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C Programming Codes

C Programming Codes

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C Programming Codes || Quizzes || DSA Learn along with the community Any queries admin - @Pradeep_saii

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πŸ“ˆ Analytical overview of Telegram channel C Programming Codes

Channel C Programming Codes (@c_programming_codes) in the English language segment is an active participant. Currently, the community unites 13 430 subscribers, ranking 9 534 in the Technologies & Applications category and 32 075 in the India region.

πŸ“Š Audience metrics and dynamics

Since its creation on Π½Π΅Π²Ρ–Π΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 13 430 subscribers.

According to the latest data from 11 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -239 over the last 30 days and by -9 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 9.78%. Within the first 24 hours after publication, content typically collects N/A% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 0 views. Within the first day, a publication typically gains 0 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 0.
  • Thematic interests: Content is focused on key topics such as input, string, scanf("%d, array, element.

πŸ“ Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
β€œC Programming Codes || Quizzes || DSA Learn along with the community Any queries admin - @Pradeep_saii”

Thanks to the high frequency of updates (latest data received on 12 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.

13 430
Subscribers
-924 hours
-577 days
-23930 days
Posts Archive
πŸ’» Check if String Starts with Vowel
#include <stdio.h>
#include <string.h>
#include <ctype.h>

int main() {
    char str[100];

    printf("Enter a string: ");
    scanf("%s", str);

    char firstChar = tolower(str[0]);

    if (firstChar == 'a' || firstChar == 'e' || firstChar == 'i' || firstChar == 'o' || firstChar == 'u') {
        printf("String starts with a vowel.n");
    } else {
        printf("String does not start with a vowel.n");
    }

    return 0;
}
πŸ“€ Output:
Input: apple
Output: String starts with a vowel.

Input: Banana
Output: String does not start with a vowel.

Input: Example
Output: String starts with a vowel.

Input: orange
Output: String starts with a vowel.

Input: umbrella
Output: String starts with a vowel.

Input: Test
Output: String does not start with a vowel.

πŸ’» Check if Number is Palindrome
#include <stdio.h>

int main() {
    int n, reversedInteger = 0, remainder, originalInteger;

    printf("Enter an integer: ");
    scanf("%d", &n);

    originalInteger = n;

    while (n != 0) {
        remainder = n % 10;
        reversedInteger = reversedInteger * 10 + remainder;
        n /= 10;
    }

    if (originalInteger == reversedInteger)
        printf("%d is a palindrome.", originalInteger);
    else
        printf("%d is not a palindrome.", originalInteger);

    return 0;
}
πŸ“€ Output:
Input: 121
Output: 121 is a palindrome.

Input: 123
Output: 123 is not a palindrome.

Input: 3553
Output: 3553 is a palindrome.

Input: 12345
Output: 12345 is not a palindrome.

πŸ’» Check if Character is Uppercase or Lowercase
#include <stdio.h>

int main() {
  char ch;

  printf("Enter a character: ");
  scanf(" %c", &ch);

  if (ch >= 'A' && ch <= 'Z') {
    printf("%c is an uppercase character.n", ch);
  } else if (ch >= 'a' && ch <= 'z') {
    printf("%c is a lowercase character.n", ch);
  } else {
    printf("%c is not an alphabet.n", ch);
  }

  return 0;
}
πŸ“€ Output:
Input: G
Output: Enter a character: G is an uppercase character.

Input: g
Output: Enter a character: g is a lowercase character.

Input: 5
Output: Enter a character: 5 is not an alphabet.

πŸ’» Check if Triangle is Valid
#include <stdio.h>

int main() {
    int side1, side2, side3;

    printf("Enter the lengths of three sides of a triangle: ");
    scanf("%d %d %d", &side1, &side2, &side3);

    if (side1 + side2 > side3 && side1 + side3 > side2 && side2 + side3 > side1) {
        printf("Triangle is valid.n");
    } else {
        printf("Triangle is not valid.n");
    }

    return 0;
}
πŸ“€ Output:
Input: 3 4 5
Output: Triangle is valid.

