allcoding1
前往频道在 Telegram
📈 Telegram 频道 allcoding1 的分析概览
频道 allcoding1 (@allcoding1) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 22 569 名订阅者,在 教育 类别中位列第 8 836,并在 印度 地区排名第 19 517 位。
📊 受众指标与增长动态
自 невідомо 创建以来,项目保持高速增长,吸引了 22 569 名订阅者。
根据 13 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -442,过去 24 小时变化为 -20,整体触达仍然可观。
- 认证状态: 未认证
- 互动率 (ER): 平均受众互动率为 6.17%。内容发布后 24 小时内通常能获得 1.25% 的反应,占订阅者总量。
- 帖子覆盖: 每篇帖子平均可获得 1 394 次浏览,首日通常累积 283 次浏览。
- 互动与反馈: 受众积极参与,单帖平均反应数为 2。
- 主题关注点: 内容集中在 dsa, stack, namaste, javascript, learning 等核心主题上。
📝 描述与内容策略
尚未提供频道描述。
凭借高频更新(最新数据采集于 14 六月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 教育 类别中的关键影响点。
22 569
订阅者
-2024 小时
-897 天
-44230 天
帖子存档
22 561
Accenture exam Answer 2/4/24
@allcoding1
1) I got sick, I have _
As) an
2) A) but everyone
B) government
C) an should
D) global..
As) DBAC
3) ocean : shallow
As) infinite
4) I comb my hair....
As) I used to
5) antonym word " ACCURATE "
As) invalid
6) Continue
As) prolong
7) we felt____missing the farewell party
As) didn't feel good
@allcoding1
8) horizontal bar represent
As) date input/output
9) charvi is the mother of sara...
As) sister in law
10) by the time we arrived they____ (to leave)
As) had left
11) 1) it is possible to determine....
2) no other mobile brand....
As) both conclusion follow
Telegram:- @allcoding1
22 561
Accenture exam Answer 2/4/24
Accenture exam Answer 2/4/24
1) I got sick, I have _
As) an
2) A) but everyone
B) government
C) an should
D) global..
As) DBAC
3) ocean : shallow
As) infinite
4) I comb my hair....
As) I used to
5) antonym word " ACCURATE "
As) invalid
6) Continue
As) prolong
7) we felt____missing the farewell party
As) didn't feel good
@allcoding1_official
8) horizontal bar represent
As) date input/output
9) charvi is the mother of sara...
As) sister in law
10) by the time we arrived they____ (to leave)
As) had left
11) 1) it is possible to determine....
2) no other mobile brand....
As) both conclusion follow
Telegram:- @allcoding1
1) I got sick, I have _
As) an
2) A) but everyone
B) government
C) an should
D) global..
As) DBAC
3) ocean : shallow
As) infinite
4) I comb my hair....
As) I used to
5) antonym word " ACCURATE "
As) invalid
6) Continue
As) prolong
7) we felt____missing the farewell party
As) didn't feel good
@allcoding1
8) horizontal bar represent
As) date input/output
9) charvi is the mother of sara...
As) sister in law
10) by the time we arrived they____ (to leave)
As) had left
11) 1) it is possible to determine....
2) no other mobile brand....
As) both conclusion follow
Telegram:- @allcoding1
22 561
#include<bits/stdc++.h>
using namespace std;
typedef long long LL;
#define max_v 25
bool f(double A,double B,double a,double b)
{
double d=sqrt(a*a+b*b);
double a1=asin(A/d);
double a2=asin(b/d)*2.0;
double h=cos(a1-a2)*d;
if(B>h)
return true;
else
return false;
}
int main()
{
int t;
bool flag;
cin >> t;
while(t--)
{
double A,B,a,b;
cin >> A >> B >> a >> b;
if(A<B)
swap(A,B);
if(a<b)
swap(a,b);
if(A>a&&B>b)
{
flag=true;
}
else if(A*B<=a*b||b>=B)
{
flag=false;
}else
{
flag=f(A,B,a,b);
}
if(flag)
{
cout << "Escape is possible." << endl;
}else
{
cout << "Box cannot be dropped." << endl;
}
}
return 0;
}
INFAthon 4.0
Telegram:- @allcoding1
22 561
+1
int main()
{
string text;
getline(cin, text);
int index = 0;
while (index + 13 < text.length() && (index = text.rfind(" ", index + 13)) != string::npos) {
text.replace(index, 1, "\n");
}
cout << text << endl;
return 0;
}
INFA thon 4.0
22 561
+8
📌IT learning courses
📌All programing courses
📌Abdul bari courses
📌Ashok IT
Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
🔹Artificial Intelligence
🔹AWS Certified
🔹Cloud
🔹BIG DATA
🔹Data Analytics
🔹BI
🔹Google Cloud Platform
🔹IT Training
🔹MBA
🔹Machine Learning
🔹Deep Learning
🔹Ethical Hacking
🔹SPSS
🔹Statistics
🔹Data Base
🔹Learning language resources English , 🇫🇷
All courses (100 rupees)
Contact:- @meterials_available
22 561
#include<bits/stdc++.h>
using namespace std;
const int MOD = 1e9 + 7;
vector<vector<vector<string>>> dp;
