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C Programming Language || Hands On Coding

C Programming Language || Hands On Coding

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Hands-on C programming language challenges for beginners. Learn building logic by solving programs. Owner: @Pradeep_saii

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📈 Analytical overview of Telegram channel C Programming Language || Hands On Coding

Channel C Programming Language || Hands On Coding (@c_programming_language_coding) in the English language segment is an active participant. Currently, the community unites 12 821 subscribers, ranking 9 572 in the Technologies & Applications category and 31 202 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 12 821 subscribers.

According to the latest data from 28 August, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -213 over the last 30 days and by -1 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 6.87%. Within the first 24 hours after publication, content typically collects 2.42% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 881 views. Within the first day, a publication typically gains 310 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
  • Thematic interests: Content is focused on key topics such as input, string, scanf("%d, array, element.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
Hands-on C programming language challenges for beginners. Learn building logic by solving programs. Owner: @Pradeep_saii

Thanks to the high frequency of updates (latest data received on 29 August, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.

12 821
Subscribers
-124 hours
-297 days
-21330 days
Posts Archive
📚 1. Absolute Fundamentals: Setting Up & Basic Interaction

🚀 Welcome to the C Programming Programs Channel! Welcome to the C Programming Programs Channel, your structured path to mastering C and building rock-solid problem-solving skills. We provide a simple, powerful learning plan: over 500 practical programs that guide you from foundational syntax to advanced data structures and algorithms. For the best experience, we recommend using a PC. Note: The problems sent in the channel are carefully selected to challenge your skills and prepare you for real-world scenarios. Stay Updated & Share Join the channel to get access to all the problems: https://t.me/c_programming_language_programss Share and support your fellow coders! Happy Coding! 🎉

Count Words in a Sentence
#include <stdio.h>
#include <string.h>

int main() {
 char str[100];
 int count = 0, i;

 printf("Enter a sentence: ");
 fgets(str, sizeof(str), stdin);

 for (i = 0; str[i] != '\0'; i++) {
 if (str[i] == ' ') {
 count++;
 }
 }
 if (strlen(str) > 1) {
 count++;
 }

 printf("Number of words: %d\n", count);
 return 0;
}

Pangram Checker
#include <stdio.h>
#include <string.h>
#include <ctype.h>

int isPangram(const char *str) {
 int alphabet[26] = {0};
 int index;
 int i;
 for (i = 0; str[i] != '\0'; i++) {
 if (isalpha(str[i])) {
  index = tolower(str[i]) - 'a';
  alphabet[index] = 1;
 }
 }
 for (i = 0; i < 26; i++) {
 if (alphabet[i] == 0) {
  return 0;
 }
 }
 return 1;
}

int main() {
 char str[100];
 fgets(str, sizeof(str), stdin);
 str[strcspn(str, "\n")] = 0;
 if (isPangram(str)) {
 printf("Pangram\n");
 } else {
 printf("Not a Pangram\n");
 }
 return 0;
}

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Capitalize First Letter of Words in a Sentence
#include <stdio.h>
#include <string.h>
#include <ctype.h>

void capitalize(char str[]) {
    int i = 0;
    if (str[i] != '\0') {
        str[i] = toupper(str[i]);
        i++;
    }
    while (str[i] != '\0') {
        if (str[i-1] == ' ') {
            str[i] = toupper(str[i]);
        }
        i++;
    }
}

int main() {
    char sentence[100];
    printf("Enter a sentence: ");
    fgets(sentence, sizeof(sentence), stdin);
    sentence[strcspn(sentence, "\n")] = 0;
    capitalize(sentence);
    printf("Capitalized sentence: %s\n", sentence);
    return 0;
}

Longest Word in a Sentence
#include <stdio.h>
#include <string.h>

int main() {
  char sentence[100];
  char word[50];
  char longest[50] = "";
  int i, j, len, maxLen = 0;

  printf("Enter a sentence: ");
  fgets(sentence, sizeof(sentence), stdin);
  sentence[strcspn(sentence, "\n")] = 0;

  len = strlen(sentence);
  j = 0;
  for (i = 0; i <= len; i++) {
    if (sentence[i] == ' ' || sentence[i] == '\0') {
      word[j] = '\0';
      if (strlen(word) > maxLen) {
        maxLen = strlen(word);
        strcpy(longest, word);
      }
      j = 0;
    } else {
      word[j++] = sentence[i];
    }
  }

  printf("Longest word: %s\n", longest);
  return 0;
}

Remove Repeated Characters from a String
#include <stdio.h>
#include <string.h>

int main() {
 char str[100], result[100];
 int i, j, k = 0, len;
 int found;

 printf("Enter a string: ");
 fgets(str, sizeof(str), stdin);
 str[strcspn(str, "\n")] = 0;

 len = strlen(str);

 for (i = 0; i < len; i++) {
 found = 0;
 for (j = 0; j < k; j++) {
 if (str[i] == result[j]) {
 found = 1;
 break;
 }
 }
 if (!found) {
 result[k++] = str[i];
 }
 }
 result[k] = '\0';

 printf("String with unique characters: %s\n", result);
 return 0;
}

String Contains Only Digits
#include <stdio.h>
#include <string.h>
#include <ctype.h>

int main() {
  char str[100];
  int i, len, flag = 1;

  scanf("%s", str);
  len = strlen(str);

  for (i = 0; i < len; i++) {
    if (!isdigit(str[i])) {
      flag = 0;
      break;
    }
  }

  if (flag == 1) {
    printf("Yes");
  } else {
    printf("No");
  }
  return 0;
}

