Learn Python Coding
Learn Python through simple, practical examples and real coding ideas. Clear explanations, useful snippets, and hands-on learning for anyone starting or improving their programming skills. Admin: @HusseinSheikho || @Hussein_Sheikho
Mostrar más📈 Análisis del canal de Telegram Learn Python Coding
El canal Learn Python Coding (@pythonre) en el segmento lingüístico de Inglés es un actor destacado. Actualmente la comunidad reúne a 39 165 suscriptores, ocupando la posición 3 501 en la categoría Tecnologías y Aplicaciones y el puesto 10 515 en la región India.
📊 Métricas de audiencia y dinámica
Desde su creación el невідомо, el proyecto ha mostrado un crecimiento acelerado, reuniendo a 39 165 suscriptores.
Según los últimos datos del 09 junio, 2026, el canal mantiene una actividad estable. En los últimos 30 días la variación de miembros fue de 443, y en las últimas 24 horas de 15, conservando un alto alcance.
- Estado de verificación: No verificado
- Tasa de interacción (ER): El promedio de interacción de la audiencia es 2.52%. Durante las primeras 24 horas tras publicar, el contenido suele obtener 0.96% de reacciones respecto al total de suscriptores.
- Alcance de las publicaciones: Cada publicación recibe en promedio 988 visualizaciones. En el primer día suele acumular 374 visualizaciones.
- Reacciones e interacción: La audiencia responde de forma activa: el promedio de reacciones por publicación es 4.
- Intereses temáticos: El contenido se centra en temas clave como math, harvard, oxford, supervision, waybienad.
📝 Descripción y política de contenido
El autor describe el recurso como un espacio para expresar opiniones subjetivas:
“Learn Python through simple, practical examples and real coding ideas. Clear explanations, useful snippets, and hands-on learning for anyone starting or improving their programming skills.
Admin: @HusseinSheikho || @Hussein_Sheikho”
Gracias a la alta frecuencia de actualizaciones (últimos datos recibidos el 10 junio, 2026), el canal mantiene la vigencia y un amplio alcance. La analítica demuestra que la audiencia interactúa activamente con el contenido, lo que lo convierte en un punto de referencia dentro de la categoría Tecnologías y Aplicaciones.
math module provides a wide range of mathematical functions and constants for precise computations. It supports operations like trigonometry, logarithms, powers, and more.
import math
# Constants
print(math.pi) # Output: 3.141592653589793
print(math.e) # Output: 2.718281828459045
# Basic arithmetic
print(math.sqrt(16)) # Output: 4.0
print(math.pow(2, 3)) # Output: 8.0
print(math.factorial(5)) # Output: 120
# Trigonometric functions (in radians)
print(math.sin(math.pi / 2)) # Output: 1.0
print(math.cos(0)) # Output: 1.0
print(math.tan(math.pi / 4)) # Output: 0.9999999999999999
# Logarithmic functions
print(math.log(10)) # Output: 2.302585092994046
print(math.log10(100)) # Output: 2.0
print(math.log2(8)) # Output: 3.0
# Rounding functions
print(math.ceil(4.2)) # Output: 5
print(math.floor(4.8)) # Output: 4
print(math.trunc(4.9)) # Output: 4
print(round(4.5)) # Output: 4 (rounding to nearest even)
# Special functions
print(math.isfinite(10)) # Output: True
print(math.isinf(float('inf'))) # Output: True
print(math.isnan(0.0 / 0.0)) # Output: True
# Hyperbolic functions
print(math.sinh(1)) # Output: 1.1752011936438014
print(math.cosh(1)) # Output: 1.5430806348152417
# Copysign and fmod
print(math.copysign(-3, 1)) # Output: -3.0
print(math.fmod(10, 3)) # Output: 1.0
# Gamma function
print(math.gamma(4)) # Output: 6.0 (same as factorial(3))
By: @DataScienceQ 🚀# For loop: Use for fixed iterations over iterables (e.g., processing lists)
fruits = ["apple", "banana", "cherry"]
for fruit in fruits: # Iterates each element
