Learn Python Coding
Learn Python through simple, practical examples and real coding ideas. Clear explanations, useful snippets, and hands-on learning for anyone starting or improving their programming skills. Admin: @HusseinSheikho || @Hussein_Sheikho
Show more📈 Analytical overview of Telegram channel Learn Python Coding
Channel Learn Python Coding (@pythonre) in the English language segment is an active participant. Currently, the community unites 39 165 subscribers, ranking 3 501 in the Technologies & Applications category and 10 515 in the India region.
📊 Audience metrics and dynamics
Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 39 165 subscribers.
According to the latest data from 09 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by 443 over the last 30 days and by 15 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 2.52%. Within the first 24 hours after publication, content typically collects 0.96% reactions from the total number of subscribers.
- Post reach: On average, each post receives 988 views. Within the first day, a publication typically gains 374 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 4.
- Thematic interests: Content is focused on key topics such as math, harvard, oxford, supervision, waybienad.
📝 Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
“Learn Python through simple, practical examples and real coding ideas. Clear explanations, useful snippets, and hands-on learning for anyone starting or improving their programming skills.
Admin: @HusseinSheikho || @Hussein_Sheikho”
Thanks to the high frequency of updates (latest data received on 10 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.
math module provides a wide range of mathematical functions and constants for precise computations. It supports operations like trigonometry, logarithms, powers, and more.
import math
# Constants
print(math.pi) # Output: 3.141592653589793
print(math.e) # Output: 2.718281828459045
# Basic arithmetic
print(math.sqrt(16)) # Output: 4.0
print(math.pow(2, 3)) # Output: 8.0
print(math.factorial(5)) # Output: 120
# Trigonometric functions (in radians)
print(math.sin(math.pi / 2)) # Output: 1.0
print(math.cos(0)) # Output: 1.0
print(math.tan(math.pi / 4)) # Output: 0.9999999999999999
# Logarithmic functions
print(math.log(10)) # Output: 2.302585092994046
print(math.log10(100)) # Output: 2.0
print(math.log2(8)) # Output: 3.0
# Rounding functions
print(math.ceil(4.2)) # Output: 5
print(math.floor(4.8)) # Output: 4
print(math.trunc(4.9)) # Output: 4
print(round(4.5)) # Output: 4 (rounding to nearest even)
# Special functions
print(math.isfinite(10)) # Output: True
print(math.isinf(float('inf'))) # Output: True
print(math.isnan(0.0 / 0.0)) # Output: True
# Hyperbolic functions
print(math.sinh(1)) # Output: 1.1752011936438014
print(math.cosh(1)) # Output: 1.5430806348152417
# Copysign and fmod
print(math.copysign(-3, 1)) # Output: -3.0
print(math.fmod(10, 3)) # Output: 1.0
# Gamma function
print(math.gamma(4)) # Output: 6.0 (same as factorial(3))
By: @DataScienceQ 🚀# For loop: Use for fixed iterations over iterables (e.g., processing lists)
fruits = ["apple", "banana", "cherry"]
for fruit in fruits: # Iterates each element
print(fruit) # Output: apple \n banana \n cherry
for i in range(3): # Numeric sequence (start=0, stop=3)
print(i) # Output: 0 \n 1 \n 2
# While loop: Use when iterations depend on a dynamic condition (e.g., user input, convergence)
count = 0
while count < 3: # Runs as long as condition is True
print(count)
count += 1 # Increment to avoid infinite loop! Output: 0 \n 1 \n 2
# Nested loops: Use for 2D data (e.g., matrices, grids); outer for rows, inner for columns
matrix = [[1, 2], [3, 4]]
for row in matrix: # Outer: each sublist
for num in row: # Inner: elements in row
print(num) # Output: 1 \n 2 \n 3 \n 4
# Control statements: break (exit loop), continue (skip iteration)
for i in range(5):
if i == 2:
continue # Skip 2
if i == 4:
break # Exit at 4
print(i) # Output: 0 \n 1 \n 3
# List comprehension: Concise for loop alternative (use for simple transformations/filtering)
squares = [x**2 for x in range(5) if x % 2 == 0] # Even squares
print(squares) # Output: [0, 4, 16]
#python #loops #forloop #whileloop #nestedloops #comprehensions #interviewtips #controlflow
