OSSSC / OSSC MATH AND REASONING
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𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS Join our YouTube Channel: https://shorturl.at/Ulwjw 🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY 🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH
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网络:📈 Telegram 频道 OSSSC / OSSC MATH AND REASONING 的分析概览
频道 OSSSC / OSSC MATH AND REASONING (@pinnacle_math_reasoning) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 11 514 名订阅者，在 教育 类别中位列第 17 145，并在 印度 地区排名第 33 527 位。
📊 受众指标与增长动态
自 невідомо 创建以来，项目保持高速增长，吸引了 11 514 名订阅者。
根据 27 九月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 166，过去 24 小时变化为 -6，整体触达仍然可观。
- 认证状态： 未认证
- 互动率 (ER)： 平均受众互动率为 18.24%。内容发布后 24 小时内通常能获得 4.61% 的反应，占订阅者总量。
- 帖子覆盖： 每篇帖子平均可获得 2 100 次浏览，首日通常累积 531 次浏览。
- 互动与反馈： 受众积极参与，单帖平均反应数为 2。
- 主题关注点： 内容集中在 ʜᴇʀᴇ, cgle, cgl, mcqs, mcq 等核心主题上。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台：
“𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS
Join our YouTube Channel: https://shorturl.at/Ulwjw
🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY
🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH”
凭借高频更新（最新数据采集于 28 九月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为 教育 类别中的关键影响点。
11 514
订阅者
-624 小时
+157 天
+16630 天
帖子存档
𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤThe average of 11 results is 182. If the average of first 6 results is 199 and 7 that of the last 6 results is 161, then what will be the 6th result ?
𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤFind the least number which when divided by 4, 5, 6, 7 and 8, leaves remainder 3, 4, 5, 6 and 7. ?
P alone can do a work in 10 days,
Q alone can do the same work in 15 days
R alone can do the same work in 12 days.
They jointly complete the work and earn Rs. 3000
Concept used:👇
Profit is shared as per their efficiency ratio.
Calculation:
Their efficiency ratio will be, 1/10:1/15:1/12=6:4;5
The share of R is
🙂3000 x 5/15 = Rs 1000
.. The correct option is 1
𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬
ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ
P alone can complete the work in 5 days, Q alone can do same work in 6 days and R alone can do the same work in 12 days. They jointly complete the work and earn Rs 5400. What is the share of R ?
5 years ago, ages of mohit and rohan = 5:6
7 years after, ages of mohit and rohan = 11:12
Calculation:
Present age of mohit = 5x + 5
Present age of rohan = 6x + 5
After 7 years in future, their ages will be 5x + 5 + 7 and 6x + 5 + 7 respectively
According to question,
(5x + 12) / (6x + 12) = 11/12
60x + 144 = 66x + 132
6x = 12
x = 2
So, the present age of rohan = 6x + 5 = 12 + 5 = 17 years
.. The required answer is 17 years
𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬
ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ
5 years ago, the ratio of the ages of Mohit and Rohan was 5: 6. Seven years hence, the ratio of their ages will be 11:12. Find the age of Rohan.
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𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬
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𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤThe ratio of LCM and HCF of two numbers is 24: 1 and the sum of LCM and HCF is 750, if the first number is 75, find the second number.
𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤA candidate who gets 33% marks in an examination fail by 15 marks, but another candidate who gets 38% gets 25 marks more than the passing marks. find the maximum marks of
𝗢𝗗𝗜𝗦𝗛𝗔 𝗩𝗜𝗥𝗧𝗨𝗔𝗟 𝗟𝗜𝗕𝗥𝗔𝗥𝗬 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤFind the effective discount for the scheme - Buy 5 get 3 free.