print(fruit) # Output: apple \n banana \n cherry
for i in range(3): # Numeric sequence (start=0, stop=3)
print(i) # Output: 0 \n 1 \n 2
# While loop: Use when iterations depend on a dynamic condition (e.g., user input, convergence)
count = 0
while count < 3: # Runs as long as condition is True
print(count)
count += 1 # Increment to avoid infinite loop! Output: 0 \n 1 \n 2
# Nested loops: Use for 2D data (e.g., matrices, grids); outer for rows, inner for columns
matrix = [[1, 2], [3, 4]]
for row in matrix: # Outer: each sublist
for num in row: # Inner: elements in row
print(num) # Output: 1 \n 2 \n 3 \n 4
# Control statements: break (exit loop), continue (skip iteration)
for i in range(5):
if i == 2:
continue # Skip 2
if i == 4:
break # Exit at 4
print(i) # Output: 0 \n 1 \n 3
# List comprehension: Concise for loop alternative (use for simple transformations/filtering)
squares = [x**2 for x in range(5) if x % 2 == 0] # Even squares
print(squares) # Output: [0, 4, 16]
#python #loops #forloop #whileloop #nestedloops #comprehensions #interviewtips #controlflow
👉 @DataScience4# Basic linear search (O(n) - naive approach)
def linear_search(arr, target):
for i in range(len(arr)):
if arr[i] == target:
return i
return -1
nums = [1, 3, 5, 7, 9]
print(linear_search(nums, 5)) # Output: 2
# Binary search (O(log n) - efficient for sorted arrays)
def binary_search(arr, target):
left, right = 0, len(arr) - 1
while left <= right: # Divide range until found or empty
mid = (left + right) // 2
if arr[mid] == target:
return mid
elif arr[mid] < target:
left = mid + 1 # Search right half
else:
right = mid - 1 # Search left half
return -1
sorted_nums = [1, 3, 5, 7, 9]
print(binary_search(sorted_nums, 5)) # Output: 2
print(binary_search(sorted_nums, 6)) # Output: -1 (not found)
# Edge cases
print(binary_search([], 1)) # Output: -1 (empty list)
print(binary_search(, 1)) # Output: 0 (single element)
#python #algorithms #binarysearch #interviews #timescomplexity #problemsolving
👉 @DataScience4# Basic for loop over iterable (list)
fruits = ["apple", "banana", "cherry"]
for fruit in fruits: # Iterates each element directly
print(fruit) # Output: apple \n banana \n cherry
# For loop with range() for numeric sequences
for i in range(3): # Generates 0, 1, 2 (start=0, stop=3, step=1)
print(i) # Output: 0 \n 1 \n 2
for i in range(1, 6, 2): # Start=1, stop=6, step=2
print(i) # Output: 1 \n 3 \n 5
# Index-aware with enumerate() (gets both index and value)
for index, fruit in enumerate(fruits, start=1): # start=1 for 1-based indexing
print(f"{index}: {fruit}") # Output: 1: apple \n 2: banana \n 3: cherry
# Parallel iteration with zip() (pairs multiple iterables)
names = ["Alice", "Bob", "Charlie"]
ages = [25, 30, 35]
for name, age in zip(names, ages): # Stops at shortest iterable
print(f"{name} is {age} years old") # Output: Alice is 25 years old \n Bob is 30 years old \n Charlie is 35 years old
# Nested for loops (outer for rows, inner for columns; e.g., matrix)
matrix = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
for row in matrix: # Outer: each sublist
for num in row: # Inner: each element in row
print(num, end=' ') # Output: 1 2 3 4 5 6 7 8 9 (space-separated)
# For loop in list comprehension (concise iteration with optional condition)
squares = [x**2 for x in range(5)] # Basic comprehension
print(squares) # Output: [0, 1, 4, 9, 16]
evens_squared = [x**2 for x in range(10) if x % 2 == 0] # With condition (if)
print(evens_squared) # Output: [0, 4, 16, 36, 64]
# Nested comprehension (flattens 2D list)
flattened = [num for row in matrix for num in row] # Equivalent to nested for
print(flattened) # Output: [1, 2, 3, 4, 5, 6, 7, 8, 9]
#python #forloops #range #enumerate #zip #nestedloops #listcomprehension #interviewtips #iteration