Find Most Frequent Character in a String
#include <stdio.h>
#include <string.h>

int main() {
 char str[100];
 int freq[256] = {0};
 int i, max = 0, ascii;

 printf("Enter a string: ");
 fgets(str, sizeof(str), stdin);
 str[strcspn(str, "\n")] = 0;

 for (i = 0; str[i] != '\0'; i++) {
 ascii = (int)str[i];
 freq[ascii]++;
 }

 for (i = 0; i < 256; i++) {
 if (freq[i] > freq[max]) {
 max = i;
 }
 }

 printf("Most frequent character: %c\n", (char)max);
 printf("Frequency: %d\n", freq[max]);

 return 0;
}

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Character Frequency in String
#include <stdio.h>
#include <string.h>

int main() {
 char str[100];
 int freq[256] = {0};
 int i;

 printf("Enter a string: ");
 fgets(str, sizeof(str), stdin);
 str[strcspn(str, "\n")] = 0;

 for (i = 0; str[i] != '\0'; i++) {
 freq[str[i]]++;
 }

 printf("Character frequencies:\n");
 for (i = 0; i < 256; i++) {
 if (freq[i] != 0) {
 printf("'%c': %d\n", i, freq[i]);
 }
 }

 return 0;
}

String Rotation Check
#include <stdio.h>
#include <string.h>
#include <stdbool.h>

bool areRotations(char *str1, char *str2) {
  int n = strlen(str1);
  int m = strlen(str2);
  if (n != m) return false;
  char temp[2 * n + 1];
  strcpy(temp, str1);
  strcat(temp, str1);
  if (strstr(temp, str2) != NULL) return true;
  return false;
}

int main() {
  char str1[] = "ABCD";
  char str2[] = "CDAB";
  if (areRotations(str1, str2))
    printf("Strings are rotations of each other");
  else
    printf("Strings are not rotations of each other");
  return 0;
}

First Non-Repeating Character in a String
#include <stdio.h>
#include <string.h>

char findFirstNonRepeating(const char *str) {
 int counts[256] = {0};
 int len = strlen(str);
 for (int i = 0; i < len; i++) {
 counts[(unsigned char)str[i]]++;
 }
 for (int i = 0; i < len; i++) {
 if (counts[(unsigned char)str[i]] == 1) {
 return str[i];
 }
 }
 return '\0';
}

int main() {
 char str[] = "programming";
 char result = findFirstNonRepeating(str);
 if (result != '\0') {
 printf("First non-repeating char: %c\n", result);
 } else {
 printf("No non-repeating character found.\n");
 }
 return 0;
}

Anagram String Checker
#include <stdio.h>
#include <string.h>
#include <stdbool.h>

bool areAnagrams(char str1[], char str2[]) {
    int n1 = strlen(str1);
    int n2 = strlen(str2);

    if (n1 != n2)
        return false;

    int count[256] = {0};
    for (int i = 0; str1[i] && str2[i]; i++) {
        count[str1[i]]++;
        count[str2[i]]--;
    }

    for (int i = 0; i < 256; i++)
        if (count[i])
            return false;

    return true;
}

int main() {
    char str1[100], str2[100];
    printf("Enter first string: ");
    scanf("%s", str1);
    printf("Enter second string: ");
    scanf("%s", str2);

    if (areAnagrams(str1, str2))
        printf("\"%s\" and \"%s\" are anagrams\n", str1, str2);
    else
        printf("\"%s\" and \"%s\" are not anagrams\n", str1, str2);

    return 0;
}

Find Duplicate Characters in a String
#include <stdio.h>
#include <string.h>

int main() {
 char str[100];
 int i, j, len;

 printf("Enter a string: ");
 fgets(str, sizeof(str), stdin);
 str[strcspn(str, "\n")] = 0;

 len = strlen(str);

 printf("Duplicate characters are: ");
 for (i = 0; i < len; i++) {
 for (j = i + 1; j < len; j++) {
 if (str[i] == str[j]) {
 printf("%c ", str[i]);
 break;
 }
 }
 }
 printf("\n");

 return 0;
}

Palindrome String Check (No strrev)
#include <stdio.h>
#include <string.h>

int main() {
 char str[100];
 int i, len, flag = 1;

 printf("Enter a string: ");
 scanf("%s", str);

 len = strlen(str);

 for (i = 0; i < len/2; i++) {
 if (str[i] != str[len-i-1]) {
 flag = 0;
 break;
 }
 }

 if (flag) {
 printf("%s is a palindrome", str);
 } else {
 printf("%s is not a palindrome", str);
 }
 return 0;
}

Reverse a String
#include <stdio.h>
#include <string.h>

int main() {
 char str[100];
 int i, len;
 char temp;

 printf("Enter a string: ");
 scanf("%s", str);

 len = strlen(str);

 for (i = 0; i < len/2; i++) {
 temp = str[i];
 str[i] = str[len - i - 1];
 str[len - i - 1] = temp;
 }

 printf("Reversed string: %s\n", str);
 return 0;
}