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allcoding1

allcoding1

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📈 Analytical overview of Telegram channel allcoding1

Channel allcoding1 (@allcoding1) in the English language segment is an active participant. Currently, the community unites 22 575 subscribers, ranking 8 822 in the Education category and 19 518 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 22 575 subscribers.

According to the latest data from 12 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -437 over the last 30 days and by -6 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 5.99%. Within the first 24 hours after publication, content typically collects 1.25% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 1 353 views. Within the first day, a publication typically gains 283 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
  • Thematic interests: Content is focused on key topics such as dsa, stack, namaste, javascript, learning.

📝 Description and content policy

Channel description not provided.

Thanks to the high frequency of updates (latest data received on 13 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

22 575
Subscribers
-624 hours
-967 days
-43730 days
Posts Archive
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Work
+8
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources English , 🇫🇷 All courses (100 rupees) Contact:- @meterials_available

int solve(vector tc) {     int n = tc.size();     vector p(n), s(n);     p[0] =
int solve(vector tc) {     int n = tc.size();     vector p(n), s(n);     p[0] = tc[0];     for (int i = 1; i < n; ++i) {         p[i] = p[i - 1] + tc[i];     }     s[n - 1] = tc[n - 1];     for (int i = n - 2; i >= 0; --i) {         s[i] = s[i + 1] + tc[i];     }     int m = max(p[0], s[0]);     for (int i = 1; i < n; ++i) {         m = max(m, max(p[i], s[i]));     }     return m; } Amazon

#include #include #include using namespace std; long getkRepValue(string user_history, long k) { &nbsp;&nbsp;&nbsp; long n =
#include <iostream> #include <string> #include <unordered_map> using namespace std; long getkRepValue(string user_history, long k) {     long n = user_history.size();     unordered_map<char, long> count;     long left = 0, right = 0, ans = 0;     while (right < n) {         count[user_history[right]]++;         while (count[user_history[right]] >= k && left <= right) {             ans += n - right;             count[user_history[left]]--;             left++;         }         right++;     }     return ans; }  Machine learning Amazon

📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Work
+8
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources English , 🇫🇷 All courses (100 rupees) Contact:- @meterials_available

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class Message(object): def init(self, message: str, sender: int, receiver: int) -> None: self.message = message self.sender =
class Message(object):     def init(self, message: str, sender: int, receiver: int) -> None:         self.message = message         self.sender = sender         self.receiver = receiver     def str(self) -> str:         return self.message     def eq(self, other: object) -> bool:         if not isinstance(other, Message):             return False         return self.message == other.message Message Objects

#include <iostream> #include <sstream> #include <string> #include <vector> std::string stemmer(const std::string& text) {     std::stringstream ss(text);     std::string word;     std::vector<std::string> stemmed_words;     while (ss >> word) {         if (word.size() > 2 && (word.substr(word.size() - 2) == "ed" word.substr(word.size() - 2) == "ly" word.substr(word.size() - 3) == "ing")) {             word = word.substr(0, word.size() - 2);         }         if (word.size() > 8) {             word = word.substr(0, 8);         }         stemmed_words.push_back(word);     }     std::string result;     for (const std::string& stemmed_word : stemmed_words) {         result += stemmed_word + " ";     }     result.pop_back();     return result; } int main() {     std::string text = "an extremely dangerous dog is barking";     std::cout << stemmer(text) << std::endl;  // Output: "an extreme dangerou dog is bark"     return 0; } Suffix stripping stemmer Telegram:- @allcoding1

Paid Promotion:- @Priya_i

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heights = [int(i) for i in input().split()] freq_dict = {} for h in heights: if h in freq_dict: freq_dict[h] += 1 else: freq_
heights = [int(i) for i in input().split()] freq_dict = {} for h in heights: if h in freq_dict:   freq_dict[h] += 1 else:   freq_dict[h] = 1 for h in sorted(freq_dict): print(h, freq_dict[h])

#include <iostream> #include <string> #include <vector> using namespace std; int numDecodings(string msg) {     int MOD = 1000000007;     int n = msg.size();         vector<long long> dp(n + 1, 0);     dp[0] = 1;         if (msg[0] == '0')         dp[1] = 0;     else if (msg[0] == '*')         dp[1] = 9;     else         dp[1] = 1;         for (int i = 2; i <= n; ++i) {         if (msg[i - 1] == '0') {                         if (msg[i - 2] == '1' || msg[i - 2] == '2')                 dp[i] += dp[i - 2];             else if (msg[i - 2] == '*')                 dp[i] += 2 * dp[i - 2];         } else if (msg[i - 1] >= '1' && msg[i - 1] <= '9') {                   dp[i] += dp[i - 1];                         if (msg[i - 2] == '1' || (msg[i - 2] == '2' && msg[i - 1] <= '6'))                 dp[i] += dp[i - 2];             else if (msg[i - 2] == '*') {                                 if (msg[i - 1] <= '6')                     dp[i] += 2 * dp[i - 2];                 else                     dp[i] += dp[i - 2];             }         } else if (msg[i - 1] == '*') {             dp[i] += 9 * dp[i - 1];                         if (msg[i - 2] == '1')                 dp[i] += 9 * dp[i - 2];             else if (msg[i - 2] == '2')                 dp[i] += 6 * dp[i - 2];             else if (msg[i - 2] == '*')                 dp[i] += 15 * dp[i - 2];         }                 dp[i] %= MOD;     }         return dp[n]; } Number of ways decode

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import re a = int(input().strip()) b = set() c = r'\b[A-Za-z0-9._%+-]+@[A-Za-z0-9.-]+\.[A-Z|a-z]{2,}\b' for _ in range(a): li
import re a = int(input().strip()) b = set() c = r'\b[A-Za-z0-9._%+-]+@[A-Za-z0-9.-]+\.[A-Z|a-z]{2,}\b' for _ in range(a):     line = input().strip()     b.update(re.findall(c, line)) print(';'.join(sorted(b)))

int solve(int k, vector&amp; s) { &nbsp;&nbsp;&nbsp; sort(s.rbegin(), s.rend()); &nbsp;&nbsp;&nbsp; int c = 0; &nbsp;&nbsp;&n
int solve(int k, vector<int>& s) {     sort(s.rbegin(), s.rend());     int c = 0;     for (int i = 0; i < s.size(); i++) {         if (i < k && s[i] > 0) {             c++;         } else if (s[i] == s[i - 1] && s[i] > 0) {             c++;         } else {             break;         }     }     return c; } Competitive Gaming Accenture exam Telegram:- @allcoding1

#include <iostream> #include <vector> #include <algorithm> using namespace std; int findLIS(vector<int>& s) {     vector<int> tails;     for (int x : s) {         auto it = lower_bound(tails.begin(), tails.end(), x);         if (it == tails.end()) {             tails.push_back(x);         } else {             *it = x;         }     }     return tails.size(); }   Swiggy LIS