Data Analytics
Perfect channel to learn Data Analytics Learn SQL, Python, Alteryx, Tableau, Power BI and many more For Promotions: @coderfun @love_data
Mostrar más📈 Análisis del canal de Telegram Data Analytics
El canal Data Analytics (@sqlspecialist) en el segmento lingüístico de Inglés es un actor destacado. Actualmente la comunidad reúne a 109 681 suscriptores, ocupando la posición 1 122 en la categoría Tecnologías y Aplicaciones y el puesto 2 340 en la región India.
📊 Métricas de audiencia y dinámica
Desde su creación el невідомо, el proyecto ha mostrado un crecimiento acelerado, reuniendo a 109 681 suscriptores.
Según los últimos datos del 24 junio, 2026, el canal mantiene una actividad estable. En los últimos 30 días la variación de miembros fue de 584, y en las últimas 24 horas de 71, conservando un alto alcance.
- Estado de verificación: No verificado
- Tasa de interacción (ER): El promedio de interacción de la audiencia es 2.76%. Durante las primeras 24 horas tras publicar, el contenido suele obtener 0.68% de reacciones respecto al total de suscriptores.
- Alcance de las publicaciones: Cada publicación recibe en promedio 3 024 visualizaciones. En el primer día suele acumular 743 visualizaciones.
- Reacciones e interacción: La audiencia responde de forma activa: el promedio de reacciones por publicación es 8.
- Intereses temáticos: El contenido se centra en temas clave como row, sql, analytic, analyst, visualization.
📝 Descripción y política de contenido
El autor describe el recurso como un espacio para expresar opiniones subjetivas:
“Perfect channel to learn Data Analytics
Learn SQL, Python, Alteryx, Tableau, Power BI and many more
For Promotions: @coderfun @love_data”
Gracias a la alta frecuencia de actualizaciones (últimos datos recibidos el 25 junio, 2026), el canal mantiene la vigencia y un amplio alcance. La analítica demuestra que la audiencia interactúa activamente con el contenido, lo que lo convierte en un punto de referencia dentro de la categoría Tecnologías y Aplicaciones.
SELECT employee_id, name, COALESCE(salary, 0) AS salary FROM employees;
Here, if salary is NULL, it will be replaced with 0.
Example: Selecting the First Non-NULL Value
SELECT employee_id, COALESCE(phone_number, email, 'No Contact Info') AS contact FROM employees;
This returns phone_number if available; otherwise, it returns email. If both are NULL, it defaults to 'No Contact Info'.
Top 20 SQL Interview Questions
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Hope it helps :)SELECT employee_id, name FROM employees e WHERE EXISTS ( SELECT 1 FROM departments d WHERE d.department_id = e.department_id );
Here, EXISTS checks if a matching department_id exists in the departments table and returns TRUE as soon as it finds a match.
Example of IN:
SELECT employee_id, name FROM employees WHERE department_id IN (SELECT department_id FROM departments);
In this case, IN retrieves all department_id values from the departments table and checks each row in the employees table against this list.
Top 20 SQL Interview Questions
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Hope it helps :)SELECT employee_id, department_id, COUNT(*) FROM employees GROUP BY employee_id, department_id HAVING COUNT(*) > 1;
This retrieves records where the same employee_id and department_id appear more than once.
Removing Duplicates Using ROW_NUMBER():
To delete duplicates while keeping only one occurrence, use ROW_NUMBER():
WITH CTE AS ( SELECT *, ROW_NUMBER() OVER (PARTITION BY employee_id, department_id ORDER BY employee_id) AS row_num FROM employees ) DELETE FROM employees WHERE employee_id IN (SELECT employee_id FROM CTE WHERE row_num > 1);
Alternative: Deleting Using DISTINCT and a Temp Table
If ROW_NUMBER() is not supported, you can create a temporary table:
CREATE TABLE employees_temp AS SELECT DISTINCT * FROM employees; DROP TABLE employees; ALTER TABLE employees_temp RENAME TO employees;
This removes duplicates by keeping only distinct records.
Top 20 SQL Interview Questions
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Hope it helps :)SELECT * FROM employees; -- Fetch all columns from 'employees' table SELECT name, salary FROM employees; -- Fetch specific columns
🔹 WHERE – Filter Data
SELECT * FROM employees WHERE department = 'Sales'; -- Filter by department SELECT * FROM employees WHERE salary > 50000; -- Filter by salary
🔹 ORDER BY – Sort Data
SELECT * FROM employees ORDER BY salary DESC; -- Sort by salary (highest first) SELECT name, hire_date FROM employees ORDER BY hire_date ASC; -- Sort by hire date (oldest first)
🔹 LIMIT – Restrict Number of Results
SELECT * FROM employees LIMIT 5; -- Fetch only 5 rows SELECT * FROM employees WHERE department = 'HR' LIMIT 10; -- Fetch first 10 HR employees
🔹 DISTINCT – Remove Duplicates
SELECT DISTINCT department FROM employees; -- Show unique departments
Mini Task for You: Try to write an SQL query to fetch the top 3 highest-paid employees from an "employees" table.
You can find free SQL Resources here
👇👇
https://t.me/mysqldata
Like this post if you want me to a continue covering all the topics! 👍❤️
Share with credits: https://t.me/sqlspecialist
Hope it helps :)
#sqlSELECT * FROM employees; -- Fetch all columns from 'employees' table SELECT name, salary FROM employees; -- Fetch specific columns
🔹 WHERE – Filter Data
SELECT * FROM employees WHERE department = 'Sales'; -- Filter by department SELECT * FROM employees WHERE salary > 50000; -- Filter by salary
🔹 ORDER BY – Sort Data
SELECT * FROM employees ORDER BY salary DESC; -- Sort by salary (highest first) SELECT name, hire_date FROM employees ORDER BY hire_date ASC; -- Sort by hire date (oldest first)
🔹 LIMIT – Restrict Number of Results
SELECT * FROM employees LIMIT 5; -- Fetch only 5 rows SELECT * FROM employees WHERE department = 'HR' LIMIT 10; -- Fetch first 10 HR employees
🔹 DISTINCT – Remove Duplicates
SELECT DISTINCT department FROM employees; -- Show unique departments
Mini Task for You:
Try to write an SQL query to fetch the top 3 highest-paid employees from an "employees" table.
You can find free SQL Resources here: https://t.me/mysqldata
Like this post if you want me to a continue covering all the topics! 👍❤️
Share with credits: https://t.me/sqlspecialist
Hope it helps :)
#sqlSELECT employee_id, department_id, salary, SUM(salary) OVER (PARTITION BY department_id ORDER BY employee_id) AS running_total FROM employees;
Here, SUM(salary) is calculated for each department separately, but all rows remain in the result.
Example of GROUP BY (Aggregates Data)
SELECT department_id, SUM(salary) FROM employees GROUP BY department_id;
In this case, the result shows only one row per department, removing individual employee details.
Top 20 SQL Interview Questions
Like this post if you want me to continue this SQL Interview Series♥️
Share with credits: https://t.me/sqlspecialist
Hope it helps :)
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