vector<string> solve(string& alice, string& bob, int i, int j) {
if(i == alice.size() || j == bob.size()) {
return {""};
}
if(dp[i][j].size() != 0) {
return dp[i][j];
}
if(alice[i] == bob[j]) {
vector<string> tmp = solve(alice, bob, i+1, j+1);
for(string& s : tmp) {
s = alice[i] + s;
}
return dp[i][j] = tmp;
}
vector<string> left = solve(alice, bob, i+1, j);
vector<string> right = solve(alice, bob, i, j+1);
if(left[0].size() > right[0].size()) {
return dp[i][j] = left;
}
if(left[0].size() < right[0].size()) {
return dp[i][j] = right;
}
left.insert(left.end(), right.begin(), right.end());
sort(left.begin(), left.end());
left.erase(unique(left.begin(), left.end()), left.end());
return dp[i][j] = left;
}
int main() {
int T;
cin >> T;
while(T--) {
string alice, bob;
cin >> alice >> bob;
dp = vector<vector<vector<string>>>(alice.size(), vector<vector<string>>(bob.size()));
vector<string> trips = solve(alice, bob, 0, 0);
for(string& trip : trips) {
cout << trip << endl;
}
}
return 0;
}
22 561
#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
class Solution {
public:
int maxSumOptimalArrangement(vector<int>& coins) {
vector<int> positive;
vector<int> negative;
for (int coin : coins) {
if (coin >= 0)
positive.push_back(coin);
else
negative.push_back(coin);
}
sort(positive.rbegin(), positive.rend());
sort(negative.begin(), negative.end());
int totalSum = 0;
for (size_t i = 0; i < max(positive.size(), negative.size()); ++i) {
if (i < positive.size())
totalSum += positive[i];
if (i < negative.size())
totalSum -= negative[i];
}
return totalSum;
}
};
ZS campus beat code
Circuit Board
Telegram:- @allcoding1
22 561
+8
📌IT learning courses
📌All programing courses
📌Abdul bari courses
📌Ashok IT
Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
🔹Artificial Intelligence
🔹AWS Certified
🔹Cloud
🔹BIG DATA
🔹Data Analytics
🔹BI
🔹Google Cloud Platform
🔹IT Training
🔹MBA
🔹Machine Learning
🔹Deep Learning
🔹Ethical Hacking
🔹SPSS
🔹Statistics
🔹Data Base
🔹Learning language resources English , 🇫🇷
All courses (100 rupees)
Contact:- @meterials_available
22 561
Company Name: Qualcomm
Job Title: Software Engineer Intern
2024 and 2025
Apply Now:- https://careers.qualcomm.com/careers/job?domain=qualcomm.com&pid=446693743471&query=intern&location=India&domain=qualcomm.com&sort_by=relevance&job_index=0
Telegram:- @allcoding1
22 561
#include<stdio.h>
#include<stdlib.h>
#define MOD 1000000007
int compare(const void *a, const void *b) {
return (*(int*)a - *(int*)b);
}
int main() {
int N;
scanf("%d", &N);
if (N <= 1) {
printf("NO HOURS\n");
return 0;
}
int *A = (int*)malloc(N * sizeof(int));
for (int i = 0; i < N; i++) {
scanf("%d", &A[i]);
}
qsort(A, N, sizeof(int), compare);
int count = 0;
for (int i = 0; i < N - 1; i++) {
for (int j = i + 1; j < N; j++) {
if ((A[i] + A[j]) % 60 == 0) {
count = (count + 1) % MOD;
}
}
}
if (count > 0) {
printf("%d\n", count);
} else {
printf("NO HOURS\n");
}
free(A);
return 0;
}
Hours Count
Telegram:-
22 561
Repost from allcoding1_official
+8
📌IT learning courses
📌All programing courses
📌Abdul bari courses
📌Ashok IT
Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
🔹Artificial Intelligence
🔹AWS Certified
🔹Cloud
🔹BIG DATA
🔹Data Analytics
🔹BI
🔹Google Cloud Platform
🔹IT Training
🔹MBA
🔹Machine Learning
🔹Deep Learning
🔹Ethical Hacking
🔹SPSS
🔹Statistics
🔹Data Base
🔹Learning language resources English , 🇫🇷
All courses (100 rupees)
Contact:- @meterials_available
Proofs:- https://t.me/+mP2YTsMihZozNWQ1
22 561
Repost from allcoding1_official
+8
📌IT learning courses
📌All programing courses
📌Abdul bari courses
📌Ashok IT
Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
🔹Artificial Intelligence
🔹AWS Certified
🔹Cloud
🔹BIG DATA
🔹Data Analytics
🔹BI
🔹Google Cloud Platform
🔹IT Training
🔹MBA
🔹Machine Learning
🔹Deep Learning
🔹Ethical Hacking
🔹SPSS
🔹Statistics
🔹Data Base
🔹Learning language resources English , 🇫🇷
All courses (100 rupees)
Contact:- @meterials_available
Proofs:- https://t.me/+mP2YTsMihZozNWQ1
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