Data Analytics
Perfect channel to learn Data Analytics Learn SQL, Python, Alteryx, Tableau, Power BI and many more For Promotions: @coderfun @love_data
Ko'proq ko'rsatish๐ Telegram kanali Data Analytics analitikasi
Data Analytics (@sqlspecialist) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 109 681 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 1 122-o'rinni va Hindiston mintaqasida 2 340-o'rinni egallagan.
๐ Auditoriya koโrsatkichlari va dinamika
ะฝะตะฒัะดะพะผะพ sanasidan buyon loyiha tez oโsib, 109 681 obunachiga ega boโldi.
24 Iyun, 2026 dagi oxirgi maโlumotlarga koโra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni 584 ga, soโnggi 24 soatda esa 71 ga oโzgardi va umumiy qamrov yuqori darajada qolmoqda.
- Tasdiqlash holati: Tasdiqlanmagan
- Jalb etish (ER): Auditoriya oโrtacha 2.76% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 0.68% ini tashkil etuvchi reaksiyalarni toโplaydi.
- Post qamrovi: Har bir post oโrtacha 3 024 marta koโriladi; birinchi sutkada odatda 743 ta koโrish yigโiladi.
- Reaksiyalar va oโzaro taโsir: Auditoriya faol: har bir postga oโrtacha 8 ta reaksiya keladi.
- Tematik yoโnalishlar: Kontent row, sql, analytic, analyst, visualization kabi asosiy mavzularga jamlangan.
๐ Tavsif va kontent siyosati
Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida taโriflaydi:
โPerfect channel to learn Data Analytics
Learn SQL, Python, Alteryx, Tableau, Power BI and many more
For Promotions: @coderfun @love_dataโ
Yuqori yangilanish chastotasi (oxirgi maโlumot 25 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli boโlib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim taโsir nuqtasiga aylantirishini koโrsatadi.
SELECT employee_id, name, COALESCE(salary, 0) AS salary FROM employees;
Here, if salary is NULL, it will be replaced with 0.
Example: Selecting the First Non-NULL Value
SELECT employee_id, COALESCE(phone_number, email, 'No Contact Info') AS contact FROM employees;
This returns phone_number if available; otherwise, it returns email. If both are NULL, it defaults to 'No Contact Info'.
Top 20 SQL Interview Questions
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Hope it helps :)SELECT employee_id, name FROM employees e WHERE EXISTS ( SELECT 1 FROM departments d WHERE d.department_id = e.department_id );
Here, EXISTS checks if a matching department_id exists in the departments table and returns TRUE as soon as it finds a match.
Example of IN:
SELECT employee_id, name FROM employees WHERE department_id IN (SELECT department_id FROM departments);
In this case, IN retrieves all department_id values from the departments table and checks each row in the employees table against this list.
Top 20 SQL Interview Questions
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Hope it helps :)SELECT employee_id, department_id, COUNT(*) FROM employees GROUP BY employee_id, department_id HAVING COUNT(*) > 1;
This retrieves records where the same employee_id and department_id appear more than once.
Removing Duplicates Using ROW_NUMBER():
To delete duplicates while keeping only one occurrence, use ROW_NUMBER():
WITH CTE AS ( SELECT *, ROW_NUMBER() OVER (PARTITION BY employee_id, department_id ORDER BY employee_id) AS row_num FROM employees ) DELETE FROM employees WHERE employee_id IN (SELECT employee_id FROM CTE WHERE row_num > 1);
Alternative: Deleting Using DISTINCT and a Temp Table
If ROW_NUMBER() is not supported, you can create a temporary table:
CREATE TABLE employees_temp AS SELECT DISTINCT * FROM employees; DROP TABLE employees; ALTER TABLE employees_temp RENAME TO employees;
This removes duplicates by keeping only distinct records.
Top 20 SQL Interview Questions
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Hope it helps :)SELECT * FROM employees; -- Fetch all columns from 'employees' table SELECT name, salary FROM employees; -- Fetch specific columns
๐น WHERE โ Filter Data
SELECT * FROM employees WHERE department = 'Sales'; -- Filter by department SELECT * FROM employees WHERE salary > 50000; -- Filter by salary
๐น ORDER BY โ Sort Data
SELECT * FROM employees ORDER BY salary DESC; -- Sort by salary (highest first) SELECT name, hire_date FROM employees ORDER BY hire_date ASC; -- Sort by hire date (oldest first)
๐น LIMIT โ Restrict Number of Results
SELECT * FROM employees LIMIT 5; -- Fetch only 5 rows SELECT * FROM employees WHERE department = 'HR' LIMIT 10; -- Fetch first 10 HR employees
๐น DISTINCT โ Remove Duplicates
SELECT DISTINCT department FROM employees; -- Show unique departments
Mini Task for You: Try to write an SQL query to fetch the top 3 highest-paid employees from an "employees" table.
You can find free SQL Resources here
๐๐
https://t.me/mysqldata
Like this post if you want me to a continue covering all the topics! ๐โค๏ธ
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Hope it helps :)
#sqlSELECT * FROM employees; -- Fetch all columns from 'employees' table SELECT name, salary FROM employees; -- Fetch specific columns
๐น WHERE โ Filter Data
SELECT * FROM employees WHERE department = 'Sales'; -- Filter by department SELECT * FROM employees WHERE salary > 50000; -- Filter by salary
๐น ORDER BY โ Sort Data
SELECT * FROM employees ORDER BY salary DESC; -- Sort by salary (highest first) SELECT name, hire_date FROM employees ORDER BY hire_date ASC; -- Sort by hire date (oldest first)
๐น LIMIT โ Restrict Number of Results
SELECT * FROM employees LIMIT 5; -- Fetch only 5 rows SELECT * FROM employees WHERE department = 'HR' LIMIT 10; -- Fetch first 10 HR employees
๐น DISTINCT โ Remove Duplicates
SELECT DISTINCT department FROM employees; -- Show unique departments
Mini Task for You:
Try to write an SQL query to fetch the top 3 highest-paid employees from an "employees" table.
You can find free SQL Resources here: https://t.me/mysqldata
Like this post if you want me to a continue covering all the topics! ๐โค๏ธ
Share with credits: https://t.me/sqlspecialist
Hope it helps :)
#sqlSELECT employee_id, department_id, salary, SUM(salary) OVER (PARTITION BY department_id ORDER BY employee_id) AS running_total FROM employees;
Here, SUM(salary) is calculated for each department separately, but all rows remain in the result.
Example of GROUP BY (Aggregates Data)
SELECT department_id, SUM(salary) FROM employees GROUP BY department_id;
In this case, the result shows only one row per department, removing individual employee details.
Top 20 SQL Interview Questions
Like this post if you want me to continue this SQL Interview Seriesโฅ๏ธ
Share with credits: https://t.me/sqlspecialist
Hope it helps :)
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