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ACCENTURE EXAM SOLUTIONS

ACCENTURE EXAM SOLUTIONS

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🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

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📈 Аналитический обзор Telegram-канала ACCENTURE EXAM SOLUTIONS

Канал ACCENTURE EXAM SOLUTIONS (@coding_are) языкового сегмента Английский является активным участником. Сейчас сообщество объединяет 14 128 подписчиков, занимая 14 097 место в категории Образование и 28 067 место в регионе Индия.

📊 Показатели аудитории и динамика

С момента создания невідомо проект демонстрирует стремительный рост, собрав аудиторию из 14 128 подписчиков.

Согласно последним данным от 26 сентября, 2026, канал показывает стабильную активность. За последние 30 дней изменение числа участников составило -112, а за последние 24 часа — -6, при этом общий охват остаётся высоким.

  • Статус верификации: Не верифицирован
  • Уровень вовлечённости (ER): Средний показатель вовлечённости аудитории составляет 3.64%. В первые 24 часа после публикации контент обычно набирает 1.54% реакций от общего числа подписчиков.
  • Охват публикаций: В среднем каждый пост получает 514 просмотров. В течение первых суток публикация набирает 218 просмотров.
  • Реакции и взаимодействия: Аудитория активно поддерживает контент: среднее количество реакций на один пост — 2.
  • Тематические интересы: Контент сосредоточен на ключевых темах, таких как placement, gaurntee, suree, capgemini, infosy.

📝 Описание и контентная политика

Автор описывает ресурс как площадку для выражения субъективного мнения:
“🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...”

Благодаря высокой частоте обновлений (последние данные получены 27 сентября, 2026) канал поддерживает актуальность и высокий уровень охвата публикаций. Аналитика показывает, что аудитория активно взаимодействует с контентом, что делает его важной точкой влияния в категории Образование.

14 128
Подписчики
-624 часа
-127 дней
-11230 дней
Архив постов
import java.util.*; public class DesertPathfinder { static class Cell implements Comparable<Cell> { int row, col, waterCost; Cell(int row, int col, int waterCost) { this.row = row; this.col = col; this.waterCost = waterCost; } @Override public int compareTo(Cell other) { return Integer.compare(this.waterCost, other.waterCost); } } public static int calculateMinWater(char[][] grid, int gridSize) { int[] rowOffsets = {-1, 1, 0, 0}; int[] colOffsets = {0, 0, -1, 1}; int[][] waterUsage = new int[gridSize][gridSize]; boolean[][] isVisited = new boolean[gridSize][gridSize]; for (int[] row : waterUsage) { Arrays.fill(row, Integer.MAX_VALUE); } int startRow = -1, startCol = -1, endRow = -1, endCol = -1; for (int row = 0; row < gridSize; row++) { for (int col = 0; col < gridSize; col++) { if (grid[row][col] == 'S') { startRow = row; startCol = col; } else if (grid[row][col] == 'E') { endRow = row; endCol = col; } } } PriorityQueue<Cell> priorityQueue = new PriorityQueue<>(); priorityQueue.offer(new Cell(startRow, startCol, 0)); waterUsage[startRow][startCol] = 0; while (!priorityQueue.isEmpty()) { Cell current = priorityQueue.poll(); int currentRow = current.row; int currentCol = current.col; if (isVisited[currentRow][currentCol]) { continue; } isVisited[currentRow][currentCol] = true; if (currentRow == endRow && currentCol == endCol) { return waterUsage[currentRow][currentCol]; } for (int i = 0; i < 4; i++) { int nextRow = currentRow + rowOffsets[i]; int nextCol = currentCol + colOffsets[i]; if (nextRow >= 0 && nextCol >= 0 && nextRow < gridSize && nextCol < gridSize && grid[nextRow][nextCol] != 'M' && !isVisited[nextRow][nextCol]) { int newCost = waterUsage[currentRow][currentCol] + (grid[currentRow][currentCol] == 'T' && grid[nextRow][nextCol] == 'T' ? 0 : 1); if (newCost < waterUsage[nextRow][nextCol]) { waterUsage[nextRow][nextCol] = newCost; priorityQueue.offer(new Cell(nextRow, nextCol, newCost)); } } } } return -1; } public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int gridSize = scanner.nextInt(); scanner.nextLine(); char[][] grid = new char[gridSize][gridSize]; for (int row = 0; row < gridSize; row++) { String[] elements = scanner.nextLine().split(" "); for (int col = 0; col < gridSize; col++) { grid[row][col] = elements[col].charAt(0); } } int result = calculateMinWater(grid, gridSize); System.out.print(result); scanner.close(); } } Desert queen 👑👑 https://t.me/codeing_are

