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AI Coding & CSE Fundamentals

AI Coding & CSE Fundamentals

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πŸš€ Explore AI, Coding & Computer Science Fundamentals. πŸ’» Programming β€’ DSA β€’ DBMS β€’ OS β€’ Networks πŸ€– AI & Emerging Technologies πŸ› οΈ Projects β€’ Tutorials β€’ Learning Resources πŸ“š Your freedom to gain knowledge for free.

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πŸ“ˆ Analytical overview of Telegram channel AI Coding & CSE Fundamentals

Channel AI Coding & CSE Fundamentals (@aicoding_csefundamentals) in the English language segment is an active participant. Currently, the community unites 12 318 subscribers, ranking 10 235 in the Technologies & Applications category and 31 257 in the India region.

πŸ“Š Audience metrics and dynamics

Since its creation on Π½Π΅Π²Ρ–Π΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 12 318 subscribers.

According to the latest data from 13 November, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -236 over the last 30 days and by -9 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 10.85%. Within the first 24 hours after publication, content typically collects N/A% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 1 337 views. Within the first day, a publication typically gains 0 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 11.
  • Thematic interests: Content is focused on key topics such as input, string, scanf("%d, array, element.

πŸ“ Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
β€œπŸš€ Explore AI, Coding & Computer Science Fundamentals. πŸ’» Programming β€’ DSA β€’ DBMS β€’ OS β€’ Networks πŸ€– AI & Emerging Technologies πŸ› οΈ Projects β€’ Tutorials β€’ Learning Resources πŸ“š Your freedom to gain knowledge for free.”

Thanks to the high frequency of updates (latest data received on 14 November, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.

12 318
Subscribers
-924 hours
-837 days
-23630 days
Posts Archive
Unlock a world of free educational content, expert-led courses, and skill-building resources β€” all designed to empower you, g
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Leetcode 283: https://leetcode.com/problems/move-zeroes/
class Solution {
public:
    void moveZeroes(vector<int>& nums) {
        if (nums.size() < 2) {
            return;
        }
        
        int leftIdx = 0, rightIdx = 1;
        
        while (rightIdx < nums.size()) {
            if (nums[leftIdx] != 0) {
                leftIdx++;
                rightIdx++;
            } 
            else if (nums[rightIdx] == 0) {
                rightIdx++;
            } 
            else {
                swap(nums[leftIdx], nums[rightIdx]);
            }
        }
    }
};

Leetcode 66: https://leetcode.com/problems/plus-one/
class Solution {
public:
    std::vector<int> plusOne(std::vector<int>& digits) {
        int currentIndex = digits.size() - 1;
        
        while (digits[currentIndex] == 9) {
            if (currentIndex == 0) {
                std::vector<int> resultArr(digits.size() + 1, 0);
                resultArr[0] = 1;
                return resultArr;
            }
            digits[currentIndex] = 0;
            currentIndex--;
        }

        digits[currentIndex]++;
        return digits;
    }
};

Leetcode 350: https://leetcode.com/problems/intersection-of-two-arrays-ii/
class Solution {
public:
    std::vector<int> intersect(std::vector<int>& nums1, std::vector<int>& nums2) {
        std::unordered_map<int, int> numsMap;
        std::vector<int> intersectedNums;

        for (int num : nums1) {
            numsMap[num]++;
        }

        for (int num : nums2) {
            if (numsMap.find(num) != numsMap.end() && numsMap[num] > 0) {
                intersectedNums.push_back(num);
                numsMap[num]--;
                if (numsMap[num] == 0) {
                    numsMap.erase(num);
                }
            }
        }

        return intersectedNums;
    }
};

Leetcode 136: https://leetcode.com/problems/single-number/
class Solution {
public:
    int singleNumber(vector<int>& nums) {
        int finder = 0;
        for(int i = 0; i < nums.size(); i++) {
            finder = finder ^ nums[i];
        }
        return finder;
    }
};

Leetcode 217: https://leetcode.com/problems/contains-duplicate/description/
#include <vector>
#include <algorithm>

class Solution {
public:
    bool containsDuplicate(std::vector<int>& nums) {
        std::sort(nums.begin(), nums.end());
        for (size_t i = 0; i < nums.size() - 1; i++) {
            if (nums[i] == nums[i + 1]) {
                return true;
            }
        }
        return false;
    }
};

Leetcode 189: https://leetcode.com/problems/rotate-array/
#include <vector>
#include <iostream>

class Solution {
public:
    void rotate(std::vector<int>& nums, int k) {
        k = k % nums.size();
        // Reversing the whole array
        reverseNumsArr(nums, 0, nums.size());
        // Reversing first k elements
        reverseNumsArr(nums, 0, k);
        // Reversing remaining elements
        reverseNumsArr(nums, k, nums.size());
    }

private:
    void reverseNumsArr(std::vector<int>& nums, int start, int end) {
        end--; // Adjusting end to be the last index
        while (start < end) {
            std::swap(nums[start], nums[end]);
            start++;
            end--;
        }
    }
};

Leetcode 122: https://leetcode.com/problems/best-time-to-buy-and-sell-stock-ii/
class Solution {
public:
    int maxProfit(vector<int>& prices) {
        int maxProfit = 0;
        for(int i = 0; i < prices.size() - 1; i++) {
            if(prices[i] < prices[i + 1]) {
                int diff = prices[i + 1] - prices[i];
                maxProfit += diff;
            }
        }
        return maxProfit;
    }
};

Leetcode 26: https://leetcode.com/problems/remove-duplicates-from-sorted-array/description/
class Solution {
public:
    int removeDuplicates(vector<int>& nums) {
        int lastUniqueElementIdx = 0;

        for (int i = 1; i < nums.size(); i++) {
            if (nums[lastUniqueElementIdx] != nums[i]) {
                nums[lastUniqueElementIdx + 1] = nums[i];
                lastUniqueElementIdx++;
            }
        }
        return lastUniqueElementIdx + 1;
    }
};

