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AI Coding & CSE Fundamentals

AI Coding & CSE Fundamentals

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πŸš€ Explore AI, Coding & Computer Science Fundamentals. πŸ’» Programming β€’ DSA β€’ DBMS β€’ OS β€’ Networks πŸ€– AI & Emerging Technologies πŸ› οΈ Projects β€’ Tutorials β€’ Learning Resources πŸ“š Your freedom to gain knowledge for free.

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πŸ“ˆ Analytical overview of Telegram channel AI Coding & CSE Fundamentals

Channel AI Coding & CSE Fundamentals (@aicoding_csefundamentals) in the English language segment is an active participant. Currently, the community unites 12 324 subscribers, ranking 10 232 in the Technologies & Applications category and 31 271 in the India region.

πŸ“Š Audience metrics and dynamics

Since its creation on Π½Π΅Π²Ρ–Π΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 12 324 subscribers.

According to the latest data from 12 November, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -238 over the last 30 days and by -8 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 10.45%. Within the first 24 hours after publication, content typically collects N/A% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 1 288 views. Within the first day, a publication typically gains 0 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 11.
  • Thematic interests: Content is focused on key topics such as input, string, scanf("%d, array, element.

πŸ“ Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
β€œπŸš€ Explore AI, Coding & Computer Science Fundamentals. πŸ’» Programming β€’ DSA β€’ DBMS β€’ OS β€’ Networks πŸ€– AI & Emerging Technologies πŸ› οΈ Projects β€’ Tutorials β€’ Learning Resources πŸ“š Your freedom to gain knowledge for free.”

Thanks to the high frequency of updates (latest data received on 13 November, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.

12 324
Subscribers
-824 hours
-827 days
-23830 days
Posts Archive
πŸš€100 Days of LeetCode 2025 Challenge started Join below channel to be part of this challenge πŸ”—https://t.me/+utZsK17rSXRmZWQ
πŸš€100 Days of LeetCode 2025 Challenge started Join below channel to be part of this challenge πŸ”—https://t.me/+utZsK17rSXRmZWQ1 ❌ Don't miss it guys, great channel in telegram for dsa

πŸ’» Check if Number is Divisible by 5
#include <stdio.h>

int main() {
    int number;

    printf("Enter an integer: ");
    scanf("%d", &number);

    if (number % 5 == 0) {
        printf("%d is divisible by 5n", number);
    } else {
        printf("%d is not divisible by 5n", number);
    }

    return 0;
}
πŸ“€ Output:
Input: 10
Output: 10 is divisible by 5

Input: 7
Output: 7 is not divisible by 5

πŸ’» Check if Temperature is Freezing
#include <stdio.h>

int main() {
  int temperature;

  printf("Enter the temperature in Celsius: ");
  scanf("%d", &temperature);

  if (temperature <= 0) {
    printf("The temperature is freezing.n");
  } else {
    printf("The temperature is not freezing.n");
  }

  return 0;
}
πŸ“€ Output:
Input: -5
Output: The temperature is freezing.

Input: 25
Output: The temperature is not freezing.

Input: 0
Output: The temperature is freezing.

πŸš€100 Days of LeetCode 2025 Challenge started Join below channel to be part of this challenge πŸ”—https://t.me/+utZsK17rSXRmZWQ
πŸš€100 Days of LeetCode 2025 Challenge started Join below channel to be part of this challenge πŸ”—https://t.me/+utZsK17rSXRmZWQ1

πŸ’» Check if Year is Leap Year
#include <stdio.h>

int main() {
    int year;

    printf("Enter a year: ");
    scanf("%d", &year);

    if (year % 4 == 0) {
        if (year % 100 == 0) {
            if (year % 400 == 0) {
                printf("%d is a leap year.n", year);
            } else {
                printf("%d is not a leap year.n", year);
            }
        } else {
            printf("%d is a leap year.n", year);
        }
    } else {
        printf("%d is not a leap year.n", year);
    }

    return 0;
}
πŸ“€ Output:
Input: 2024
Output: 2024 is a leap year.

Input: 2023
Output: 2023 is not a leap year.

Input: 1900
Output: 1900 is not a leap year.

Input: 2000
Output: 2000 is a leap year.

