ar
Feedback

لا تقع ضحية للمخادعين! تيليمتريو يكتشف ويُميّز هذه القنوات 👉 إذا كنت تريد رؤية العلامة، اشترك

AI Coding & CSE Fundamentals

AI Coding & CSE Fundamentals

الذهاب إلى القناة على Telegram

🚀 Explore AI, Coding & Computer Science Fundamentals. 💻 Programming • DSA • DBMS • OS • Networks 🤖 AI & Emerging Technologies 🛠️ Projects • Tutorials • Learning Resources 📚 Your freedom to gain knowledge for free.

إظهار المزيد

📈 نظرة تحليلية على قناة تيليجرام AI Coding & CSE Fundamentals

تُعد قناة AI Coding & CSE Fundamentals (@aicoding_csefundamentals) في القطاع اللغوي الإنكليزية لاعباً نشطاً. يضم المجتمع حالياً 12 324 مشتركاً، محتلاً المرتبة 10 232 في فئة التكنولوجيات والتطبيقات والمرتبة 31 271 في منطقة الهند.

📊 مؤشرات الجمهور والحراك

منذ تأسيسه في невідомо، حقق المشروع نمواً سريعاً وجمع 12 324 مشتركاً.

بحسب آخر البيانات بتاريخ 12 نوفمبر, 2026، تحافظ القناة على نشاط مستقر. خلال آخر 30 يوماً تغيّر عدد الأعضاء بمقدار -238، وفي آخر 24 ساعة بمقدار -8، مع بقاء الوصول العام مرتفعاً.

  • حالة التحقق: غير موثّقة
  • معدل التفاعل (ER): يبلغ متوسط تفاعل الجمهور 10.45‎%. وخلال أول 24 ساعة من النشر يحصد المحتوى عادةً N/A‎% من ردود الفعل نسبةً إلى إجمالي المشتركين.
  • وصول المنشورات: يحصل كل منشور على متوسط 1 288 مشاهدة. وخلال اليوم الأول يجمع عادةً 0 مشاهدة.
  • التفاعلات والاستجابة: يتفاعل الجمهور بانتظام؛ متوسط التفاعلات لكل منشور يبلغ 11.
  • الاهتمامات الموضوعية: يركز المحتوى على مواضيع رئيسية مثل input, string, scanf("%d, array, element.

📝 الوصف وسياسة المحتوى

يصف المؤلف القناة بأنها مساحة للتعبير عن الآراء الذاتية:
“🚀 Explore AI, Coding & Computer Science Fundamentals. 💻 Programming • DSA • DBMS • OS • Networks 🤖 AI & Emerging Technologies 🛠️ Projects • Tutorials • Learning Resources 📚 Your freedom to gain knowledge for free.”

بفضل وتيرة التحديث المرتفعة (أحدث البيانات بتاريخ 13 نوفمبر, 2026) تحافظ القناة على حداثتها ومستوى وصول مرتفع. وتُظهر التحليلات تفاعلاً نشطاً من الجمهور، ما يجعلها نقطة تأثير مهمة ضمن فئة التكنولوجيات والتطبيقات.

12 324
المشتركون
-824 ساعات
-827 أيام
-23830 أيام
أرشيف المشاركات
🚀100 Days of LeetCode 2025 Challenge started Join below channel to be part of this challenge 🔗https://t.me/+utZsK17rSXRmZWQ
🚀100 Days of LeetCode 2025 Challenge started Join below channel to be part of this challenge 🔗https://t.me/+utZsK17rSXRmZWQ1 ❌ Don't miss it guys, great channel in telegram for dsa

💻 Check if Number is Divisible by 5
#include <stdio.h>

int main() {
    int number;

    printf("Enter an integer: ");
    scanf("%d", &number);

    if (number % 5 == 0) {
        printf("%d is divisible by 5n", number);
    } else {
        printf("%d is not divisible by 5n", number);
    }

    return 0;
}
📤 Output:
Input: 10
Output: 10 is divisible by 5

Input: 7
Output: 7 is not divisible by 5

💻 Check if Temperature is Freezing
#include <stdio.h>

int main() {
  int temperature;

  printf("Enter the temperature in Celsius: ");
  scanf("%d", &temperature);

  if (temperature <= 0) {
    printf("The temperature is freezing.n");
  } else {
    printf("The temperature is not freezing.n");
  }

  return 0;
}
📤 Output:
Input: -5
Output: The temperature is freezing.

Input: 25
Output: The temperature is not freezing.

Input: 0
Output: The temperature is freezing.

