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C Programming Codes

C Programming Codes

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C Programming Codes || Quizzes || DSA Learn along with the community Any queries admin - @Pradeep_saii

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πŸ“ˆ Analytical overview of Telegram channel C Programming Codes

Channel C Programming Codes (@c_programming_codes) in the English language segment is an active participant. Currently, the community unites 13 430 subscribers, ranking 9 534 in the Technologies & Applications category and 32 075 in the India region.

πŸ“Š Audience metrics and dynamics

Since its creation on Π½Π΅Π²Ρ–Π΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 13 430 subscribers.

According to the latest data from 11 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -239 over the last 30 days and by -9 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 9.78%. Within the first 24 hours after publication, content typically collects N/A% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 0 views. Within the first day, a publication typically gains 0 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 0.
  • Thematic interests: Content is focused on key topics such as input, string, scanf("%d, array, element.

πŸ“ Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
β€œC Programming Codes || Quizzes || DSA Learn along with the community Any queries admin - @Pradeep_saii”

Thanks to the high frequency of updates (latest data received on 12 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.

13 430
Subscribers
-924 hours
-577 days
-23930 days
Posts Archive
πŸ’» Check if Point Lies on Y-Axis
#include <stdio.h>

int main() {
  int x, y;

  printf("Enter the x-coordinate: ");
  scanf("%d", &x);

  printf("Enter the y-coordinate: ");
  scanf("%d", &y);

  if (x == 0) {
    printf("The point lies on the Y-axis.n");
  } else {
    printf("The point does not lie on the Y-axis.n");
  }

  return 0;
}
πŸ“€ Output:
Input: 0
Output: Enter the x-coordinate: Enter the y-coordinate: The point lies on the Y-axis.

Input: 5
Output: Enter the x-coordinate: Enter the y-coordinate: The point does not lie on the Y-axis.

πŸ’» Check if Point Lies on X-Axis
#include <stdio.h>

int main() {
  float x, y;

  printf("Enter the x-coordinate: ");
  scanf("%f", &x);

  printf("Enter the y-coordinate: ");
  scanf("%f", &y);

  if (y == 0) {
    printf("The point lies on the X-axis.n");
  } else {
    printf("The point does not lie on the X-axis.n");
  }

  return 0;
}
πŸ“€ Output:
Input: 5.0
Input: 0.0
Output: The point lies on the X-axis.

Input: 2.5
Input: 3.7
Output: The point does not lie on the X-axis.

πŸ’» Check if Character is Vowel
#include <stdio.h>
#include <ctype.h>

int main() {
    char ch;

    printf("Enter a character: ");
    scanf(" %c", &ch);

    ch = tolower(ch);

    if (ch == 'a' || ch == 'e' || ch == 'i' || ch == 'o' || ch == 'u') {
        printf("%c is a vowel.n", ch);
    } else {
        printf("%c is not a vowel.n", ch);
    }

    return 0;
}
πŸ“€ Output:
Input: A
Output: a is a vowel.

Input: b
Output: b is not a vowel.

Input: E
Output: e is a vowel.

Input: z
Output: z is not a vowel.

πŸ’» Check if Number is Even
#include <stdio.h>

int main() {
    int number;

    printf("Enter an integer: ");
    scanf("%d", &number);

    if (number % 2 == 0) {
        printf("%d is even.n", number);
    } else {
        printf("%d is odd.n", number);
    }

    return 0;
}
πŸ“€ Output:
Input: 4
Output: 4 is even.

Input: 7
Output: 7 is odd.

Input: 0
Output: 0 is even.

Input: -2
Output: -2 is even.

Input: -5
Output: -5 is odd.

πŸš€100 Days of LeetCode 2025 Challenge started Join below channel to be part of this challenge πŸ”—https://t.me/+utZsK17rSXRmZWQ
πŸš€100 Days of LeetCode 2025 Challenge started Join below channel to be part of this challenge πŸ”—https://t.me/+utZsK17rSXRmZWQ1

πŸ’» Check if Number is Positive
#include <stdio.h>

int main() {
    int num;

    printf("Enter a number: ");
    scanf("%d", &num);

    if (num > 0) {
        printf("The number is positive.n");
    }

    return 0;
}
πŸ“€ Output:
Input: 5
Output: Enter a number: The number is positive.