👉 @DataScience4# Basic linear search (O(n) - naive approach)
def linear_search(arr, target):
for i in range(len(arr)):
if arr[i] == target:
return i
return -1
nums = [1, 3, 5, 7, 9]
print(linear_search(nums, 5)) # Output: 2
# Binary search (O(log n) - efficient for sorted arrays)
def binary_search(arr, target):
left, right = 0, len(arr) - 1
while left <= right: # Divide range until found or empty
mid = (left + right) // 2
if arr[mid] == target:
return mid
elif arr[mid] < target:
left = mid + 1 # Search right half
else:
right = mid - 1 # Search left half
return -1
sorted_nums = [1, 3, 5, 7, 9]
print(binary_search(sorted_nums, 5)) # Output: 2
print(binary_search(sorted_nums, 6)) # Output: -1 (not found)
# Edge cases
print(binary_search([], 1)) # Output: -1 (empty list)
print(binary_search(, 1)) # Output: 0 (single element)
#python #algorithms #binarysearch #interviews #timescomplexity #problemsolving
👉 @DataScience4# Basic for loop over iterable (list)
fruits = ["apple", "banana", "cherry"]
for fruit in fruits: # Iterates each element directly
print(fruit) # Output: apple \n banana \n cherry
# For loop with range() for numeric sequences
for i in range(3): # Generates 0, 1, 2 (start=0, stop=3, step=1)
print(i) # Output: 0 \n 1 \n 2
for i in range(1, 6, 2): # Start=1, stop=6, step=2
print(i) # Output: 1 \n 3 \n 5
# Index-aware with enumerate() (gets both index and value)
for index, fruit in enumerate(fruits, start=1): # start=1 for 1-based indexing
print(f"{index}: {fruit}") # Output: 1: apple \n 2: banana \n 3: cherry
# Parallel iteration with zip() (pairs multiple iterables)
names = ["Alice", "Bob", "Charlie"]
ages = [25, 30, 35]
for name, age in zip(names, ages): # Stops at shortest iterable
print(f"{name} is {age} years old") # Output: Alice is 25 years old \n Bob is 30 years old \n Charlie is 35 years old
# Nested for loops (outer for rows, inner for columns; e.g., matrix)
matrix = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
for row in matrix: # Outer: each sublist
for num in row: # Inner: each element in row
print(num, end=' ') # Output: 1 2 3 4 5 6 7 8 9 (space-separated)
# For loop in list comprehension (concise iteration with optional condition)
squares = [x**2 for x in range(5)] # Basic comprehension
print(squares) # Output: [0, 1, 4, 9, 16]
evens_squared = [x**2 for x in range(10) if x % 2 == 0] # With condition (if)
print(evens_squared) # Output: [0, 4, 16, 36, 64]
# Nested comprehension (flattens 2D list)
flattened = [num for row in matrix for num in row] # Equivalent to nested for
print(flattened) # Output: [1, 2, 3, 4, 5, 6, 7, 8, 9]
#python #forloops #range #enumerate #zip #nestedloops #listcomprehension #interviewtips #iteration
👉 @DataScience4# Example: Solve "Find max in list" problem step-by-step
# Step 1: Understand - Input: list of nums; Output: max value; Constraints: empty list?
def find_max(numbers):
if not numbers: # Step 2: Handle edge case (empty list)
return None # Or raise ValueError
max_val = numbers # Step 3: Initialize with first element
for num in numbers[1:]: # Step 4: Loop through rest (sub-problem: compare)
if num > max_val:
max_val = num
return max_val # Step 5: Return result
# Step 6: Test cases
print(find_max([3, 1, 4, 1, 5])) # Output: 5
print(find_max([])) # Output: None
print(find_max()) # Output: 10
# If stuck: Comment code to trace, or simplify (e.g., use max() built-in first to verify)
This approach builds confidence—practice on platforms like LeetCode to make it habit! #python #problemsolving #codingexams #debugging #interviewtips
👉 @DataScience4# Basic comprehension
squares = [x**2 for x in range(5)] # [0, 1, 4, 9, 16]
# With condition
evens = [x for x in range(10) if x % 2 == 0] # [0, 2, 4, 6, 8]
# Nested with transformation
matrix = [[1, 2], [3, 4]]
flattened = [num for row in matrix for num in row] # [1, 2, 3, 4]
# Equivalent to loop (interview comparison)
result = []
for x in range(5):
result.append(x**2)
# result = [0, 1, 4, 9, 16] # Same as first example
#python #listcomprehensions #interviewtips #pythonic #datastructures
👉 @DataScience4 lst = [1, 2]
lst.append(3)
print(lst) # Output: [1, 2, 3]
⦁ extend(iterable): Adds all elements from an iterable to the end.