🚀100 Days of LeetCode 2025 Challenge started Join below channel to be part of this challenge 🔗https://t.me/+utZsK17rSXRmZWQ
🚀100 Days of LeetCode 2025 Challenge started Join below channel to be part of this challenge 🔗https://t.me/+utZsK17rSXRmZWQ1

💻 Check if Year is Leap Year
#include <stdio.h>

int main() {
    int year;

    printf("Enter a year: ");
    scanf("%d", &year);

    if (year % 4 == 0) {
        if (year % 100 == 0) {
            if (year % 400 == 0) {
                printf("%d is a leap year.n", year);
            } else {
                printf("%d is not a leap year.n", year);
            }
        } else {
            printf("%d is a leap year.n", year);
        }
    } else {
        printf("%d is not a leap year.n", year);
    }

    return 0;
}
📤 Output:
Input: 2024
Output: 2024 is a leap year.

Input: 2023
Output: 2023 is not a leap year.

Input: 1900
Output: 1900 is not a leap year.

Input: 2000
Output: 2000 is a leap year.

💻 Check if Point is at Origin
#include <stdio.h>

int main() {
  int x, y;

  printf("Enter the x-coordinate: ");
  scanf("%d", &x);

  printf("Enter the y-coordinate: ");
  scanf("%d", &y);

  if (x == 0 && y == 0) {
    printf("The point is at the origin.n");
  } else {
    printf("The point is not at the origin.n");
  }

  return 0;
}
📤 Output:
Input: 0
Input: 0
Output: The point is at the origin.

Input: 1
Input: 2
Output: The point is not at the origin.

💻 Check if Point Lies on Y-Axis
#include <stdio.h>

int main() {
  int x, y;

  printf("Enter the x-coordinate: ");
  scanf("%d", &x);

  printf("Enter the y-coordinate: ");
  scanf("%d", &y);

  if (x == 0) {
    printf("The point lies on the Y-axis.n");
  } else {
    printf("The point does not lie on the Y-axis.n");
  }

  return 0;
}
📤 Output:
Input: 0
Output: Enter the x-coordinate: Enter the y-coordinate: The point lies on the Y-axis.

Input: 5
Output: Enter the x-coordinate: Enter the y-coordinate: The point does not lie on the Y-axis.

💻 Check if Point Lies on X-Axis
#include <stdio.h>

int main() {
  float x, y;

  printf("Enter the x-coordinate: ");
  scanf("%f", &x);

  printf("Enter the y-coordinate: ");
  scanf("%f", &y);

  if (y == 0) {
    printf("The point lies on the X-axis.n");
  } else {
    printf("The point does not lie on the X-axis.n");
  }

  return 0;
}
📤 Output:
Input: 5.0
Input: 0.0
Output: The point lies on the X-axis.

Input: 2.5
Input: 3.7
Output: The point does not lie on the X-axis.

💻 Check if Character is Vowel
#include <stdio.h>
#include <ctype.h>

int main() {
    char ch;

    printf("Enter a character: ");
    scanf(" %c", &ch);

    ch = tolower(ch);

    if (ch == 'a' || ch == 'e' || ch == 'i' || ch == 'o' || ch == 'u') {
        printf("%c is a vowel.n", ch);
    } else {
        printf("%c is not a vowel.n", ch);
    }

    return 0;
}
📤 Output:
Input: A
Output: a is a vowel.

Input: b
Output: b is not a vowel.

Input: E
Output: e is a vowel.

Input: z
Output: z is not a vowel.

💻 Check if Number is Even
#include <stdio.h>

int main() {
    int number;

    printf("Enter an integer: ");
    scanf("%d", &number);

    if (number % 2 == 0) {
        printf("%d is even.n", number);
    } else {
        printf("%d is odd.n", number);
    }

    return 0;
}
📤 Output:
Input: 4
Output: 4 is even.

Input: 7
Output: 7 is odd.

Input: 0
Output: 0 is even.

Input: -2
Output: -2 is even.

Input: -5
Output: -5 is odd.

🚀100 Days of LeetCode 2025 Challenge started Join below channel to be part of this challenge 🔗https://t.me/+utZsK17rSXRmZWQ
🚀100 Days of LeetCode 2025 Challenge started Join below channel to be part of this challenge 🔗https://t.me/+utZsK17rSXRmZWQ1

💻 Check if Number is Positive
#include <stdio.h>

int main() {
    int num;

    printf("Enter a number: ");
    scanf("%d", &num);

    if (num > 0) {
        printf("The number is positive.n");
    }

    return 0;
}
📤 Output:
Input: 5
Output: Enter a number: The number is positive.

