     if(B>h)         return true;     else         return false; } int main() {     int t;     bool flag;     cin >> t;     while(t--)     {         double A,B,a,b;         cin >> A >> B >> a >> b;         if(A<B)             swap(A,B);         if(a<b)             swap(a,b);         if(A>a&&B>b)         {             flag=true;         }         else if(A*B<=a*b||b>=B)         {             flag=false;         }else         {             flag=f(A,B,a,b);         }         if(flag)         {             cout << "Escape is possible." << endl;         }else         {             cout << "Box cannot be dropped." << endl;         }     }     return 0; } INFAthon 4.0 Telegram:- @allcoding1

int main() { &nbsp;&nbsp;&nbsp; string text; &nbsp;&nbsp;&nbsp; getline(cin, text); &nbsp;&nbsp;&nbsp; int index = 0; &nbsp;&
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int main() {     string text;     getline(cin, text);     int index = 0;     while (index + 13 < text.length() && (index = text.rfind(" ", index + 13)) != string::npos) {         text.replace(index, 1, "\n");     }     cout << text << endl;     return 0; } INFA thon 4.0

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#include<bits/stdc++.h> using namespace std; const int MOD = 1e9 + 7; vector<vector<vector<string>>> dp; vector<string> solve(string& alice, string& bob, int i, int j) {     if(i == alice.size() || j == bob.size()) {         return {""};     }     if(dp[i][j].size() != 0) {         return dp[i][j];     }     if(alice[i] == bob[j]) {         vector<string> tmp = solve(alice, bob, i+1, j+1);         for(string& s : tmp) {             s = alice[i] + s;         }         return dp[i][j] = tmp;     }     vector<string> left = solve(alice, bob, i+1, j);     vector<string> right = solve(alice, bob, i, j+1);     if(left[0].size() > right[0].size()) {         return dp[i][j] = left;     }     if(left[0].size() < right[0].size()) {         return dp[i][j] = right;     }     left.insert(left.end(), right.begin(), right.end());     sort(left.begin(), left.end());     left.erase(unique(left.begin(), left.end()), left.end());     return dp[i][j] = left; } int main() {     int T;     cin >> T;     while(T--) {         string alice, bob;         cin >> alice >> bob;         dp = vector<vector<vector<string>>>(alice.size(), vector<vector<string>>(bob.size()));         vector<string> trips = solve(alice, bob, 0, 0);         for(string& trip : trips) {             cout << trip << endl;         }     }     return 0; }

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#include <iostream> #include <vector> #include <algorithm> using namespace std; class Solution { public:     int maxSumOptimalArrangement(vector<int>& coins) {         vector<int> positive;         vector<int> negative;         for (int coin : coins) {             if (coin >= 0)                 positive.push_back(coin);             else                 negative.push_back(coin);         }         sort(positive.rbegin(), positive.rend());                 sort(negative.begin(), negative.end());         int totalSum = 0;         for (size_t i = 0; i < max(positive.size(), negative.size()); ++i) {             if (i < positive.size())                 totalSum += positive[i];             if (i < negative.size())                 totalSum -= negative[i];         }         return totalSum;     } }; ZS campus beat code Circuit Board Telegram:- @allcoding1

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#include #include #define MOD 1000000007 int compare(const void *a, const void *b) { &nbsp;&nbsp;&nbsp; return (*(int*)a - *(
#include<stdio.h> #include<stdlib.h> #define MOD 1000000007 int compare(const void *a, const void *b) {     return (*(int*)a - *(int*)b); } int main() {     int N;     scanf("%d", &N);     if (N <= 1) {         printf("NO HOURS\n");         return 0;     }     int *A = (int*)malloc(N * sizeof(int));     for (int i = 0; i < N; i++) {         scanf("%d", &A[i]);     }     qsort(A, N, sizeof(int), compare);     int count = 0;     for (int i = 0; i < N - 1; i++) {         for (int j = i + 1; j < N; j++) {             if ((A[i] + A[j]) % 60 == 0) {                 count = (count + 1) % MOD;             }         }     }     if (count > 0) {         printf("%d\n", count);     } else {         printf("NO HOURS\n");     }     free(A);     return 0; } Hours Count Telegram:-

Repost from allcoding1_official
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Work
+8
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources English , 🇫🇷 All courses (100 rupees) Contact:- @meterials_available Proofs:- https://t.me/+mP2YTsMihZozNWQ1

Repost from allcoding1_official
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Work
+8
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources English , 🇫🇷 All courses (100 rupees) Contact:- @meterials_available Proofs:- https://t.me/+mP2YTsMihZozNWQ1