AI Coding & CSE Fundamentals
🚀 Explore AI, Coding & Computer Science Fundamentals. 💻 Programming • DSA • DBMS • OS • Networks 🤖 AI & Emerging Technologies 🛠️ Projects • Tutorials • Learning Resources 📚 Your freedom to gain knowledge for free.
Show more📈 Analytical overview of Telegram channel AI Coding & CSE Fundamentals
Channel AI Coding & CSE Fundamentals (@aicoding_csefundamentals) in the English language segment is an active participant. Currently, the community unites 12 324 subscribers, ranking 10 232 in the Technologies & Applications category and 31 271 in the India region.
📊 Audience metrics and dynamics
Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 12 324 subscribers.
According to the latest data from 12 November, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -238 over the last 30 days and by -8 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 10.45%. Within the first 24 hours after publication, content typically collects N/A% reactions from the total number of subscribers.
- Post reach: On average, each post receives 1 288 views. Within the first day, a publication typically gains 0 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 11.
- Thematic interests: Content is focused on key topics such as input, string, scanf("%d, array, element.
📝 Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
“🚀 Explore AI, Coding & Computer Science Fundamentals.
💻 Programming • DSA • DBMS • OS • Networks
🤖 AI & Emerging Technologies
🛠️ Projects • Tutorials • Learning Resources
📚 Your freedom to gain knowledge for free.”
Thanks to the high frequency of updates (latest data received on 13 November, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.
#include <stdio.h>
int main() {
printf("Hello, World!\n");
return 0;
}
Step 3: Save the File: Save the file with a .c extension, for example, hello.c. Choose a location where you can easily find it (e.g., your desktop).
Step 4: Open a Command Prompt/Terminal: Open the command prompt (Windows) or terminal (macOS/Linux).
Step 5: Navigate to the Directory: Use the cd command to navigate to the directory where you saved the hello.c file. For example, if you saved it on your desktop, you might use cd Desktop (Windows) or cd ~/Desktop (macOS/Linux).
Step 6: Compile the Code: Use a C compiler (like GCC) to compile the code. Type the following command and press Enter: gcc hello.c -o hello (This creates an executable file named "hello"). If you are on Windows and GCC is not recognized, you might need to configure your system's PATH environment variable to include the directory where GCC is installed.
Step 7: Run the Executable: Execute the compiled program.
On Windows, type hello.exe and press Enter.
On macOS/Linux, type ./hello and press Enter.
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❤️ Understood | 👎 Not Understood#include <stdio.h>
#include <string.h>
int main() {
char str[100];
int count = 0, i;
printf("Enter a sentence: ");
fgets(str, sizeof(str), stdin);
for (i = 0; str[i] != '\0'; i++) {
if (str[i] == ' ') {
count++;
}
}
if (strlen(str) > 1) {
count++;
}
printf("Number of words: %d\n", count);
return 0;
}#include <stdio.h>
#include <string.h>
#include <ctype.h>
int isPangram(const char *str) {
int alphabet[26] = {0};
int index;
int i;
for (i = 0; str[i] != '\0'; i++) {
if (isalpha(str[i])) {
index = tolower(str[i]) - 'a';
alphabet[index] = 1;
}
}
for (i = 0; i < 26; i++) {
if (alphabet[i] == 0) {
return 0;
}
}
return 1;
}
int main() {
char str[100];
fgets(str, sizeof(str), stdin);
str[strcspn(str, "\n")] = 0;
if (isPangram(str)) {
printf("Pangram\n");
} else {
printf("Not a Pangram\n");
}
return 0;
}#include <stdio.h>
#include <string.h>
#include <ctype.h>
void capitalize(char str[]) {
int i = 0;
if (str[i] != '\0') {
str[i] = toupper(str[i]);
i++;
}
while (str[i] != '\0') {
if (str[i-1] == ' ') {
str[i] = toupper(str[i]);
}
i++;
}
}
int main() {
char sentence[100];
printf("Enter a sentence: ");
fgets(sentence, sizeof(sentence), stdin);
sentence[strcspn(sentence, "\n")] = 0;
capitalize(sentence);
printf("Capitalized sentence: %s\n", sentence);
return 0;
}#include <stdio.h>
