Data Analytics
Perfect channel to learn Data Analytics Learn SQL, Python, Alteryx, Tableau, Power BI and many more For Promotions: @coderfun @love_data
Show more📈 Analytical overview of Telegram channel Data Analytics
Channel Data Analytics (@sqlspecialist) in the English language segment is an active participant. Currently, the community unites 109 605 subscribers, ranking 1 124 in the Technologies & Applications category and 2 373 in the India region.
📊 Audience metrics and dynamics
Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 109 605 subscribers.
According to the latest data from 19 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by 624 over the last 30 days and by -15 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 3.26%. Within the first 24 hours after publication, content typically collects 1.27% reactions from the total number of subscribers.
- Post reach: On average, each post receives 3 575 views. Within the first day, a publication typically gains 1 388 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 9.
- Thematic interests: Content is focused on key topics such as row, sql, analytic, analyst, visualization.
📝 Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
“Perfect channel to learn Data Analytics
Learn SQL, Python, Alteryx, Tableau, Power BI and many more
For Promotions: @coderfun @love_data”
Thanks to the high frequency of updates (latest data received on 20 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.
SELECT MAX(salary) AS SecondHighest
FROM Employees
WHERE salary < (SELECT MAX(salary) FROM Employees);
2. Find employees without assigned managers
SELECT * FROM Employees
WHERE manager_id IS NULL;
3. Retrieve departments with more than 5 employees
SELECT department_id, COUNT(*) AS employee_count
FROM Employees
GROUP BY department_id
HAVING COUNT(*) > 5;
4. List customers who made no orders
SELECT c.name
FROM Customers c
LEFT JOIN Orders o ON c.id = o.customer_id
WHERE o.id IS NULL;
5. Find the top 3 highest-paid employees
SELECT * FROM Employees
ORDER BY salary DESC
LIMIT 3;
6. Display total sales for each product
SELECT product, SUM(amount) AS total_sales
FROM Sales
GROUP BY product;
7. Get employee names starting with 'A' and ending with 'n'
SELECT name FROM Employees
WHERE name LIKE 'A%n';
8. Show employees who joined in the last 30 days
SELECT * FROM Employees
WHERE join_date >= CURRENT_DATE - INTERVAL 30 DAY;
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——————————SELECT email, COUNT(*)
FROM customers
GROUP BY email
HAVING COUNT(*) > 1;
2. Find the Second Highest Salary
SELECT MAX(salary)
FROM employees
WHERE salary < (SELECT MAX(salary) FROM employees);
3. Customers with More Than 3 Orders in Last 30 Days
SELECT customer_id
FROM orders
WHERE order_date >= CURRENT_DATE - INTERVAL '30 days'
GROUP BY customer_id
HAVING COUNT(*) > 3;
4. Calculate Monthly Revenue
SELECT DATE_TRUNC('month', sale_date) AS month,
SUM(amount) AS monthly_revenue
FROM sales
GROUP BY month
ORDER BY month;
5. Find Employees Without Managers
SELECT *
FROM employees
WHERE manager_id IS NULL;
6. Join Two Tables and Filter by Amount
SELECT o.order_id, c.name, o.amount
FROM orders o
JOIN customers c ON o.customer_id = c.customer_id
WHERE o.amount > 100;
7. Use CASE for Conditional Logic
SELECT name,
CASE
WHEN score >= 90 THEN 'Excellent'
WHEN score >= 75 THEN 'Good'
ELSE 'Needs Improvement'
END AS rating
FROM students;
8. Find Top-Selling Products
SELECT product_id, SUM(quantity) AS total_sold
FROM sales
GROUP BY product_id
ORDER BY total_sold DESC
LIMIT 5;
9. Identify Inactive Users
SELECT user_id
FROM users
WHERE last_login < CURRENT_DATE - INTERVAL '90 days';
🔟 Calculate Conversion Rate
SELECT COUNT(*) FILTER (WHERE status = 'converted') * 100.0 / COUNT(*) AS conversion_rate
FROM leads;
💡 Pro Tip: Practice these with real datasets and explain your logic clearly in interviews.
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——————————SELECT name, age FROM employees;
2️⃣ FROM – Specify Table
Tells SQL where to pull the data from.
SELECT * FROM sales_data;
3️⃣ WHERE – Filter Data
Applies conditions to filter rows.
SELECT * FROM customers WHERE city = 'Delhi';
4️⃣ GROUP BY – Aggregate by Categories
Groups rows based on one or more columns for aggregation.
SELECT department, COUNT(*) FROM employees GROUP BY department;
5️⃣ HAVING – Filter After Grouping
Filters groups after GROUP BY (unlike WHERE, which filters rows).
SELECT category, SUM(sales)
FROM orders
GROUP BY category
HAVING SUM(sales) > 10000;
6️⃣ ORDER BY – Sort Results
Sorts the result set in ascending or descending order.
SELECT name, salary FROM employees ORDER BY salary DESC;
7️⃣ COUNT() – Count Records
Counts number of rows or non-null values.
SELECT COUNT(*) FROM products;
8️⃣ SUM() – Total Values
Calculates the sum of numeric values.
SELECT SUM(amount) FROM transactions;
9️⃣ AVG() – Average Values
Returns the average of numeric values.
SELECT AVG(price) FROM items;
🔟 JOIN – Combine Tables
Combines rows from multiple tables based on related columns.
SELECT a.name, b.order_date
FROM customers a
JOIN orders b ON a.id = b.customer_id;
Whether you're preparing for interviews or exploring large datasets—these are your go-to tools.
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