πŸ’» Check if Point is at Origin
#include <stdio.h>

int main() {
  int x, y;

  printf("Enter the x-coordinate: ");
  scanf("%d", &x);

  printf("Enter the y-coordinate: ");
  scanf("%d", &y);

  if (x == 0 && y == 0) {
    printf("The point is at the origin.n");
  } else {
    printf("The point is not at the origin.n");
  }

  return 0;
}
πŸ“€ Output:
Input: 0
Input: 0
Output: The point is at the origin.

Input: 1
Input: 2
Output: The point is not at the origin.

πŸ’» Check if Point Lies on Y-Axis
#include <stdio.h>

int main() {
  int x, y;

  printf("Enter the x-coordinate: ");
  scanf("%d", &x);

  printf("Enter the y-coordinate: ");
  scanf("%d", &y);

  if (x == 0) {
    printf("The point lies on the Y-axis.n");
  } else {
    printf("The point does not lie on the Y-axis.n");
  }

  return 0;
}
πŸ“€ Output:
Input: 0
Output: Enter the x-coordinate: Enter the y-coordinate: The point lies on the Y-axis.

Input: 5
Output: Enter the x-coordinate: Enter the y-coordinate: The point does not lie on the Y-axis.

πŸ’» Check if Point Lies on X-Axis
#include <stdio.h>

int main() {
  float x, y;

  printf("Enter the x-coordinate: ");
  scanf("%f", &x);

  printf("Enter the y-coordinate: ");
  scanf("%f", &y);

  if (y == 0) {
    printf("The point lies on the X-axis.n");
  } else {
    printf("The point does not lie on the X-axis.n");
  }

  return 0;
}
πŸ“€ Output:
Input: 5.0
Input: 0.0
Output: The point lies on the X-axis.

Input: 2.5
Input: 3.7
Output: The point does not lie on the X-axis.

πŸ’» Check if Character is Vowel
#include <stdio.h>
#include <ctype.h>

int main() {
    char ch;

    printf("Enter a character: ");
    scanf(" %c", &ch);

    ch = tolower(ch);

    if (ch == 'a' || ch == 'e' || ch == 'i' || ch == 'o' || ch == 'u') {
        printf("%c is a vowel.n", ch);
    } else {
        printf("%c is not a vowel.n", ch);
    }

    return 0;
}
πŸ“€ Output:
Input: A
Output: a is a vowel.

Input: b
Output: b is not a vowel.

Input: E
Output: e is a vowel.

Input: z
Output: z is not a vowel.

πŸ’» Check if Number is Even
#include <stdio.h>

int main() {
    int number;

    printf("Enter an integer: ");
    scanf("%d", &number);

    if (number % 2 == 0) {
        printf("%d is even.n", number);
    } else {
        printf("%d is odd.n", number);
    }

    return 0;
}
πŸ“€ Output:
Input: 4
Output: 4 is even.

Input: 7
Output: 7 is odd.

Input: 0
Output: 0 is even.

Input: -2
Output: -2 is even.

Input: -5
Output: -5 is odd.

πŸš€100 Days of LeetCode 2025 Challenge started Join below channel to be part of this challenge πŸ”—https://t.me/+utZsK17rSXRmZWQ
πŸš€100 Days of LeetCode 2025 Challenge started Join below channel to be part of this challenge πŸ”—https://t.me/+utZsK17rSXRmZWQ1

πŸ’» Check if Number is Positive
#include <stdio.h>

int main() {
    int num;

    printf("Enter a number: ");
    scanf("%d", &num);

    if (num > 0) {
        printf("The number is positive.n");
    }

    return 0;
}
πŸ“€ Output:
Input: 5
Output: Enter a number: The number is positive.

Input: -3
Output: Enter a number:

πŸ”§ Conditional Statements - Simple if

πŸ’» Swap First and Last Digits of a Number
#include <stdio.h>
#include <math.h>

int main() {
    int num, firstDigit, lastDigit, digits, tempNum, swappedNum;

    printf("Enter an integer: ");
    scanf("%d", &num);

    lastDigit = num % 10;
    tempNum = num;
    digits = 0;

    while (tempNum != 0) {
        tempNum /= 10;
        digits++;
    }

    firstDigit = num / pow(10, digits - 1);

    num -= firstDigit * pow(10, digits - 1);
    num += firstDigit;

    num -= lastDigit;
    num += lastDigit * pow(10, digits - 1);

    swappedNum = num;

    printf("Number after swapping first and last digit: %dn", swappedNum);

    return 0;
}
πŸ“€ Output:
Input: 12345
Output: Number after swapping first and last digit: 52341