Input: 1 2 5
Output: Triangle is not valid.

Input: 7 10 5
Output: Triangle is valid.

πŸ’» Check if Number is Prime
#include <stdio.h>
#include <stdbool.h>

int main() {
  int num, i;
  bool isPrime = true;

  printf("Enter a positive integer: ");
  scanf("%d", &num);

  if (num <= 1) {
    isPrime = false;
  } else {
    for (i = 2; i <= num / 2; ++i) {
      if (num % i == 0) {
        isPrime = false;
        break; // Exit the loop if not prime
      }
    }
  }

  if (isPrime) {
    printf("%d is a prime number.n", num);
  } else {
    printf("%d is not a prime number.n", num);
  }

  return 0;
}
πŸ“€ Output:
Input: 7
Output: 7 is a prime number.

Input: 12
Output: 12 is not a prime number.

Input: 1
Output: 1 is not a prime number.

Input: 2
Output: 2 is a prime number.

Input: 0
Output: 0 is not a prime number.

Input: -5
Output: -5 is not a prime number.

πŸ’» Check if Person is Eligible to Vote
#include <stdio.h>

int main() {
    int age;

    printf("Enter your age: ");
    scanf("%d", &age);

    if (age >= 18) {
        printf("You are eligible to vote!n");
    } else {
        printf("You are not eligible to vote yet.n");
    }

    return 0;
}
πŸ“€ Output:
Input: 25
Output: Enter your age: You are eligible to vote!

Input: 16
Output: Enter your age: You are not eligible to vote yet.

πŸ’» Check Profit or Loss from Cost and Sell Price
#include <stdio.h>

int main() {
  float costPrice, sellingPrice, profit, loss;

  printf("Enter cost price: ");
  scanf("%f", &costPrice);

  printf("Enter selling price: ");
  scanf("%f", &sellingPrice);

  if (sellingPrice > costPrice) {
    profit = sellingPrice - costPrice;
    printf("Profit: %.2fn", profit);
  } else if (costPrice > sellingPrice) {
    loss = costPrice - sellingPrice;
    printf("Loss: %.2fn", loss);
  } else {
    printf("No profit, no loss.n");
  }

  return 0;
}
πŸ“€ Output:
Input: 100.00
Input: 120.00
Output: Profit: 20.00

Input: 100.00
Input: 80.00
Output: Loss: 20.00

Input: 100.00
Input: 100.00
Output: No profit, no loss.

πŸ’» Check if Character is Alphabet or Digit
#include <stdio.h>

int main() {
    char ch;

    printf("Enter a character: ");
    scanf(" %c", &ch);

    if ((ch >= 'a' && ch <= 'z') || (ch >= 'A' && ch <= 'Z')) {
        printf("%c is an alphabet.n", ch);
    } else if (ch >= '0' && ch <= '9') {
        printf("%c is a digit.n", ch);
    } else {
        printf("%c is not an alphabet or a digit.n", ch);
    }

    return 0;
}
πŸ“€ Output:
Input: A
Output: Enter a character: A is an alphabet.

Input: 5
Output: Enter a character: 5 is a digit.

Input: $
Output: Enter a character: $ is not an alphabet or a digit.

πŸ’» Check if Number is Even or Odd
#include <stdio.h>

int main() {
    int number;

    printf("Enter an integer: ");
    scanf("%d", &number);

    if (number % 2 == 0) {
        printf("%d is even.n", number);
    } else {
        printf("%d is odd.n", number);
    }

    return 0;
}
πŸ“€ Output:
Input: 7
Output: 7 is odd.

Input: 12
Output: 12 is even.

Input: 0
Output: 0 is even.

Input: -5
Output: -5 is odd.

Input: -8
Output: -8 is even.

πŸ’» Check if Number is Positive or Negative
#include <stdio.h>

int main() {
    int number;

    printf("Enter an integer: ");
    scanf("%d", &number);

    if (number > 0) {
        printf("The number is positive.n");
    } else if (number < 0) {
        printf("The number is negative.n");
    } else {
        printf("The number is zero.n");
    }

    return 0;
}
πŸ“€ Output:
Input: 5
Output: The number is positive.

