C Programming Language || Hands On Coding
Hands-on C programming language challenges for beginners. Learn building logic by solving programs. Owner: @Pradeep_saii
Show moreπ Analytical overview of Telegram channel C Programming Language || Hands On Coding
Channel C Programming Language || Hands On Coding (@c_programming_language_coding) in the English language segment is an active participant. Currently, the community unites 12 794 subscribers, ranking 9 613 in the Technologies & Applications category and 31 064 in the India region.
π Audience metrics and dynamics
Since its creation on Π½Π΅Π²ΡΠ΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 12 794 subscribers.
According to the latest data from 01 September, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -213 over the last 30 days and by -5 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 8.32%. Within the first 24 hours after publication, content typically collects 2.42% reactions from the total number of subscribers.
- Post reach: On average, each post receives 1 064 views. Within the first day, a publication typically gains 310 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 3.
- Thematic interests: Content is focused on key topics such as input, string, scanf("%d, array, element.
π Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
βHands-on C programming language challenges for beginners. Learn building logic by solving programs.
Owner: @Pradeep_saiiβ
Thanks to the high frequency of updates (latest data received on 02 September, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.
class Solution {
public:
void moveZeroes(vector<int>& nums) {
if (nums.size() < 2) {
return;
}
int leftIdx = 0, rightIdx = 1;
while (rightIdx < nums.size()) {
if (nums[leftIdx] != 0) {
leftIdx++;
rightIdx++;
}
else if (nums[rightIdx] == 0) {
rightIdx++;
}
else {
swap(nums[leftIdx], nums[rightIdx]);
}
}
}
};