C Programming Language || Hands On Coding
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Hands-on C programming language challenges for beginners. Learn building logic by solving programs. Owner: @Pradeep_saii
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频道 C Programming Language || Hands On Coding (@c_programming_language_coding) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 12 821 名订阅者,在 技术与应用 类别中位列第 9 572,并在 印度 地区排名第 31 202 位。
📊 受众指标与增长动态
自 невідомо 创建以来,项目保持高速增长,吸引了 12 821 名订阅者。
根据 28 八月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -213,过去 24 小时变化为 -1,整体触达仍然可观。
- 认证状态: 未认证
- 互动率 (ER): 平均受众互动率为 6.87%。内容发布后 24 小时内通常能获得 2.42% 的反应,占订阅者总量。
- 帖子覆盖: 每篇帖子平均可获得 881 次浏览,首日通常累积 310 次浏览。
- 互动与反馈: 受众积极参与,单帖平均反应数为 2。
- 主题关注点: 内容集中在 input, string, scanf("%d, array, element 等核心主题上。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台:
“Hands-on C programming language challenges for beginners. Learn building logic by solving programs.
Owner: @Pradeep_saii”
凭借高频更新(最新数据采集于 29 八月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。
12 821
订阅者
-124 小时
-297 天
-21330 天
帖子存档
📚 1. Absolute Fundamentals: Setting Up & Basic Interaction
🚀 Welcome to the C Programming Programs Channel!
Welcome to the C Programming Programs Channel, your structured path to mastering C and building rock-solid problem-solving skills.
We provide a simple, powerful learning plan: over 500 practical programs that guide you from foundational syntax to advanced data structures and algorithms.
For the best experience, we recommend using a PC.
Note: The problems sent in the channel are carefully selected to challenge your skills and prepare you for real-world scenarios.
Stay Updated & Share
Join the channel to get access to all the problems:
https://t.me/c_programming_language_programss
Share and support your fellow coders!
Happy Coding! 🎉
Count Words in a Sentence
#include <stdio.h>
#include <string.h>
int main() {
char str[100];
int count = 0, i;
printf("Enter a sentence: ");
fgets(str, sizeof(str), stdin);
for (i = 0; str[i] != '\0'; i++) {
if (str[i] == ' ') {
count++;
}
}
if (strlen(str) > 1) {
count++;
}
printf("Number of words: %d\n", count);
return 0;
}Pangram Checker
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int isPangram(const char *str) {
int alphabet[26] = {0};
int index;
int i;
for (i = 0; str[i] != '\0'; i++) {
if (isalpha(str[i])) {
index = tolower(str[i]) - 'a';
alphabet[index] = 1;
}
}
for (i = 0; i < 26; i++) {
if (alphabet[i] == 0) {
return 0;
}
}
return 1;
}
int main() {
char str[100];
fgets(str, sizeof(str), stdin);
str[strcspn(str, "\n")] = 0;
if (isPangram(str)) {
printf("Pangram\n");
} else {
printf("Not a Pangram\n");
}
return 0;
}🔥 Solve LeetCode problems consistently in a structured path.
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Capitalize First Letter of Words in a Sentence
#include <stdio.h>
#include <string.h>
#include <ctype.h>
void capitalize(char str[]) {
int i = 0;
if (str[i] != '\0') {
str[i] = toupper(str[i]);
i++;
}
while (str[i] != '\0') {
if (str[i-1] == ' ') {
str[i] = toupper(str[i]);
}
i++;
}
}
int main() {
char sentence[100];
printf("Enter a sentence: ");
fgets(sentence, sizeof(sentence), stdin);
sentence[strcspn(sentence, "\n")] = 0;
capitalize(sentence);
printf("Capitalized sentence: %s\n", sentence);
return 0;
}Longest Word in a Sentence
#include <stdio.h>
#include <string.h>
int main() {
char sentence[100];
char word[50];
char longest[50] = "";
int i, j, len, maxLen = 0;
printf("Enter a sentence: ");
fgets(sentence, sizeof(sentence), stdin);
sentence[strcspn(sentence, "\n")] = 0;
len = strlen(sentence);
j = 0;
for (i = 0; i <= len; i++) {
if (sentence[i] == ' ' || sentence[i] == '\0') {
word[j] = '\0';
if (strlen(word) > maxLen) {
maxLen = strlen(word);
strcpy(longest, word);
}
j = 0;
} else {
word[j++] = sentence[i];
}
}
printf("Longest word: %s\n", longest);
return 0;
}Remove Repeated Characters from a String
#include <stdio.h>
#include <string.h>
int main() {
char str[100], result[100];
int i, j, k = 0, len;
int found;
printf("Enter a string: ");
fgets(str, sizeof(str), stdin);
str[strcspn(str, "\n")] = 0;
len = strlen(str);
for (i = 0; i < len; i++) {
found = 0;
for (j = 0; j < k; j++) {
if (str[i] == result[j]) {
found = 1;
break;
}
}
if (!found) {
result[k++] = str[i];
}
}
result[k] = '\0';