👉 @DataScience4# Example: Solve "Find max in list" problem step-by-step
# Step 1: Understand - Input: list of nums; Output: max value; Constraints: empty list?
def find_max(numbers):
if not numbers: # Step 2: Handle edge case (empty list)
return None # Or raise ValueError
max_val = numbers # Step 3: Initialize with first element
for num in numbers[1:]: # Step 4: Loop through rest (sub-problem: compare)
if num > max_val:
max_val = num
return max_val # Step 5: Return result
# Step 6: Test cases
print(find_max([3, 1, 4, 1, 5])) # Output: 5
print(find_max([])) # Output: None
print(find_max()) # Output: 10
# If stuck: Comment code to trace, or simplify (e.g., use max() built-in first to verify)
This approach builds confidence—practice on platforms like LeetCode to make it habit! #python #problemsolving #codingexams #debugging #interviewtips
👉 @DataScience4# Basic comprehension
squares = [x**2 for x in range(5)] # [0, 1, 4, 9, 16]
# With condition
evens = [x for x in range(10) if x % 2 == 0] # [0, 2, 4, 6, 8]
# Nested with transformation
matrix = [[1, 2], [3, 4]]
flattened = [num for row in matrix for num in row] # [1, 2, 3, 4]
# Equivalent to loop (interview comparison)
result = []
for x in range(5):
result.append(x**2)
# result = [0, 1, 4, 9, 16] # Same as first example
#python #listcomprehensions #interviewtips #pythonic #datastructures
👉 @DataScience4 lst = [1, 2]
lst.append(3)
print(lst) # Output: [1, 2, 3]
⦁ extend(iterable): Adds all elements from an iterable to the end.
lst = [1, 2]
lst.extend([3, 4])
print(lst) # Output: [1, 2, 3, 4]
⦁ insert(i, x): Inserts x at index i (shifts elements right).
lst = [1, 3]
lst.insert(1, 2)
print(lst) # Output: [1, 2, 3]
📚 Removing Elements
⦁ remove(x): Removes the first occurrence of x (raises ValueError if not found).
lst = [1, 2, 2]
lst.remove(2)
print(lst) # Output: [1, 2]
⦁ pop(i=-1): Removes and returns the element at index i (default: last).
lst = [1, 2, 3]
item = lst.pop(1)
print(item, lst) # Output: 2 [1, 3]
⦁ clear(): Removes all elements.
lst = [1, 2, 3]
lst.clear()
print(lst) # Output: []
📚 Searching and Counting
⦁ count(x): Returns the number of occurrences of x.
lst = [1, 2, 2, 3]
print(lst.count(2)) # Output: 2
⦁ index(x[, start[, end]]): Returns the lowest index of x in the slice (raises ValueError if not found).
lst = [1, 2, 3, 2]
print(lst.index(2)) # Output: 1
📚 Ordering and Copying
⦁ sort(key=None, reverse=False): Sorts the list in place (ascending by default; stable sort).
lst = [3, 1, 2]
lst.sort()
print(lst) # Output: [1, 2, 3]
⦁ reverse(): Reverses the elements in place.
lst = [1, 2, 3]
lst.reverse()
print(lst) # Output: [3, 2, 1]
⦁ copy(): Returns a shallow copy of the list.
lst = [1, 2]
new_lst = lst.copy()
print(new_lst) # Output: [1, 2]
📚 Built-in Functions for Lists (Common Cases)
⦁ len(lst): Returns the number of elements.
lst = [1, 2, 3]
print(len(lst)) # Output: 3
⦁ min(lst): Returns the smallest element (raises ValueError if empty).
lst = [3, 1, 2]
print(min(lst)) # Output: 1
⦁ max(lst): Returns the largest element.
lst = [3, 1, 2]
print(max(lst)) # Output: 3
⦁ sum(lst[, start=0]): Sums the elements (start adds an offset).
lst = [1, 2, 3]
print(sum(lst)) # Output: 6
⦁ sorted(lst, key=None, reverse=False): Returns a new sorted list (non-destructive).
lst = [3, 1, 2]
print(sorted(lst)) # Output: [1, 2, 3]
These cover all standard operations (O(1) for append/pop from end, O(n) for most others). Use slicing lst[start:end:step] for advanced extraction, like lst[1:3] outputs ``.
#python #lists #datastructures #methods #examples #programming
⭐ @DataScience4for loops with enumerate() provide both the index and value of items in an iterable, making it ideal for tasks needing positional awareness without manual counters. This is more Pythonic and efficient than using range(len()) for list traversals.
fruits = ['apple', 'banana', 'cherry']
for index, fruit in enumerate(fruits):
print(f"{index}: {fruit}")
# Output:
# 0: apple
# 1: banana
# 2: cherry
# With start offset:
for index, fruit in enumerate(fruits, start=1):
print(f"{index}: {fruit}")
# 1: apple
# 2: banana
# 3: cherry
#python #forloops #enumerate #bestpractices
✉️ @DataScience4yield instead of return, allowing lazy evaluation for large datasets or infinite sequences. They're ideal for advanced scenarios like streaming data or coroutines.
def fibonacci(n):
a, b = 0, 1
for _ in range(n):
yield a
a, b = b, a + b
# Usage: list(fibonacci(10)) -> [0, 1, 1, 2, 3, 5, 8, 13, 21, 34]
🆘 @DataScience4
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