Input: -3
Output: Enter a number:

πŸ”§ Conditional Statements - Simple if

πŸ’» Swap First and Last Digits of a Number
#include <stdio.h>
#include <math.h>

int main() {
    int num, firstDigit, lastDigit, digits, tempNum, swappedNum;

    printf("Enter an integer: ");
    scanf("%d", &num);

    lastDigit = num % 10;
    tempNum = num;
    digits = 0;

    while (tempNum != 0) {
        tempNum /= 10;
        digits++;
    }

    firstDigit = num / pow(10, digits - 1);

    num -= firstDigit * pow(10, digits - 1);
    num += firstDigit;

    num -= lastDigit;
    num += lastDigit * pow(10, digits - 1);

    swappedNum = num;

    printf("Number after swapping first and last digit: %dn", swappedNum);

    return 0;
}
πŸ“€ Output:
Input: 12345
Output: Number after swapping first and last digit: 52341

Input: 678
Output: Number after swapping first and last digit: 876

Input: 9
Output: Number after swapping first and last digit: 9

Input: 2024
Output: Number after swapping first and last digit: 4022

πŸ’» Seconds to Hours:Minutes:Seconds Converter
#include <stdio.h>

int main() {
  int totalSeconds, hours, minutes, seconds;

  printf("Enter the total number of seconds: ");
  scanf("%d", &totalSeconds);

  hours = totalSeconds / 3600;
  minutes = (totalSeconds % 3600) / 60;
  seconds = totalSeconds % 60;

  printf("Hours: %dn", hours);
  printf("Minutes: %dn", minutes);
  printf("Seconds: %dn", seconds);

  return 0;
}
πŸ“€ Output:
Input: 3661
Output: Enter the total number of seconds: Hours: 1
Minutes: 1
Seconds: 1

Input: 86400
Output: Enter the total number of seconds: Hours: 24
Minutes: 0
Seconds: 0

Input: 59
Output: Enter the total number of seconds: Hours: 0
Minutes: 0
Seconds: 59

πŸ’» Calculate BMI (Body Mass Index)
#include <stdio.h>

int main() {
    float weight, height, bmi;

    printf("Enter weight in kilograms: ");
    scanf("%f", &weight);

    printf("Enter height in meters: ");
    scanf("%f", &height);

    bmi = weight / (height * height);

    printf("BMI = %.2fn", bmi);

    return 0;
}
πŸ“€ Output:
Input: 70
Input: 1.75
Output: BMI = 22.86

πŸ’» Print Your Name, Age, and Hobby
#include <stdio.h>

int main() {
    char name[50];
    int age;
    char hobby[100];

    printf("Enter your name: ");
    scanf("%s", name);

    printf("Enter your age: ");
    scanf("%d", &age);

    printf("Enter your hobby: ");
    scanf(" %[^n]s", hobby);

    printf("Name: %sn", name);
    printf("Age: %dn", age);
    printf("Hobby: %sn", hobby);

    return 0;
}
πŸ“€ Output:
Input: John Doe
Input: 30
Input: Playing the guitar
Output: Enter your name: Enter your age: Enter your hobby: Name: John
Age: 30
Hobby: Playing the guitar

πŸ’» Celsius to Fahrenheit Converter
#include <stdio.h>

int main() {
  float celsius, fahrenheit;

  printf("Enter temperature in Celsius: ");
  scanf("%f", &celsius);

  fahrenheit = (celsius * 9 / 5) + 32;

  printf("Temperature in Fahrenheit: %.2fn", fahrenheit);

  return 0;
}
πŸ“€ Output:
Input: 25
Output: Temperature in Fahrenheit: 77.00
Input: 0
Output: Temperature in Fahrenheit: 32.00
Input: -40
Output: Temperature in Fahrenheit: -40.00
Input: 100
Output: Temperature in Fahrenheit: 212.00