printf("String with unique characters: %s\n", result);
return 0;
}String Contains Only Digits
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main() {
char str[100];
int i, len, flag = 1;
scanf("%s", str);
len = strlen(str);
for (i = 0; i < len; i++) {
if (!isdigit(str[i])) {
flag = 0;
break;
}
}
if (flag == 1) {
printf("Yes");
} else {
printf("No");
}
return 0;
}Find Most Frequent Character in a String
#include <stdio.h>
#include <string.h>
int main() {
char str[100];
int freq[256] = {0};
int i, max = 0, ascii;
printf("Enter a string: ");
fgets(str, sizeof(str), stdin);
str[strcspn(str, "\n")] = 0;
for (i = 0; str[i] != '\0'; i++) {
ascii = (int)str[i];
freq[ascii]++;
}
for (i = 0; i < 256; i++) {
if (freq[i] > freq[max]) {
max = i;
}
}
printf("Most frequent character: %c\n", (char)max);
printf("Frequency: %d\n", freq[max]);
return 0;
}🔥Solve LeetCode Problems Daily
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Repost from C Programming Language || Hands On Coding
🔥Solve LeetCode Problems Daily
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Character Frequency in String
#include <stdio.h>
#include <string.h>
int main() {
char str[100];
int freq[256] = {0};
int i;
printf("Enter a string: ");
fgets(str, sizeof(str), stdin);
str[strcspn(str, "\n")] = 0;
for (i = 0; str[i] != '\0'; i++) {
freq[str[i]]++;
}
printf("Character frequencies:\n");
for (i = 0; i < 256; i++) {
if (freq[i] != 0) {
printf("'%c': %d\n", i, freq[i]);
}
}
return 0;
}String Rotation Check
#include <stdio.h>
#include <string.h>
#include <stdbool.h>
bool areRotations(char *str1, char *str2) {
int n = strlen(str1);
int m = strlen(str2);
if (n != m) return false;
char temp[2 * n + 1];
strcpy(temp, str1);
strcat(temp, str1);
if (strstr(temp, str2) != NULL) return true;
return false;
}
int main() {
char str1[] = "ABCD";
char str2[] = "CDAB";
if (areRotations(str1, str2))
printf("Strings are rotations of each other");
else
printf("Strings are not rotations of each other");
return 0;
}First Non-Repeating Character in a String
#include <stdio.h>
#include <string.h>
char findFirstNonRepeating(const char *str) {
int counts[256] = {0};
int len = strlen(str);
for (int i = 0; i < len; i++) {
counts[(unsigned char)str[i]]++;
}
for (int i = 0; i < len; i++) {
if (counts[(unsigned char)str[i]] == 1) {
return str[i];
}
}
return '\0';
}
int main() {
char str[] = "programming";
char result = findFirstNonRepeating(str);
if (result != '\0') {
printf("First non-repeating char: %c\n", result);
} else {
printf("No non-repeating character found.\n");
}
return 0;
}Anagram String Checker
#include <stdio.h>
#include <string.h>
#include <stdbool.h>
bool areAnagrams(char str1[], char str2[]) {
int n1 = strlen(str1);
int n2 = strlen(str2);
if (n1 != n2)
return false;
int count[256] = {0};
for (int i = 0; str1[i] && str2[i]; i++) {
count[str1[i]]++;
count[str2[i]]--;
}
for (int i = 0; i < 256; i++)
if (count[i])
return false;
return true;
}
int main() {
char str1[100], str2[100];
printf("Enter first string: ");
scanf("%s", str1);
printf("Enter second string: ");
scanf("%s", str2);
if (areAnagrams(str1, str2))
printf("\"%s\" and \"%s\" are anagrams\n", str1, str2);
else
printf("\"%s\" and \"%s\" are not anagrams\n", str1, str2);
return 0;
}Find Duplicate Characters in a String
#include <stdio.h>
#include <string.h>
int main() {
char str[100];
int i, j, len;
printf("Enter a string: ");
fgets(str, sizeof(str), stdin);
str[strcspn(str, "\n")] = 0;
len = strlen(str);
printf("Duplicate characters are: ");
for (i = 0; i < len; i++) {
for (j = i + 1; j < len; j++) {
if (str[i] == str[j]) {
printf("%c ", str[i]);
break;
}
}
}
printf("\n");
return 0;
}Palindrome String Check (No strrev)
#include <stdio.h>
#include <string.h>
int main() {
char str[100];
int i, len, flag = 1;
printf("Enter a string: ");
scanf("%s", str);
len = strlen(str);
for (i = 0; i < len/2; i++) {
if (str[i] != str[len-i-1]) {
flag = 0;
break;
}
}
if (flag) {
printf("%s is a palindrome", str);
} else {
printf("%s is not a palindrome", str);
}
return 0;
}Reverse a String
#include <stdio.h>
#include <string.h>
int main() {
char str[100];
int i, len;
char temp;
printf("Enter a string: ");
scanf("%s", str);
len = strlen(str);
for (i = 0; i < len/2; i++) {
temp = str[i];
str[i] = str[len - i - 1];
str[len - i - 1] = temp;
}
printf("Reversed string: %s\n", str);
return 0;
}