#include <string.h>
int main() {
char sentence[100];
char word[50];
char longest[50] = "";
int i, j, len, maxLen = 0;
printf("Enter a sentence: ");
fgets(sentence, sizeof(sentence), stdin);
sentence[strcspn(sentence, "\n")] = 0;
len = strlen(sentence);
j = 0;
for (i = 0; i <= len; i++) {
if (sentence[i] == ' ' || sentence[i] == '\0') {
word[j] = '\0';
if (strlen(word) > maxLen) {
maxLen = strlen(word);
strcpy(longest, word);
}
j = 0;
} else {
word[j++] = sentence[i];
}
}
printf("Longest word: %s\n", longest);
return 0;
}#include <stdio.h>
#include <string.h>
int main() {
char str[100], result[100];
int i, j, k = 0, len;
int found;
printf("Enter a string: ");
fgets(str, sizeof(str), stdin);
str[strcspn(str, "\n")] = 0;
len = strlen(str);
for (i = 0; i < len; i++) {
found = 0;
for (j = 0; j < k; j++) {
if (str[i] == result[j]) {
found = 1;
break;
}
}
if (!found) {
result[k++] = str[i];
}
}
result[k] = '\0';
printf("String with unique characters: %s\n", result);
return 0;
}#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main() {
char str[100];
int i, len, flag = 1;
scanf("%s", str);
len = strlen(str);
for (i = 0; i < len; i++) {
if (!isdigit(str[i])) {
flag = 0;
break;
}
}
if (flag == 1) {
printf("Yes");
} else {
printf("No");
}
return 0;
}#include <stdio.h>
#include <string.h>
int main() {
char str[100];
int freq[256] = {0};
int i, max = 0, ascii;
printf("Enter a string: ");
fgets(str, sizeof(str), stdin);
str[strcspn(str, "\n")] = 0;
for (i = 0; str[i] != '\0'; i++) {
ascii = (int)str[i];
freq[ascii]++;
}
for (i = 0; i < 256; i++) {
if (freq[i] > freq[max]) {
max = i;
}
}
printf("Most frequent character: %c\n", (char)max);
printf("Frequency: %d\n", freq[max]);
return 0;
}#include <stdio.h>
#include <string.h>
int main() {
char str[100];
int freq[256] = {0};
int i;
printf("Enter a string: ");
fgets(str, sizeof(str), stdin);
str[strcspn(str, "\n")] = 0;
for (i = 0; str[i] != '\0'; i++) {
freq[str[i]]++;
}
printf("Character frequencies:\n");
for (i = 0; i < 256; i++) {
if (freq[i] != 0) {
printf("'%c': %d\n", i, freq[i]);
}
}
return 0;
}#include <stdio.h>
#include <string.h>
#include <stdbool.h>
bool areRotations(char *str1, char *str2) {
int n = strlen(str1);
int m = strlen(str2);
if (n != m) return false;
char temp[2 * n + 1];
strcpy(temp, str1);
strcat(temp, str1);
if (strstr(temp, str2) != NULL) return true;
return false;
}
int main() {
char str1[] = "ABCD";
char str2[] = "CDAB";
if (areRotations(str1, str2))
printf("Strings are rotations of each other");
else
printf("Strings are not rotations of each other");
return 0;
}#include <stdio.h>
#include <string.h>
char findFirstNonRepeating(const char *str) {
int counts[256] = {0};
int len = strlen(str);
for (int i = 0; i < len; i++) {
counts[(unsigned char)str[i]]++;
}
for (int i = 0; i < len; i++) {
if (counts[(unsigned char)str[i]] == 1) {
return str[i];
}
}
return '\0';
}
int main() {
char str[] = "programming";
char result = findFirstNonRepeating(str);
if (result != '\0') {
printf("First non-repeating char: %c\n", result);
} else {
printf("No non-repeating character found.\n");
}
return 0;
}#include <stdio.h>
#include <string.h>
#include <stdbool.h>
bool areAnagrams(char str1[], char str2[]) {
int n1 = strlen(str1);
int n2 = strlen(str2);
if (n1 != n2)
return false;
int count[256] = {0};
for (int i = 0; str1[i] && str2[i]; i++) {
count[str1[i]]++;
count[str2[i]]--;
}
for (int i = 0; i < 256; i++)
if (count[i])
return false;
return true;
}
int main() {
char str1[100], str2[100];
printf("Enter first string: ");
scanf("%s", str1);
printf("Enter second string: ");
scanf("%s", str2);
if (areAnagrams(str1, str2))
printf("\"%s\" and \"%s\" are anagrams\n", str1, str2);
else
printf("\"%s\" and \"%s\" are not anagrams\n", str1, str2);
return 0;
}#include <stdio.h>
#include <string.h>
int main() {
char str[100];
int i, j, len;
printf("Enter a string: ");
fgets(str, sizeof(str), stdin);
str[strcspn(str, "\n")] = 0;
len = strlen(str);
printf("Duplicate characters are: ");
for (i = 0; i < len; i++) {
for (j = i + 1; j < len; j++) {
if (str[i] == str[j]) {
printf("%c ", str[i]);
break;
}
}
}
printf("\n");
return 0;
}