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Firibgarlarga uchmang! Telemetrio bunday kanallarni topadi va belgilaydi 👉 Belgini ko‘rmoqchi bo‘lsangiz, obuna bo‘ling

AddMath Spmnetic!™⚡️

AddMath Spmnetic!™⚡️

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This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨

Ko'proq ko'rsatish

📈 Telegram kanali AddMath Spmnetic!™⚡️ analitikasi

AddMath Spmnetic!™⚡️ (@addmathspmnotes) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 38 070 obunachidan iborat bo'lib, Taʼlim toifasida 4 953-o'rinni va Hindiston mintaqasida 10 228-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 38 070 obunachiga ega bo‘ldi.

27 Oktabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni 988 ga, so‘nggi 24 soatda esa 29 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 11.80% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 6.49% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 4 490 marta ko‘riladi; birinchi sutkada odatda 2 470 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 12 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent addmath, untuk, 629/4, math, eqn kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨”

Yuqori yangilanish chastotasi (oxirgi ma’lumot 28 Oktabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

38 070
Obunachilar
+2924 soatlar
+1787 kun
+98830 kun
Postlar arxiv
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Lol guys help our GOAT Jason to get an iPhone by forwarding the same link to more ppl 🔥 🔥

Those who want devices to study can join this PTTI competition, U also have to send the link to others in order to increase your rank...

5 HARI LAGI BAKAL TAMAT! Peluang besar masih ada untuk menang iPad, Macbook dan iPhone 17 Pro! Hanya perlu sharekan link awak
5 HARI LAGI BAKAL TAMAT! Peluang besar masih ada untuk menang iPad, Macbook dan iPhone 17 Pro! Hanya perlu sharekan link awak kepada kawan-kawan. Makin ramai kawan yang join, makin besar peluang awak untuk menang. Layari https://contest.ptti.my/belajarbersamaptti untuk sertai peraduan dan dapatkan link awak.

There ya’ go 🙌🏻
+1
There ya’ go 🙌🏻

Just extra info, I also dk much about it..but y'all can research about it and learn more
Just extra info, I also dk much about it..but y'all can research about it and learn more

(e) When pp(x)=x, p(x) is a function such that p^-1(x)=p(x). Draw a ring around the function that has this property. f(x)=2x-1 , g(x)=3x+2, h(x)=1/x, x not equal to 0, j(x)=x^2 level: hard

(d) Find hf(x) +gh(x), giving your answer in a single fraction in its simplest form.

(a) j(-1), (b) find x when f(x) +g(x)=0, (c) gg(x), giving your answer in its simplest form.
(a) j(-1), (b) find x when f(x) +g(x)=0, (c) gg(x), giving your answer in its simplest form.

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try 🤓
try 🤓

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Question 1: Functions & Quadratic Equations Given that f(x)=2x-3 and g(x)=x^2+4x+1. (a) find: (i) f^-1(x) [2 marks] (ii) gf(x) [2 marks] (b) solve the equation gf(x)=6. [3 marks] (c) find the range of values of k for which the equation g(x)=k has no real roots. [ 3 marks ]

For those who are taking DLP, a. Show that h = ⅛. [2 marks] b. Determine the volume, in cm³, of the water required to fill in the container such that the depth of water is 6cm. [4 marks]

a) Tunjukkan bahawa h=1/8. [2m] b) Tentukan isi padu , dalam cm^3 , air yang diperlukan untuk mengisi bekas itu dengan kedala
a) Tunjukkan bahawa h=1/8. [2m] b) Tentukan isi padu , dalam cm^3 , air yang diperlukan untuk mengisi bekas itu dengan kedalaman 6 cm. [4m]

Soalan 6(b) Trial K2 SPM 2024
Soalan 6(b) Trial K2 SPM 2024