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MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

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إظهار المزيد

📈 نظرة تحليلية على قناة تيليجرام MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

تُعد قناة MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer (@coding_are) في القطاع اللغوي الإنكليزية لاعباً نشطاً. يضم المجتمع حالياً 13 236 مشتركاً، محتلاً المرتبة 15 345 في فئة التعليم والمرتبة 32 011 في منطقة الهند.

📊 مؤشرات الجمهور والحراك

منذ تأسيسه في невідомо، حقق المشروع نمواً سريعاً وجمع 13 236 مشتركاً.

بحسب آخر البيانات بتاريخ 19 يونيو, 2026، تحافظ القناة على نشاط مستقر. خلال آخر 30 يوماً تغيّر عدد الأعضاء بمقدار -137، وفي آخر 24 ساعة بمقدار -4، مع بقاء الوصول العام مرتفعاً.

  • حالة التحقق: غير موثّقة
  • معدل التفاعل (ER): يبلغ متوسط تفاعل الجمهور 2.81‎%. وخلال أول 24 ساعة من النشر يحصد المحتوى عادةً 1.07‎% من ردود الفعل نسبةً إلى إجمالي المشتركين.
  • وصول المنشورات: يحصل كل منشور على متوسط 372 مشاهدة. وخلال اليوم الأول يجمع عادةً 142 مشاهدة.
  • التفاعلات والاستجابة: يتفاعل الجمهور بانتظام؛ متوسط التفاعلات لكل منشور يبلغ 2.
  • الاهتمامات الموضوعية: يركز المحتوى على مواضيع رئيسية مثل placement, gaurntee, suree, capgemini, infosy.

📝 الوصف وسياسة المحتوى

يصف المؤلف القناة بأنها مساحة للتعبير عن الآراء الذاتية:
🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...

بفضل وتيرة التحديث المرتفعة (أحدث البيانات بتاريخ 20 يونيو, 2026) تحافظ القناة على حداثتها ومستوى وصول مرتفع. وتُظهر التحليلات تفاعلاً نشطاً من الجمهور، ما يجعلها نقطة تأثير مهمة ضمن فئة التعليم.

13 236
المشتركون
-424 ساعات
-407 أيام
-13730 أيام
أرشيف المشاركات
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def find_winning_party(input1, input2, input3): party_votes = {} for i in range(input1): party = input2[i] votes = input3[i] if party in party_votes: party_votes[party] += votes else: party_votes[party] = votes max_party = None max_votes = -1 for party in input2: if party_votes[party] > max_votes: max_votes = party_votes[party] max_party = party return f"{max_party} {max_votes}" Function ke according adjust kr lena

def temperatureFluctuation (cls, input1, input2, input3): for t in range(input2): all_green = True for n in range(input1): if
def temperatureFluctuation (cls, input1, input2, input3): for t in range(input2): all_green = True for n in range(input1): if input3[n][t] == 0: all_green = False break if all_green: return t return -1

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MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer - إحصائيات وتحليلات قناة تيليجرام @coding_are