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OSSSC / OSSC MATH AND REASONING

OSSSC / OSSC MATH AND REASONING

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𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS Join our YouTube Channel: https://shorturl.at/Ulwjw 🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY 🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH

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📈 Analytical overview of Telegram channel OSSSC / OSSC MATH AND REASONING

Channel OSSSC / OSSC MATH AND REASONING (@pinnacle_math_reasoning) in the English language segment is an active participant. Currently, the community unites 11 530 subscribers, ranking 17 105 in the Education category and 33 456 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 11 530 subscribers.

According to the latest data from 03 October, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by 130 over the last 30 days and by -3 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 12.47%. Within the first 24 hours after publication, content typically collects 4.11% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 1 438 views. Within the first day, a publication typically gains 474 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
  • Thematic interests: Content is focused on key topics such as ʜᴇʀᴇ, cgle, cgl, mcqs, mcq.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
“𝐀𝐧𝐲 PROMOTION RELATED CONTACT OWNER @BUNNYTAPAS Join our YouTube Channel: https://shorturl.at/Ulwjw 🔴 𝐂𝐮𝐫𝐫𝐞𝐧𝐭 𝐚𝐟𝐟𝐚𝐢𝐫𝐬 @CURRENT_AFFAIRS_REGULARLY 🔴𝐄𝐧𝐠𝐥𝐢𝐬𝐡- @BLACKBOOK_ENGLISH”

Thanks to the high frequency of updates (latest data received on 04 October, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

11 530
Subscribers
-324 hours
+117 days
+13030 days
Posts Archive
Ans. (a) : L.C.M of 15, 18 and 36 15 = 3 × 5 18 = 2 × 3 × 3 36 = 2 × 2 × 3 × 3 LCM = 180 Required number = 180 k + 9 => 180 × 6 + 9 = 1089 Hence, on putting k = 6, the number is divisible by 11

𝐎𝐃𝐈𝐒𝐇𝐀   𝐕𝐈𝐑𝐓𝐔𝐀𝐋   𝐋𝐈𝐁𝐑𝐀𝐑𝐘 What is the least number which when divided by 15, 18 and 36 leaves the same remainder 9 in each case and is divisible by 11 ?
Anonymous voting

Ans. (c) : The least number · (L.C.M of 15, 18, 36) x + 9 = 180x + 9 ∵ (180x + 9) is divisible by 11. ∴ On taking x = 6, Number · 180×6 + 9 = 1089 Sum of the digits of the number · 1+0+8+9 =18 ✅

𝐎𝐃𝐈𝐒𝐇𝐀   𝐕𝐈𝐑𝐓𝐔𝐀𝐋   𝐋𝐈𝐁𝐑𝐀𝐑𝐘 What is the sum of the digits of the least number which when divided by 15, 18 and 36 leaves the same remainder 9 in each case and is divisible by 11?
Anonymous voting

Ans. (d) : The number divisible by 5, 6 and 8 · (L.C.M of 5, 6 and 8)×k = 120 k The numbers between 300 and 700 = (120×3), (120×4), (120×5) = 360, 480, 600 Hence, there are three numbers (360, 480, 600) between 300 and 700 which is divisible by 5, 6 and 8.

𝐎𝐃𝐈𝐒𝐇𝐀   𝐕𝐈𝐑𝐓𝐔𝐀𝐋   𝐋𝐈𝐁𝐑𝐀𝐑𝐘 How many numbers between 300 and 700 are divisible by 5, 6 and 8?
Anonymous voting

Again the bells ring simultaneously after · (L.C.M of 3, 5, 8, 9 and 10) = 360 seconds 360 / 60minutes =6 minutes

𝐎𝐃𝐈𝐒𝐇𝐀   𝐕𝐈𝐑𝐓𝐔𝐀𝐋   𝐋𝐈𝐁𝐑𝐀𝐑𝐘 Five bells ring together at the intervals of 3, 5, 8, 9 and 10 seconds. All the bells ring simultaneously at the same time. They will again ring simultaneously after:
Anonymous voting

Ans. (d) : L.C.M of 12, 16, 18, 20 and 25 = 3600 ∴ x = 3600 k + 4 For k = 5, the number will be divisible by x = 7 x = 18004 Hence, the digit at the thousand's place will be 8.

𝐎𝐃𝐈𝐒𝐇𝐀   𝐕𝐈𝐑𝐓𝐔𝐀𝐋   𝐋𝐈𝐁𝐑𝐀𝐑𝐘 When 12, 16, 18, 20 and 25 divide the least number x, the remainder in each case is 4 but x is divisible by 7. What is the digit at the thousands' place in x ?
Anonymous voting

Ans. (b) : LCM of 5, 6 and 8 = 5 × 2 × 3 × 2 × 2 = 120 Required number · 120 + 3 = 123

𝐎𝐃𝐈𝐒𝐇𝐀   𝐕𝐈𝐑𝐓𝐔𝐀𝐋   𝐋𝐈𝐁𝐑𝐀𝐑𝐘 Find the smallest number such that when it is divided by 5, 6 and 8 it leaves a remainder 3 in each case.
Anonymous voting

𝐎𝐃𝐈𝐒𝐇𝐀   𝐕𝐈𝐑𝐓𝐔𝐀𝐋   𝐋𝐈𝐁𝐑𝐀𝐑𝐘 How many zeroes are there in product 4⁶ × 15¹⁰?
Anonymous voting

𝐎𝐃𝐈𝐒𝐇𝐀   𝐕𝐈𝐑𝐓𝐔𝐀𝐋   𝐋𝐈𝐁𝐑𝐀𝐑𝐘 Find the positive number which when decreased by 20 is equal to 2925 times the reciprocal of the number.
Anonymous voting

𝐎𝐃𝐈𝐒𝐇𝐀   𝐕𝐈𝐑𝐓𝐔𝐀𝐋   𝐋𝐈𝐁𝐑𝐀𝐑𝐘 If the difference between two numbers is 6 and the difference between their squares is 60, what is the sum of their cubes?
Anonymous voting

𝐎𝐃𝐈𝐒𝐇𝐀   𝐕𝐈𝐑𝐓𝐔𝐀𝐋   𝐋𝐈𝐁𝐑𝐀𝐑𝐘 If A = 0.abcabc....., then by what number A should be multiplied so as to get an integeral value ?
Anonymous voting