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Physics UNBOXED

Physics UNBOXED

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In this channel you will get phy. All level questions including olympiad level too.. with extra ordinary problems FOR QUERY Contact us :- @unv_unbx_bot

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πŸ“ˆ Analytical overview of Telegram channel Physics UNBOXED

Channel Physics UNBOXED (@phy_unbx) in the English language segment is an active participant. Currently, the community unites 10 268 subscribers, ranking 19 322 in the Education category and 38 938 in the India region.

πŸ“Š Audience metrics and dynamics

Since its creation on Π½Π΅Π²Ρ–Π΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 10 268 subscribers.

According to the latest data from 02 July, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -1 898 over the last 30 days and by -91 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 10.20%. Within the first 24 hours after publication, content typically collects 3.86% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 1 047 views. Within the first day, a publication typically gains 396 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 3.
  • Thematic interests: Content is focused on key topics such as jee, dosto, shift, troy, sir.

πŸ“ Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
β€œIn this channel you will get phy. All level questions including olympiad level too.. with extra ordinary problems FOR QUERY Contact us :- @unv_unbx_bot”

Thanks to the high frequency of updates (latest data received on 03 July, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

10 268
Subscribers
-9124 hours
-1 1707 days
-1 89830 days
Posts Archive
if you want Problem compilation pdf ( only 5 problems ) then everybody give reactions min target is 100 reactions

join @phy_unbx for more
join @phy_unbx for more

I think unboxed is active again guys Same problem solving Reactions and all Making unboxed great again
I think unboxed is active again guys Same problem solving Reactions and all Making unboxed great again

Repost from Physics UNBOXED
STATMENT A massless rope winds around a cylinder of mass M and radius R, over a pulley, and then wraps around a solid sphere
STATMENT A massless rope winds around a cylinder of mass M and radius R, over a pulley, and then wraps around a solid sphere of mass M and radius R. The pulley is a hoop, also of mass M and radius R, and is free to turn about a frictionless bearing located at its center. The rope does not slip on the pulley. Find the linear accelerations a1 and a2 of the centers of the sphere and cylinder respectively, and the angular acceleration Ξ± of the pulley. The positive directions for a1, a2, and Ξ± are shown in the figure.

Lou archives are evergreenπŸ₯°

Solution in the next hour
Solution in the next hour

Repost from N/a
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next time lou paper by my side pakka
+1
next time lou paper by my side pakka

Introducing Real Lou Paper ( physics bhi noi bna rha iss baar mein )
+1
Introducing Real Lou Paper ( physics bhi noi bna rha iss baar mein )

Hey fellas Unboxed owner is back now solve this
Hey fellas Unboxed owner is back now solve this

#LOU sample problem
#LOU sample problem

Kitne mil rhe bhaiya ..

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Build Your Future with the Right Support at Troy University! Great research starts with great mentorship. At Troy University, you'll learn from experienced faculty, receive personalized academic guidance, and become part of a collaborative learning community that helps you grow academically, professionally, and globally. Start your journey today: https://go2troyuniversity.com/international-form/⁠�

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photo content

Does there exist a non symmetric charge distribution such that the Electric field generated due to it is exactly 0 for all points P far enough from origin.

easy problem from F=ma
easy problem from F=ma