lst = [1, 2]
lst.extend([3, 4])
print(lst) # Output: [1, 2, 3, 4]
⦁ insert(i, x): Inserts x at index i (shifts elements right).
lst = [1, 3]
lst.insert(1, 2)
print(lst) # Output: [1, 2, 3]
📚 Removing Elements
⦁ remove(x): Removes the first occurrence of x (raises ValueError if not found).
lst = [1, 2, 2]
lst.remove(2)
print(lst) # Output: [1, 2]
⦁ pop(i=-1): Removes and returns the element at index i (default: last).
lst = [1, 2, 3]
item = lst.pop(1)
print(item, lst) # Output: 2 [1, 3]
⦁ clear(): Removes all elements.
lst = [1, 2, 3]
lst.clear()
print(lst) # Output: []
📚 Searching and Counting
⦁ count(x): Returns the number of occurrences of x.
lst = [1, 2, 2, 3]
print(lst.count(2)) # Output: 2
⦁ index(x[, start[, end]]): Returns the lowest index of x in the slice (raises ValueError if not found).
lst = [1, 2, 3, 2]
print(lst.index(2)) # Output: 1
📚 Ordering and Copying
⦁ sort(key=None, reverse=False): Sorts the list in place (ascending by default; stable sort).
lst = [3, 1, 2]
lst.sort()
print(lst) # Output: [1, 2, 3]
⦁ reverse(): Reverses the elements in place.
lst = [1, 2, 3]
lst.reverse()
print(lst) # Output: [3, 2, 1]
⦁ copy(): Returns a shallow copy of the list.
lst = [1, 2]
new_lst = lst.copy()
print(new_lst) # Output: [1, 2]
📚 Built-in Functions for Lists (Common Cases)
⦁ len(lst): Returns the number of elements.
lst = [1, 2, 3]
print(len(lst)) # Output: 3
⦁ min(lst): Returns the smallest element (raises ValueError if empty).
lst = [3, 1, 2]
print(min(lst)) # Output: 1
⦁ max(lst): Returns the largest element.
lst = [3, 1, 2]
print(max(lst)) # Output: 3
⦁ sum(lst[, start=0]): Sums the elements (start adds an offset).
lst = [1, 2, 3]
print(sum(lst)) # Output: 6
⦁ sorted(lst, key=None, reverse=False): Returns a new sorted list (non-destructive).
lst = [3, 1, 2]
print(sorted(lst)) # Output: [1, 2, 3]
These cover all standard operations (O(1) for append/pop from end, O(n) for most others). Use slicing lst[start:end:step] for advanced extraction, like lst[1:3] outputs ``.
#python #lists #datastructures #methods #examples #programming
⭐ @DataScience4for loops with enumerate() provide both the index and value of items in an iterable, making it ideal for tasks needing positional awareness without manual counters. This is more Pythonic and efficient than using range(len()) for list traversals.
fruits = ['apple', 'banana', 'cherry']
for index, fruit in enumerate(fruits):
print(f"{index}: {fruit}")
# Output:
# 0: apple
# 1: banana
# 2: cherry
# With start offset:
for index, fruit in enumerate(fruits, start=1):
print(f"{index}: {fruit}")
# 1: apple
# 2: banana
# 3: cherry
#python #forloops #enumerate #bestpractices
✉️ @DataScience4yield instead of return, allowing lazy evaluation for large datasets or infinite sequences. They're ideal for advanced scenarios like streaming data or coroutines.
def fibonacci(n):
a, b = 0, 1
for _ in range(n):
yield a
a, b = b, a + b
# Usage: list(fibonacci(10)) -> [0, 1, 1, 2, 3, 5, 8, 13, 21, 34]
🆘 @DataScience4
Available now! Telegram Research 2025 — the year's key insights 