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Program: Searching in a 2D array.
#include <iostream>
using namespace std;

int* search(int arr[][3], int rows, int cols, int target) {
    static int result[2]; 
    result[0] = -1;
    result[1] = -1;

    for (int i = 0; i < rows; i++) {
        for (int j = 0; j < cols; j++) {
            if (arr[i][j] == target) {
                result[0] = i;
                result[1] = j;
                return result; 
            }
        }
    }
    return result; 
}

int main() {
    int arr[3][3] = {
        {20, 45, 10},
        {32, 26, 22},
        {47, 98, 37}
    };

    int target;
    cout << "Enter target element: ";
    cin >> target;

    int* result = search(arr, 3, 3, target);
    
    if (result[0] != -1) {
        cout << "Element found at index (" << result[0] << "," << result[1] << ")" << endl;
    } else {
        cout << "Element not found" << endl;
    }

    return 0;
}
#linearsearch

Program: Finding maximum element from an array.
#include <iostream>
using namespace std;

int findMax(int arr[], int size) {
    int max = arr[0];
    for (int i = 1; i < size; i++) {
        if (arr[i] > max) {
            max = arr[i];
        }
    }
    return max;
}

int main() {
    int arr[] = {12, 32, 23, 11, 39};
    int size = sizeof(arr) / sizeof(arr[0]);
    int maxNumber = findMax(arr, size);
    cout << "Maximum number in array: " << maxNumber << endl;
    return 0;
}

Program: Finding minimum element in an array.
#include <iostream>
using namespace std;

int findMin(int arr[], int size) {
    int min = arr[0];
    for (int i = 1; i < size; i++) {
        if (arr[i] < min) {
            min = arr[i];
        }
    }
    return min;
}

int main() {
    int arr[] = {12, 32, 23, 11, 39};
    int size = sizeof(arr) / sizeof(arr[0]);
    int minNumber = findMin(arr, size);
    cout << "Minimum number in array: " << minNumber << endl;
    return 0;
}

Program: Searching for a character in specified range.
#include <iostream>
#include <string>

using namespace std;

int searchInStr(const string &str, char ch, int start, int end) {
    for (int i = start; i <= end; i++) {
        if (str[i] == ch) {
            return i;
        }
    }
    return -1;
}

int main() {
    string str = "Java Programming";
    char ch;
    int start, end;
    
    cout << "Enter character to search: ";
    cin >> ch;
    
    cout << "Enter the range,\n";
    cout << "Enter the start index: ";
    cin >> start;
    cout << "Enter the end index: ";
    cin >> end;
    
    int res = searchInStr(str, ch, start, end);
    
    if (res == -1) {
        cout << "Character not found in the specified range" << endl;
    } else {
        cout << "Character is at index " << res << endl;
    }
    
    return 0;
}

Program: Searching for first occurrence of a character in a string.
#include <iostream>
using namespace std;

int searchInStr(string str, char ch) {
    for (int i = 0; i < str.length(); i++) {
        if (str[i] == ch) {
            return i;
        }
    }
    return -1;
}

int main() {
    string str = "Java Programming";
    char ch;
    cout << "Enter character to search: ";
    cin >> ch;
    int res = searchInStr(str, ch);
    if (res == -1) {
        cout << "Character not found in the String" << endl;
    } else {
        cout << "Character is at index " << res << endl;
    }
    return 0;
}

Program: Reversing of an Array.
#include <iostream>
#include <vector>
using namespace std;

void reverseArray(vector<int>& arr) {
    int n = arr.size();
    for (int i = 0; i < n / 2; i++) {
        swap(arr[i], arr[n - 1 - i]);
    }
}

int main() {
    vector<int> arr = {1, 2, 3, 4, 5, 6};
    reverseArray(arr);

    for (size_t i = 0; i < arr.size(); i++) {
        cout << arr[i] << " ";
    }
    cout << endl;

    return 0;
}

Program : Finding Maximum element in an Array.
#include <iostream>
using namespace std;

int findMax(int arr[], int size) {
    int maxElem = arr[0];
    for(int i = 1; i < size; i++) {
        if(maxElem < arr[i]) {
            maxElem = arr[i];
        }
    }
    return maxElem;
}

int main() {
    int arr[] = {10, 5, 1, 3, 6};
    int size = sizeof(arr) / sizeof(arr[0]);
    int maxElem = findMax(arr, size);
    cout << "Maximum Element : " << maxElem << endl;
    return 0;
}

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Program : Armstrong or Not
#include <iostream>
#include <cmath> 
using namespace std;

bool isArmstrong(int num) {
    int originalNum = num, sum = 0, digits = to_string(num).length();
    while (num > 0) {
        int rem = num % 10;
        sum += pow(rem, digits); 
        num /= 10;
    }
    return originalNum == sum;
}

int main() {
    int num;
    cout << "Enter any number: ";
    cin >> num;

    if (isArmstrong(num)) {
        cout << num << " is an Armstrong number." << endl;
    } else {
        cout << num << " is not an Armstrong number." << endl;
    }
    return 0;
}

Program : Prime or Not
#include <iostream>
using namespace std;

bool isPrime(int num) {
    if (num < 2) {
        return false;
    }
    for (int i = 2; i * i <= num; i++) {
        if (num % i == 0) {
            return false;
        }
    }
    return true;
}

int main() {
    int num;
    cout << "Enter any number: ";
    cin >> num;
    if (isPrime(num)) {
        cout << num << " is a prime number" << endl;
    } else {
        cout << num << " is not a prime number" << endl;
    }
    return 0;
}