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#include <iostream> #include <vector> #include <set> #include <cmath> #include <map> #include <algorithm> using namespace std; polygon using the Shoelace Theorem int calculateArea(const vector<pair<int, int>>& polygon) { int n = polygon.size(); int area = 0; for (int i = 0; i < n; i++) { int j = (i + 1) % n; area += polygon[i].first * polygon[j].second; area -= polygon[j].first * polygon[i].second; } return abs(area) / 2; } are connected bool areConnected(pair<int, int> a, pair<int, int> b, pair<int, int>& p1, pair<int, int>& p2) { return (p1 == a && p2 == b) || (p1 == b && p2 == a); } int main() { int N; cin >> N; vector<pair<int, int>> coordinates; vector<vector<pair<int, int>>> segments(N); set<pair<int, int>> points; store them as pairs for (int i = 0; i < N; i++) { int x1, y1, x2, y2; cin >> x1 >> y1 >> x2 >> y2; coordinates.push_back({x1, y1}); coordinates.push_back({x2, y2}); points.insert({x1, y1}); points.insert({x2, y2}); } vector<pair<int, int>> polygon; int maxArea = 0; to form polygons for (auto p1 = points.begin(); p1 != points.end(); ++p1) { for (auto p2 = next(p1); p2 != points.end(); ++p2) { polygon.push_back(*p1); polygon.push_back(*p2); maxArea = max(maxArea, calculateArea(polygon)); } } cout << maxArea << endl; return 0; } maximum area

#include <iostream> #include <unordered_map> #include <unordered_set> #include <queue> #include <sstream> #include <vector> using namespace std; unordered_map<string, int> calculateLevels(unordered_map<string, vector<string>>& graph, const string& root) { unordered_map<string, int> levels; queue<pair<string, int>> q; q.push(make_pair(root, 1)); while (!q.empty()) { pair<string, int> current = q.front(); q.pop(); string node = current.first; int level = current.second; levels[node] = level; for (const string& child : graph[node]) { q.push(make_pair(child, level + 1)); } } return levels; } int main() { int n; cin >> n; unordered_map<string, vector<string>> graph; unordered_set<string> children; unordered_set<string> nodes; for (int i = 0; i < n; ++i) { string parent, child; cin >> parent >> child; graph[parent].push_back(child); children.insert(child); nodes.insert(parent); nodes.insert(child); } string root; for (const string& node : nodes) { if (children.find(node) == children.end()) { root = node; break; } } unordered_map<string, int> levels = calculateLevels(graph, root); cin.ignore(); string inputLine, word; getline(cin, inputLine); stringstream ss(inputLine); int totalValue = 0; while (ss >> word) { if (levels.find(word) != levels.end()) { totalValue += levels[word]; } else { totalValue += -1; } } cout << totalValue << endl; return 0; } String Puzzle Done ✅

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from collections import deque def count_infected_neighbors(board, x, y): size = len(board) infected_count = 0 for dx in [-1, 0, 1]: for dy in [-1, 0, 1]: if dx == 0 and dy == 0: continue nx, ny = x + dx, y + dy if 0 <= nx < size and 0 <= ny < size and board[nx][ny] == 1: infected_count += 1 return infected_count def plague_simulation(board): size = len(board) new_board = [row[:] for row in board] for x in range(size): for y in range(size): infected_count = count_infected_neighbors(board, x, y) if board[x][y] == 0 and infected_count == 3: new_board[x][y] = 1 elif board[x][y] == 1 and (infected_count < 2 or infected_count > 3): new_board[x][y] = 0 return new_board def find_path(grid_size, initial_board): board = [[1 if cell == '1' else 0 for cell in row] for row in initial_board] start_x, start_y, end_x, end_y = -1, -1, -1, -1 for x in range(grid_size): for y in range(grid_size): if initial_board[x][y] == 's': start_x, start_y = x, y board[x][y] = 0 if initial_board[x][y] == 'd': end_x, end_y = x, y board[x][y] = 0 queue = deque([(start_x, start_y, board, 0)]) visited_states = set() while queue: x, y, current_board, days = queue.popleft() if x == end_x and y == end_y: return days state = (x, y, tuple(map(tuple, current_board))) if state in visited_states: continue visited_states.add(state) next_board = plague_simulation(current_board) for dx, dy in [(0, 0), (-1, 0), (1, 0), (0, -1), (0, 1)]: nx, ny = x + dx, y + dy if 0 <= nx < grid_size and 0 <= ny < grid_size and next_board[nx][ny] == 0: queue.append((nx, ny, next_board, days + 1)) return -1 if name == "main": n = int(input()) grid = [input().strip() for _ in range(n)] print(find_path(n, grid) + 1) Plague 2050 ✅✅ Full passed✅✅