πŸ’» Fahrenheit to Celsius Converter
#include <stdio.h>

int main() {
  float fahrenheit, celsius;

  printf("Enter temperature in Fahrenheit: ");
  scanf("%f", &fahrenheit);

  celsius = (fahrenheit - 32) * 5.0 / 9.0;

  printf("Temperature in Celsius: %.2fn", celsius);

  return 0;
}
πŸ“€ Output:
Input: 212
Output: Temperature in Celsius: 100.00

Input: 32
Output: Temperature in Celsius: 0.00

Input: 98.6
Output: Temperature in Celsius: 37.00

πŸ’» Area of Rectangle Calculator
#include <stdio.h>

int main() {
    float length, width, area;

    printf("Enter the length of the rectangle: ");
    scanf("%f", &length);

    printf("Enter the width of the rectangle: ");
    scanf("%f", &width);

    area = length * width;

    printf("The area of the rectangle is: %fn", area);

    return 0;
}
πŸ“€ Output:
Input: 5.0
Input: 10.0
Output: The area of the rectangle is: 50.000000

πŸš€100 Days of LeetCode 2025 Challenge started Join below channel to be part of this challenge πŸ”—https://t.me/+utZsK17rSXRmZWQ
πŸš€100 Days of LeetCode 2025 Challenge started Join below channel to be part of this challenge πŸ”—https://t.me/+utZsK17rSXRmZWQ1

πŸ’» Area of Circle Calculator
#include <stdio.h>

int main() {
    float radius, area;
    const float PI = 3.14159;

    printf("Enter the radius of the circle: ");
    scanf("%f", &radius);

    area = PI * radius * radius;

    printf("The area of the circle is: %fn", area);

    return 0;
}
πŸ“€ Output:
Input: 5
Output: Enter the radius of the circle: The area of the circle is: 78.539757

Input: 2.5
Output: Enter the radius of the circle: The area of the circle is: 19.634938

πŸ’» Compound Interest Calculator
#include <stdio.h>
#include <math.h>

int main() {
  float principal, rate, time, compound_interest, amount;
  int compounding_frequency;

  printf("Enter principal amount: ");
  scanf("%f", &principal);

  printf("Enter annual interest rate (as a decimal, e.g., 0.05 for 5%%): ");
  scanf("%f", &rate);

  printf("Enter time in years: ");
  scanf("%f", &time);

  printf("Enter compounding frequency (e.g., 1 for annually, 12 for monthly): ");
  scanf("%d", &compounding_frequency);

  amount = principal * pow(1 + (rate / compounding_frequency), compounding_frequency * time);
  compound_interest = amount - principal;

  printf("Compound Interest: %.2fn", compound_interest);

  return 0;
}
πŸ“€ Output:
Enter principal amount: 1000
Input: 1000
Enter annual interest rate (as a decimal, e.g., 0.05 for 5%): 0.05
Input: 0.05
Enter time in years: 5
Input: 5
Enter compounding frequency (e.g., 1 for annually, 12 for monthly): 1
Input: 1
Compound Interest: 276.28

πŸ’» Simple Interest Calculator
#include <stdio.h>

int main() {
  float principal, rate, time, interest;

  printf("Enter principal amount: ");
  scanf("%f", &principal);

  printf("Enter rate of interest: ");
  scanf("%f", &rate);

  printf("Enter time in years: ");
  scanf("%f", &time);

  interest = (principal * rate * time) / 100;

  printf("Simple Interest = %fn", interest);

  return 0;
}
πŸ“€ Output:
Input: 1000
Input: 5
Input: 2
Output: Simple Interest = 100.000000

πŸ’» Variable Swapping (Three Variables)
#include <stdio.h>

int main() {
  int a, b, c, temp;

  printf("Enter the values of a, b, and c: ");
  scanf("%d %d %d", &a, &b, &c);

  printf("Before swapping: a = %d, b = %d, c = %dn", a, b, c);

  temp = a;
  a = b;
  b = c;
  c = temp;

  printf("After swapping: a = %d, b = %d, c = %dn", a, b, c);

  return 0;
}
πŸ“€ Output:
Input: 10 20 30
Output: Enter the values of a, b, and c: Before swapping: a = 10, b = 20, c = 30
After swapping: a = 20, b = 30, c = 10

πŸš€100 Days of LeetCode 2025 Challenge started Join below channel to be part of this challenge πŸ”—https://t.me/+utZsK17rSXRmZWQ
πŸš€100 Days of LeetCode 2025 Challenge started Join below channel to be part of this challenge πŸ”—https://t.me/+utZsK17rSXRmZWQ1