Data Analytics
Perfect channel to learn Data Analytics Learn SQL, Python, Alteryx, Tableau, Power BI and many more For Promotions: @coderfun @love_data
Mostrar más📈 Análisis del canal de Telegram Data Analytics
El canal Data Analytics (@sqlspecialist) en el segmento lingüístico de Inglés es un actor destacado. Actualmente la comunidad reúne a 109 605 suscriptores, ocupando la posición 1 124 en la categoría Tecnologías y Aplicaciones y el puesto 2 373 en la región India.
📊 Métricas de audiencia y dinámica
Desde su creación el невідомо, el proyecto ha mostrado un crecimiento acelerado, reuniendo a 109 605 suscriptores.
Según los últimos datos del 19 junio, 2026, el canal mantiene una actividad estable. En los últimos 30 días la variación de miembros fue de 624, y en las últimas 24 horas de -15, conservando un alto alcance.
- Estado de verificación: No verificado
- Tasa de interacción (ER): El promedio de interacción de la audiencia es 3.26%. Durante las primeras 24 horas tras publicar, el contenido suele obtener 1.27% de reacciones respecto al total de suscriptores.
- Alcance de las publicaciones: Cada publicación recibe en promedio 3 575 visualizaciones. En el primer día suele acumular 1 388 visualizaciones.
- Reacciones e interacción: La audiencia responde de forma activa: el promedio de reacciones por publicación es 9.
- Intereses temáticos: El contenido se centra en temas clave como row, sql, analytic, analyst, visualization.
📝 Descripción y política de contenido
El autor describe el recurso como un espacio para expresar opiniones subjetivas:
“Perfect channel to learn Data Analytics
Learn SQL, Python, Alteryx, Tableau, Power BI and many more
For Promotions: @coderfun @love_data”
Gracias a la alta frecuencia de actualizaciones (últimos datos recibidos el 20 junio, 2026), el canal mantiene la vigencia y un amplio alcance. La analítica demuestra que la audiencia interactúa activamente con el contenido, lo que lo convierte en un punto de referencia dentro de la categoría Tecnologías y Aplicaciones.
SELECT MAX(salary) AS SecondHighest
FROM Employees
WHERE salary < (SELECT MAX(salary) FROM Employees);
2. Find employees without assigned managers
SELECT * FROM Employees
WHERE manager_id IS NULL;
3. Retrieve departments with more than 5 employees
SELECT department_id, COUNT(*) AS employee_count
FROM Employees
GROUP BY department_id
HAVING COUNT(*) > 5;
4. List customers who made no orders
SELECT c.name
FROM Customers c
LEFT JOIN Orders o ON c.id = o.customer_id
WHERE o.id IS NULL;
5. Find the top 3 highest-paid employees
SELECT * FROM Employees
ORDER BY salary DESC
LIMIT 3;
6. Display total sales for each product
SELECT product, SUM(amount) AS total_sales
FROM Sales
GROUP BY product;
7. Get employee names starting with 'A' and ending with 'n'
SELECT name FROM Employees
WHERE name LIKE 'A%n';
8. Show employees who joined in the last 30 days
SELECT * FROM Employees
WHERE join_date >= CURRENT_DATE - INTERVAL 30 DAY;
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——————————SELECT email, COUNT(*)
FROM customers
GROUP BY email
HAVING COUNT(*) > 1;
2. Find the Second Highest Salary
SELECT MAX(salary)
FROM employees
WHERE salary < (SELECT MAX(salary) FROM employees);
3. Customers with More Than 3 Orders in Last 30 Days
SELECT customer_id
FROM orders
WHERE order_date >= CURRENT_DATE - INTERVAL '30 days'
GROUP BY customer_id
HAVING COUNT(*) > 3;
4. Calculate Monthly Revenue
SELECT DATE_TRUNC('month', sale_date) AS month,
SUM(amount) AS monthly_revenue
FROM sales
GROUP BY month
ORDER BY month;
5. Find Employees Without Managers
SELECT *
FROM employees
WHERE manager_id IS NULL;
6. Join Two Tables and Filter by Amount
SELECT o.order_id, c.name, o.amount
FROM orders o
JOIN customers c ON o.customer_id = c.customer_id
WHERE o.amount > 100;
7. Use CASE for Conditional Logic
SELECT name,
CASE
WHEN score >= 90 THEN 'Excellent'
WHEN score >= 75 THEN 'Good'
ELSE 'Needs Improvement'
END AS rating
FROM students;
8. Find Top-Selling Products
SELECT product_id, SUM(quantity) AS total_sold
FROM sales
GROUP BY product_id
ORDER BY total_sold DESC
LIMIT 5;
9. Identify Inactive Users
SELECT user_id
FROM users
WHERE last_login < CURRENT_DATE - INTERVAL '90 days';
🔟 Calculate Conversion Rate
SELECT COUNT(*) FILTER (WHERE status = 'converted') * 100.0 / COUNT(*) AS conversion_rate
FROM leads;
💡 Pro Tip: Practice these with real datasets and explain your logic clearly in interviews.
💬 Tap ❤️ if this helped you prep smarter!
——————————SELECT name, age FROM employees;
2️⃣ FROM – Specify Table
Tells SQL where to pull the data from.
SELECT * FROM sales_data;
3️⃣ WHERE – Filter Data
Applies conditions to filter rows.
SELECT * FROM customers WHERE city = 'Delhi';
4️⃣ GROUP BY – Aggregate by Categories
Groups rows based on one or more columns for aggregation.
SELECT department, COUNT(*) FROM employees GROUP BY department;
5️⃣ HAVING – Filter After Grouping
Filters groups after GROUP BY (unlike WHERE, which filters rows).
SELECT category, SUM(sales)
FROM orders
GROUP BY category
HAVING SUM(sales) > 10000;
6️⃣ ORDER BY – Sort Results
Sorts the result set in ascending or descending order.
SELECT name, salary FROM employees ORDER BY salary DESC;
7️⃣ COUNT() – Count Records
Counts number of rows or non-null values.
SELECT COUNT(*) FROM products;
8️⃣ SUM() – Total Values
Calculates the sum of numeric values.
SELECT SUM(amount) FROM transactions;
9️⃣ AVG() – Average Values
Returns the average of numeric values.
SELECT AVG(price) FROM items;
🔟 JOIN – Combine Tables
Combines rows from multiple tables based on related columns.
SELECT a.name, b.order_date
FROM customers a
JOIN orders b ON a.id = b.customer_id;
Whether you're preparing for interviews or exploring large datasets—these are your go-to tools.
SQL Resources: https://whatsapp.com/channel/0029VanC5rODzgT6TiTGoa1v
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