MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

Ir al canal en Telegram

🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

India32 011 Educación15 345...

📈 Análisis del canal de Telegram MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

El canal MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer (@coding_are) en el segmento lingüístico de Inglés es un actor destacado. Actualmente la comunidad reúne a 13 233 suscriptores, ocupando la posición 15 345 en la categoría Educación y el puesto 32 011 en la región India.

📊 Métricas de audiencia y dinámica

Desde su creación el невідомо, el proyecto ha mostrado un crecimiento acelerado, reuniendo a 13 233 suscriptores.

Según los últimos datos del 19 junio, 2026, el canal mantiene una actividad estable. En los últimos 30 días la variación de miembros fue de -137, y en las últimas 24 horas de -4, conservando un alto alcance.

Estado de verificación: No verificado
Tasa de interacción (ER): El promedio de interacción de la audiencia es 2.81%. Durante las primeras 24 horas tras publicar, el contenido suele obtener 1.07% de reacciones respecto al total de suscriptores.
Alcance de las publicaciones: Cada publicación recibe en promedio 372 visualizaciones. En el primer día suele acumular 142 visualizaciones.
Reacciones e interacción: La audiencia responde de forma activa: el promedio de reacciones por publicación es 2.
Intereses temáticos: El contenido se centra en temas clave como placement, gaurntee, suree, capgemini, infosy.

📝 Descripción y política de contenido

El autor describe el recurso como un espacio para expresar opiniones subjetivas:
“🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...”

Gracias a la alta frecuencia de actualizaciones (últimos datos recibidos el 20 junio, 2026), el canal mantiene la vigencia y un amplio alcance. La analítica demuestra que la audiencia interactúa activamente con el contenido, lo que lo convierte en un punto de referencia dentro de la categoría Educación.

13 233

Suscriptores

-424 horas

-407 días

-13730 días

372

Visitas de la publicación

~ 14224 horas

~ 19248 horas

2.81%

Tasa de compromiso

~ 3

Mensajes por día

Ads index

beta

Archivo de publicaciones

13 233

Those who want help in 8 nov Accenture exam ( 10am , 2pm , 6pm ) slot available Any off campus or on campus exam help available, Contact fast and book your slots Contact @srksvk

200% sure clearance grauntee 🔥

Remote access also available all exams

13 233

Hpe exam successfully completed by Remote access to 🔥🔥🔥🔥🔥 2/2 code done with all tests caes passed 🔥🔥🔥 Contact for placement exam @srksvk

13 233

Accenture interview help successfully done by Remote access 🔥🔥🔥🔥🔥🔥 All answers provided on time with 💯 correct answer 🔥🔥🔥 Contact for placement exam @srksvk

13 233

Fidility investment interview help successfully done by Remote access 🔥🔥🔥🔥🔥🔥🔥 All questions answered provide on time with 💯% correct answer 🔥🔥🔥🔥 Contact for placement exam @srksvk

13 233

12:30 pm Accenture on campus exam successfully completed by Remote access 🔥🔥🔥🔥🔥🔥 All Eleminted rounds Cleard 🎉🔥🎉🔥🎉🔥🎉 2/2 code passed with all tests caes passed 🔥🔥🔥 Contact for placement exam @srksvk

13 233

Accenture on campus exam help available Contact fast and book your slots Contact @srksvk..

200% sure clearance grauntee 🔥

Remote access available

13 233

Accenture on campus exam help available Contact fast and book your slots Contact @srksvk..

200% sure clearance grauntee 🔥

Remote access available

13 233

Goldman Sachs exam successfully completed by Remote access 🔥🔥🔥🔥 All mcq with code full passed with all tests caes passed 🔥 Contact for placement exam @srksvk

13 233

Amazon exam successfully completed by Remote access 🔥🔥🔥🔥🔥 2/2 code down with all tests caes passed 🔥🔥🔥 Contact for placement exam @srksvk

13 233

"This Diwali, may you conquer every obstacle in your path to success. May your journey be as vibrant and full of promise as the colors of Diwali. Happy Diwali, dear student

13 233

Got placed inmobi company 🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥 Congratulations brooo🔥🔥🔥🔥 Contact for placement exam @srksvk

13 233

Walmart exam successfully completed by Remote access 🔥🔥🔥🔥🔥🔥 2/2 code done with all tets caes passed 🔥🔥🔥🔥 Contact for placement exam @srksvk

13 233

Walmart exam help available Contact fast and book your slots Contact @srksvk 200% sure clearance grauntee

13 233

Walmart exam successfully completed by Remote access 🔥🔥🔥🔥🔥🔥 2/2 code done with all tets caes passed 🔥🔥🔥🔥 Contact for placement exam @srksvk

13 233

Amazon exam successfully completed by Remote access 🔥🔥🔥🔥🔥 2/2 code down with all tests caes passed 🔥🔥🔥 Contact for placement exam @srksvk

13 233

Those who want help in Accenture exam , Walmart, Amazon's exam , Any off campus or on campus exam help available, Contact fast and book your slots Contact @srksvk 200% sure clearance grauntee 🔥 Remote access also available all exams

13 233

Those who want help in Accenture exam , Walmart, Amazon's exam , Any off campus or on campus exam help available, Contact fast and book your slots Contact @srksvk

200% sure clearance grauntee 🔥

Remote access also available all exams

13 233

def find_winning_party(input1, input2, input3): party_votes = {} for i in range(input1): party = input2[i] votes = input3[i] if party in party_votes: party_votes[party] += votes else: party_votes[party] = votes max_party = None max_votes = -1 for party in input2: if party_votes[party] > max_votes: max_votes = party_votes[party] max_party = party return f"{max_party} {max_votes}" Function ke according adjust kr lena

13 233

def temperatureFluctuation (cls, input1, input2, input3): for t in range(input2): all_green = True for n in range(input1): if input3[n][t] == 0: all_green = False break if all_green: return t return -1

13 233

Guy's share the group ✅