Input: -3
Output: Enter a number:

🔧 Conditional Statements - Simple if

💻 Swap First and Last Digits of a Number
#include <stdio.h>
#include <math.h>

int main() {
    int num, firstDigit, lastDigit, digits, tempNum, swappedNum;

    printf("Enter an integer: ");
    scanf("%d", &num);

    lastDigit = num % 10;
    tempNum = num;
    digits = 0;

    while (tempNum != 0) {
        tempNum /= 10;
        digits++;
    }

    firstDigit = num / pow(10, digits - 1);

    num -= firstDigit * pow(10, digits - 1);
    num += firstDigit;

    num -= lastDigit;
    num += lastDigit * pow(10, digits - 1);

    swappedNum = num;

    printf("Number after swapping first and last digit: %dn", swappedNum);

    return 0;
}
📤 Output:
Input: 12345
Output: Number after swapping first and last digit: 52341

Input: 678
Output: Number after swapping first and last digit: 876

Input: 9
Output: Number after swapping first and last digit: 9

Input: 2024
Output: Number after swapping first and last digit: 4022

💻 Seconds to Hours:Minutes:Seconds Converter
#include <stdio.h>

int main() {
  int totalSeconds, hours, minutes, seconds;

  printf("Enter the total number of seconds: ");
  scanf("%d", &totalSeconds);

  hours = totalSeconds / 3600;
  minutes = (totalSeconds % 3600) / 60;
  seconds = totalSeconds % 60;

  printf("Hours: %dn", hours);
  printf("Minutes: %dn", minutes);
  printf("Seconds: %dn", seconds);

  return 0;
}
📤 Output:
Input: 3661
Output: Enter the total number of seconds: Hours: 1
Minutes: 1
Seconds: 1

Input: 86400
Output: Enter the total number of seconds: Hours: 24
Minutes: 0
Seconds: 0

Input: 59
Output: Enter the total number of seconds: Hours: 0
Minutes: 0
Seconds: 59

💻 Calculate BMI (Body Mass Index)
#include <stdio.h>

int main() {
    float weight, height, bmi;

    printf("Enter weight in kilograms: ");
    scanf("%f", &weight);

    printf("Enter height in meters: ");
    scanf("%f", &height);

    bmi = weight / (height * height);

    printf("BMI = %.2fn", bmi);

    return 0;
}
📤 Output:
Input: 70
Input: 1.75
Output: BMI = 22.86

💻 Print Your Name, Age, and Hobby
#include <stdio.h>

int main() {
    char name[50];
    int age;
    char hobby[100];

    printf("Enter your name: ");
    scanf("%s", name);

    printf("Enter your age: ");
    scanf("%d", &age);

    printf("Enter your hobby: ");
    scanf(" %[^n]s", hobby);

    printf("Name: %sn", name);
    printf("Age: %dn", age);
    printf("Hobby: %sn", hobby);

    return 0;
}
📤 Output:
Input: John Doe
Input: 30
Input: Playing the guitar
Output: Enter your name: Enter your age: Enter your hobby: Name: John
Age: 30
Hobby: Playing the guitar

💻 Celsius to Fahrenheit Converter
#include <stdio.h>

int main() {
  float celsius, fahrenheit;

  printf("Enter temperature in Celsius: ");
  scanf("%f", &celsius);

  fahrenheit = (celsius * 9 / 5) + 32;

  printf("Temperature in Fahrenheit: %.2fn", fahrenheit);

  return 0;
}
📤 Output:
Input: 25
Output: Temperature in Fahrenheit: 77.00
Input: 0
Output: Temperature in Fahrenheit: 32.00
Input: -40
Output: Temperature in Fahrenheit: -40.00
Input: 100
Output: Temperature in Fahrenheit: 212.00

💻 Fahrenheit to Celsius Converter
#include <stdio.h>

int main() {
  float fahrenheit, celsius;

  printf("Enter temperature in Fahrenheit: ");
  scanf("%f", &fahrenheit);

  celsius = (fahrenheit - 32) * 5.0 / 9.0;

  printf("Temperature in Celsius: %.2fn", celsius);

  return 0;
}
📤 Output:
Input: 212
Output: Temperature in Celsius: 100.00

Input: 32
Output: Temperature in Celsius: 0.00

Input: 98.6
Output: Temperature in Celsius: 37.00

💻 Area of Rectangle Calculator
#include <stdio.h>

int main() {
    float length, width, area;

    printf("Enter the length of the rectangle: ");
    scanf("%f", &length);

    printf("Enter the width of the rectangle: ");
    scanf("%f", &width);

    area = length * width;

    printf("The area of the rectangle is: %fn", area);

    return 0;
}
📤 Output:
Input: 5.0
Input: 10.0
Output: The area of the rectangle is: 50.000000