OSSSC / OSSC MATH AND REASONING

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𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS Join our YouTube Channel: https://shorturl.at/Ulwjw 🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY 🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH

Red:ଓଡ଼ିଆ ବ୍ୟାକରଣ India33 539 Educación17 160...

📈 Análisis del canal de Telegram OSSSC / OSSC MATH AND REASONING

El canal OSSSC / OSSC MATH AND REASONING (@pinnacle_math_reasoning) en el segmento lingüístico de Inglés es un actor destacado. Actualmente la comunidad reúne a 11 513 suscriptores, ocupando la posición 17 160 en la categoría Educación y el puesto 33 539 en la región India.

📊 Métricas de audiencia y dinámica

Desde su creación el невідомо, el proyecto ha mostrado un crecimiento acelerado, reuniendo a 11 513 suscriptores.

Según los últimos datos del 27 septiembre, 2026, el canal mantiene una actividad estable. En los últimos 30 días la variación de miembros fue de 166, y en las últimas 24 horas de -6, conservando un alto alcance.

Estado de verificación: No verificado
Tasa de interacción (ER): El promedio de interacción de la audiencia es 18.24%. Durante las primeras 24 horas tras publicar, el contenido suele obtener 4.61% de reacciones respecto al total de suscriptores.
Alcance de las publicaciones: Cada publicación recibe en promedio 2 100 visualizaciones. En el primer día suele acumular 531 visualizaciones.
Reacciones e interacción: La audiencia responde de forma activa: el promedio de reacciones por publicación es 2.
Intereses temáticos: El contenido se centra en temas clave como ʜᴇʀᴇ, cgle, cgl, mcqs, mcq.

📝 Descripción y política de contenido

El autor describe el recurso como un espacio para expresar opiniones subjetivas:
“𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS Join our YouTube Channel: https://shorturl.at/Ulwjw 🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY 🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH”

Gracias a la alta frecuencia de actualizaciones (últimos datos recibidos el 28 septiembre, 2026), el canal mantiene la vigencia y un amplio alcance. La analítica demuestra que la audiencia interactúa activamente con el contenido, lo que lo convierte en un punto de referencia dentro de la categoría Educación.

11 513

Suscriptores

-624 horas

+157 días

+16630 días

2 100

Visitas de la publicación

~ 53124 horas

~ 82548 horas

18.24%

Tasa de compromiso

~ 1

Mensajes por día

Ads index

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Archivo de publicaciones

11 510

𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤThe average of 11 results is 182. If the average of first 6 results is 199 and 7 that of the last 6 results is 161, then what will be the 6th result ?

Anonymous voting

11 510

𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤFind the least number which when divided by 4, 5, 6, 7 and 8, leaves remainder 3, 4, 5, 6 and 7. ?

Anonymous voting

11 510

P alone can do a work in 10 days, Q alone can do the same work in 15 days R alone can do the same work in 12 days. They jointly complete the work and earn Rs. 3000 Concept used:👇 Profit is shared as per their efficiency ratio. Calculation: Their efficiency ratio will be, 1/10:1/15:1/12=6:4;5 The share of R is 🙂3000 x 5/15 = Rs 1000 .. The correct option is 1

11 510

𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ P alone can complete the work in 5 days, Q alone can do same work in 6 days and R alone can do the same work in 12 days. They jointly complete the work and earn Rs 5400. What is the share of R ?

Anonymous voting

11 510

5 years ago, ages of mohit and rohan = 5:6 7 years after, ages of mohit and rohan = 11:12 Calculation: Present age of mohit = 5x + 5 Present age of rohan = 6x + 5 After 7 years in future, their ages will be 5x + 5 + 7 and 6x + 5 + 7 respectively According to question, (5x + 12) / (6x + 12) = 11/12 60x + 144 = 66x + 132 6x = 12 x = 2 So, the present age of rohan = 6x + 5 = 12 + 5 = 17 years .. The required answer is 17 years

11 510

𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ 5 years ago, the ratio of the ages of Mohit and Rohan was 5: 6. Seven years hence, the ratio of their ages will be 11:12. Find the age of Rohan.

Anonymous voting

11 510

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11 510

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11 510

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11 510

📢Important Notice : Due to the recent ban News on Telegram in India, we will be shifting our study channel and discussion forum to WhatsApp. Please join our new WhatsApp Channel 👇👇 https://whatsapp.com/channel/0029Vah188RFXUuUkPxiMa1u stay updated on study materials, Quizzes,Paid PDFs. live classes, and important announcements.🎓 Thank you for your cooperation and understanding. Best Regards 𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬

11 510

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11 510

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11 510

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11 510

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11 510

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11 510

𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤThe ratio of LCM and HCF of two numbers is 24: 1 and the sum of LCM and HCF is 750, if the first number is 75, find the second number.

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11 510

𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤA candidate who gets 33% marks in an examination fail by 15 marks, but another candidate who gets 38% gets 25 marks more than the passing marks. find the maximum marks of

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11 510

𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤFind the effective discount for the scheme - Buy 5 get 3 free.

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