C Programming Codes
C Programming Codes || Quizzes || DSA Learn along with the community Any queries admin - @Pradeep_saii
Show moreπ Analytical overview of Telegram channel C Programming Codes
Channel C Programming Codes (@c_programming_codes) in the English language segment is an active participant. Currently, the community unites 13 417 subscribers, ranking 9 552 in the Technologies & Applications category and 32 040 in the India region.
π Audience metrics and dynamics
Since its creation on Π½Π΅Π²ΡΠ΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 13 417 subscribers.
According to the latest data from 13 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -228 over the last 30 days and by -2 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 9.78%. Within the first 24 hours after publication, content typically collects N/A% reactions from the total number of subscribers.
- Post reach: On average, each post receives 0 views. Within the first day, a publication typically gains 0 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 0.
- Thematic interests: Content is focused on key topics such as input, string, scanf("%d, array, element.
π Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
βC Programming Codes || Quizzes || DSA
Learn along with the community
Any queries
admin - @Pradeep_saiiβ
Thanks to the high frequency of updates (latest data received on 14 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.
#include <stdio.h>
int main() {
int n, i, sum = 0;
scanf("%d", &n);
for (i = 1; i <= n; i++) {
sum += i;
}
printf("%d\n", sum);
return 0;
}#include <stdio.h>
#include <math.h>
int main() {
double a, b, c, discriminant, root1, root2, realPart, imagPart;
printf("Enter coefficients a, b, and c: ");
scanf("%lf %lf %lf", &a, &b, &c);
discriminant = b * b - 4 * a * c;
if (discriminant > 0) {
root1 = (-b + sqrt(discriminant)) / (2 * a);
root2 = (-b - sqrt(discriminant)) / (2 * a);
printf("Root 1 = %.2lf and Root 2 = %.2lf\n", root1, root2);
} else if (discriminant == 0) {
root1 = root2 = -b / (2 * a);
printf("Root 1 = Root 2 = %.2lf\n", root1);
} else {
realPart = -b / (2 * a);
imagPart = sqrt(-discriminant) / (2 * a);
printf("Root 1 = %.2lf+%.2lfi and Root 2 = %.2lf-%.2lfi\n", realPart, imagPart, realPart, imagPart);
}
return 0;
}#include <stdio.h>
#include <stdbool.h>
bool isLeapYear(int year) {
if (year % 400 == 0) return true;
if (year % 100 == 0) return false;
return (year % 4 == 0);
}
int main() {
int year;
printf("Enter a year: ");
scanf("%d", &year);
if (isLeapYear(year)) {
printf("%d is a leap year.\n", year);
} else {
printf("%d is not a leap year.\n", year);
}
return 0;
}#include <stdio.h>
int main() {
int a, b, c, largest;
printf("Enter three numbers: ");
scanf("%d %d %d", &a, &b, &c);
largest = a;
if (b > largest) {
largest = b;
}
if (c > largest) {
largest = c;
}
printf("Largest number = %d\n", largest);
return 0;
}#include <stdio.h>
unsigned int flipBits(unsigned int n, unsigned int mask) {
return n ^ mask;
}
int main() {
unsigned int number = 10;
unsigned int bitsToFlip = 0b101;
unsigned int result = flipBits(number, bitsToFlip);
printf("Original number: %u\n", number);
printf("Mask: %u\n", bitsToFlip);
printf("Number after flipping bits: %u\n", result);
return 0;
}#include <stdio.h>
int main() {
int x = 5;
int y = 10;
int result1, result2;
result1 = x++;
printf("x: %d, result1: %d\n", x, result1);
result2 = ++y;
printf("y: %d, result2: %d\n", y, result2);
x = 5;
y = 10;
printf("Initial x: %d, Initial y: %d\n", x, y);
printf("Post-decrement x: %d\n", x--);
printf("Pre-decrement y: %d\n", --y);
printf("Final x: %d, Final y: %d\n", x, y);
return 0;
}#include <stdio.h>
int add(int a, int b) {
return a + b;
}
int main() {
int num1, num2, sum;
printf("Enter two numbers: ");
scanf("%d %d", &num1, &num2);
sum = add(num1, num2);
printf("Sum = %d\n", sum);
return 0;
}#include <stdio.h>
int main() {
char ch;
printf("Enter a character: ");
scanf(" %c", &ch);
printf("ASCII value of %c = %d\n", ch, ch);
return 0;
}#include <stdio.h>
int main() {
int num;
scanf("%d", &num);
if (num > 0) {
printf("Positive\n");
} else if (num < 0) {
printf("Negative\n");
} else {
printf("Zero\n");
}
return 0;
}
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