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Those who need Job in It Companies can check this channel Join now @Offcampus_000 🔥🔥 Latest Jobs and Internships Updates for 2021,2022, 2023 and 2024 Batch

Any one want to crack Azure Fundamentals Dumps available ✅ Contact @ILOVEU_143👨‍💻 100% clearance guarantee 🔥🔥 Share @Codi
Any one want to crack Azure Fundamentals Dumps available ✅ Contact @ILOVEU_143👨‍💻 100% clearance guarantee 🔥🔥 Share @Coding_000 ❤️

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Deloitte Interview clear ❤️💯👨‍💻 Congratulations bro 🎉
Deloitte Interview clear ❤️💯👨‍💻 Congratulations bro  🎉

Give reactions and share our channel fast ✅ Please check all Codes uploaded... 👆👆 Jobathon👆👆 @Coding_000❤️

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Give reactions and share our channel fast ✅ Please check all Codes uploaded... 👆👆 @Coding_000❤️

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Fest and Posters Code✅ Python3 ✅ All test cases Passed ✅
Fest and Posters  Code✅ Python3 ✅ All test cases Passed

geek and xor play code done   ✅ class Solution { public: #define ll long long     vector<ll> xorPairs(int n, vector<int> &A1, vector<int> &A2, int Q, vector<vector<int>> &query)     {         vector<vector<ll>> temperary(30, vector<ll>(n)), typmu(30, vector<ll>(n));         for (int j = 0; j < 30; j++)         {             for (int i = 0; i < n; i++)             {                 temperary[j][i] = (i ? temperary[j][i - 1] : 0) + ((A1[i] >> j) & (1ll) == 1);             }             for (int i = 0; i < n; i++)             {                 typmu[j][i] = (i ? typmu[j][i - 1] : 0) + ((A2[i] >> j) & (1ll) == 1);             }         }         vector<ll> answer;         for (auto it : query)         {             ll k = it[0];             k--;             ll l1 = it[1];             ll r1 = it[2];             ll l2 = it[3];             ll r2 = it[4];             l1--;             r1--;             l2--;             r2--; @Coding_000             ll cnt_k_1 = temperary[k][r1] - (l1 ? temperary[k][l1 - 1] : 0);             ll cnt_k_2 = typmu[k][r2] - (l2 ? typmu[k][l2 - 1] : 0);             ll ans1 = 0;             ans1 += (r1 - l1 + 1 - cnt_k_1) * (cnt_k_2);             ans1 += (r2 - l2 + 1 - cnt_k_2) * (cnt_k_1);             answer.push_back(ans1);         }         return answer;     } }; code in c++  ✅ ✅ share @Coding_000❤️