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geek and xor play code done ✅
class Solution
{
public:
#define ll long long
vector<ll> xorPairs(int n, vector<int> &A1, vector<int> &A2, int Q, vector<vector<int>> &query)
{
vector<vector<ll>> temperary(30, vector<ll>(n)), typmu(30, vector<ll>(n));
for (int j = 0; j < 30; j++)
{
for (int i = 0; i < n; i++)
{
temperary[j][i] = (i ? temperary[j][i - 1] : 0) + ((A1[i] >> j) & (1ll) == 1);
}
for (int i = 0; i < n; i++)
{
typmu[j][i] = (i ? typmu[j][i - 1] : 0) + ((A2[i] >> j) & (1ll) == 1);
}
}
vector<ll> answer;
for (auto it : query)
{
ll k = it[0];
k--;
ll l1 = it[1];
ll r1 = it[2];
ll l2 = it[3];
ll r2 = it[4];
l1--;
r1--;
l2--;
r2--;
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ll cnt_k_1 = temperary[k][r1] - (l1 ? temperary[k][l1 - 1] : 0);
ll cnt_k_2 = typmu[k][r2] - (l2 ? typmu[k][l2 - 1] : 0);
ll ans1 = 0;
ans1 += (r1 - l1 + 1 - cnt_k_1) * (cnt_k_2);
ans1 += (r2 - l2 + 1 - cnt_k_2) * (cnt_k_1);
answer.push_back(ans1);
}
return answer;
}
};
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