Input: 678
Output: Number after swapping first and last digit: 876

Input: 9
Output: Number after swapping first and last digit: 9

Input: 2024
Output: Number after swapping first and last digit: 4022

πŸ’» Seconds to Hours:Minutes:Seconds Converter
#include <stdio.h>

int main() {
  int totalSeconds, hours, minutes, seconds;

  printf("Enter the total number of seconds: ");
  scanf("%d", &totalSeconds);

  hours = totalSeconds / 3600;
  minutes = (totalSeconds % 3600) / 60;
  seconds = totalSeconds % 60;

  printf("Hours: %dn", hours);
  printf("Minutes: %dn", minutes);
  printf("Seconds: %dn", seconds);

  return 0;
}
πŸ“€ Output:
Input: 3661
Output: Enter the total number of seconds: Hours: 1
Minutes: 1
Seconds: 1

Input: 86400
Output: Enter the total number of seconds: Hours: 24
Minutes: 0
Seconds: 0

Input: 59
Output: Enter the total number of seconds: Hours: 0
Minutes: 0
Seconds: 59

πŸ’» Calculate BMI (Body Mass Index)
#include <stdio.h>

int main() {
    float weight, height, bmi;

    printf("Enter weight in kilograms: ");
    scanf("%f", &weight);

    printf("Enter height in meters: ");
    scanf("%f", &height);

    bmi = weight / (height * height);

    printf("BMI = %.2fn", bmi);

    return 0;
}
πŸ“€ Output:
Input: 70
Input: 1.75
Output: BMI = 22.86

πŸ’» Print Your Name, Age, and Hobby
#include <stdio.h>

int main() {
    char name[50];
    int age;
    char hobby[100];

    printf("Enter your name: ");
    scanf("%s", name);

    printf("Enter your age: ");
    scanf("%d", &age);

    printf("Enter your hobby: ");
    scanf(" %[^n]s", hobby);

    printf("Name: %sn", name);
    printf("Age: %dn", age);
    printf("Hobby: %sn", hobby);

    return 0;
}
πŸ“€ Output:
Input: John Doe
Input: 30
Input: Playing the guitar
Output: Enter your name: Enter your age: Enter your hobby: Name: John
Age: 30
Hobby: Playing the guitar

πŸ’» Celsius to Fahrenheit Converter
#include <stdio.h>

int main() {
  float celsius, fahrenheit;

  printf("Enter temperature in Celsius: ");
  scanf("%f", &celsius);

  fahrenheit = (celsius * 9 / 5) + 32;

  printf("Temperature in Fahrenheit: %.2fn", fahrenheit);

  return 0;
}
πŸ“€ Output:
Input: 25
Output: Temperature in Fahrenheit: 77.00
Input: 0
Output: Temperature in Fahrenheit: 32.00
Input: -40
Output: Temperature in Fahrenheit: -40.00
Input: 100
Output: Temperature in Fahrenheit: 212.00

πŸ’» Fahrenheit to Celsius Converter
#include <stdio.h>

int main() {
  float fahrenheit, celsius;

  printf("Enter temperature in Fahrenheit: ");
  scanf("%f", &fahrenheit);

  celsius = (fahrenheit - 32) * 5.0 / 9.0;

  printf("Temperature in Celsius: %.2fn", celsius);

  return 0;
}
πŸ“€ Output:
Input: 212
Output: Temperature in Celsius: 100.00

Input: 32
Output: Temperature in Celsius: 0.00

Input: 98.6
Output: Temperature in Celsius: 37.00

πŸ’» Area of Rectangle Calculator
#include <stdio.h>

int main() {
    float length, width, area;

    printf("Enter the length of the rectangle: ");
    scanf("%f", &length);

    printf("Enter the width of the rectangle: ");
    scanf("%f", &width);

    area = length * width;

    printf("The area of the rectangle is: %fn", area);

    return 0;
}
πŸ“€ Output:
Input: 5.0
Input: 10.0
Output: The area of the rectangle is: 50.000000