Full accepted Please shared my group everyone ✅✅ https://t.me/codeing_are

def rotate_layer(layer, positions, direction, odd_layer): n = len(layer) rotated = [None] * n if direction == "clockwise": for i in range(n): rotated[(i + positions) % n] = layer[i] else: # counterclockwise for i in range(n): rotated[(i - positions) % n] = layer[i] for i in range(n): if odd_layer: rotated[i] = chr(((ord(rotated[i]) - ord('A') - 1) % 26) + ord('A')) else: rotated[i] = chr(((ord(rotated[i]) - ord('A') + 1) % 26) + ord('A')) return rotated def apply_query(matrix, row, col, size): layers = [] for layer in range(size // 2): current_layer = [] for j in range(col + layer, col + size - layer): current_layer.append(matrix[row + layer][j]) for i in range(row + layer + 1, row + size - layer - 1): current_layer.append(matrix[i][col + size - layer - 1]) for j in range(col + size - layer - 1, col + layer - 1, -1): current_layer.append(matrix[row + size - layer - 1][j]) for i in range(row + size - layer - 2, row + layer, -1): current_layer.append(matrix[i][col + layer]) layers.append(current_layer) for layer_idx, layer in enumerate(layers): odd_layer = (layer_idx + 1) % 2 == 1 direction = "counterclockwise" if odd_layer else "clockwise" positions = layer_idx + 1 rotated_layer = rotate_layer(layer, positions, direction, odd_layer) idx = 0 for j in range(col + layer_idx, col + size - layer_idx): matrix[row + layer_idx][j] = rotated_layer[idx] idx += 1 for i in range(row + layer_idx + 1, row + size - layer_idx - 1): matrix[i][col + size - layer_idx - 1] = rotated_layer[idx] idx += 1 for j in range(col + size - layer_idx - 1, col + layer_idx - 1, -1): matrix[row + size - layer_idx - 1][j] = rotated_layer[idx] idx += 1 for i in range(row + size - layer_idx - 2, row + layer_idx, -1): matrix[i][col + layer_idx] = rotated_layer[idx] idx += 1 def process_matrix(n, matrix, queries): for row, col, size in queries: apply_query(matrix, row, col, size) result = ''.join(''.join(row) for row in matrix) return result n = int(input()) matrix = [list(input().strip().split()) for _ in range(n)] q = int(input().strip()) queries = [tuple(map(int, input().strip().split())) for _ in range(q)] result = process_matrix(n, matrix, queries) print(result, end="") Matrix rotation

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def min_cost_to_form_string(substrings, main_string): inf = float('inf') dp = [inf] * (len(main_string) + 1) dp[0] = 0 # Cost to form an empty string is 0 substrings with their costs substring_cost = {} for substring, cost in substrings: substring_cost[substring] = cost for i in range(1, len(main_string) + 1): for j in range(i): sub = main_string[j:i] # Get the substring from j to i if sub in substring_cost:ue dp[i] = min(dp[i], dp[j] + substring_cost[sub]) dp[len(main_string)] if dp[len(main_string)] == inf: return "Impossible" else: return dp[len(main_string)] if name == "main": N = int(input()) substrings = [] for _ in range(N): line = input().split() substrings.append((line[0], int(line[1]))) # Append tuple (substring, cost) main_string = input().strip() result = min_cost_to_form_string(substrings, main_string) print(result) Form the string

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