Input: -3
Output: The number is negative.

Input: 0
Output: The number is zero.

πŸ”§ Conditional Statements - if-else

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πŸš€100 Days of LeetCode 2025 Challenge started Join below channel to be part of this challenge πŸ”—https://t.me/+utZsK17rSXRmZWQ1 ❌ Don't miss it guys, great channel in telegram for dsa

πŸ’» Check if String is Empty
#include <stdio.h>
#include <string.h>

int main() {
    char str[100];
    printf("Enter a string: ");
    scanf("%s", str);

    if (strlen(str) == 0) {
        printf("The string is empty.n");
    } else {
        printf("The string is not empty.n");
    }

    return 0;
}
πŸ“€ Output:
Input: hello
Output: The string is not empty.

Input:
Output: The string is empty.

Input: abcdefghijklmnopqrstuvwxyz
Output: The string is not empty.

πŸš€100 Days of LeetCode 2025 Challenge started Join below channel to be part of this challenge πŸ”—https://t.me/+utZsK17rSXRmZWQ
πŸš€100 Days of LeetCode 2025 Challenge started Join below channel to be part of this challenge πŸ”—https://t.me/+utZsK17rSXRmZWQ1 ❌ Don't miss it guys, great channel in telegram for dsa

πŸ’» Check if Number is Divisible by 5
#include <stdio.h>

int main() {
    int number;

    printf("Enter an integer: ");
    scanf("%d", &number);

    if (number % 5 == 0) {
        printf("%d is divisible by 5n", number);
    } else {
        printf("%d is not divisible by 5n", number);
    }

    return 0;
}
πŸ“€ Output:
Input: 10
Output: 10 is divisible by 5

Input: 7
Output: 7 is not divisible by 5

πŸ’» Check if Temperature is Freezing
#include <stdio.h>

int main() {
  int temperature;

  printf("Enter the temperature in Celsius: ");
  scanf("%d", &temperature);

  if (temperature <= 0) {
    printf("The temperature is freezing.n");
  } else {
    printf("The temperature is not freezing.n");
  }

  return 0;
}
πŸ“€ Output:
Input: -5
Output: The temperature is freezing.

Input: 25
Output: The temperature is not freezing.

Input: 0
Output: The temperature is freezing.

πŸš€100 Days of LeetCode 2025 Challenge started Join below channel to be part of this challenge πŸ”—https://t.me/+utZsK17rSXRmZWQ
πŸš€100 Days of LeetCode 2025 Challenge started Join below channel to be part of this challenge πŸ”—https://t.me/+utZsK17rSXRmZWQ1

πŸ’» Check if Year is Leap Year
#include <stdio.h>

int main() {
    int year;

    printf("Enter a year: ");
    scanf("%d", &year);

    if (year % 4 == 0) {
        if (year % 100 == 0) {
            if (year % 400 == 0) {
                printf("%d is a leap year.n", year);
            } else {
                printf("%d is not a leap year.n", year);
            }
        } else {
            printf("%d is a leap year.n", year);
        }
    } else {
        printf("%d is not a leap year.n", year);
    }

    return 0;
}
πŸ“€ Output:
Input: 2024
Output: 2024 is a leap year.

Input: 2023
Output: 2023 is not a leap year.

Input: 1900
Output: 1900 is not a leap year.

Input: 2000
Output: 2000 is a leap year.

πŸ’» Check if Point is at Origin
#include <stdio.h>

int main() {
  int x, y;

  printf("Enter the x-coordinate: ");
  scanf("%d", &x);

  printf("Enter the y-coordinate: ");
  scanf("%d", &y);

  if (x == 0 && y == 0) {
    printf("The point is at the origin.n");
  } else {
    printf("The point is not at the origin.n");
  }

  return 0;
}
πŸ“€ Output:
Input: 0
Input: 0
Output: The point is at the origin.

Input: 1
Input: 2
Output: The point is not at the origin.