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allcoding1

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allcoding1 (@allcoding1) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 22 575 obunachidan iborat bo'lib, Taʼlim toifasida 8 822-o'rinni va Hindiston mintaqasida 19 518-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 22 575 obunachiga ega bo‘ldi.

12 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -437 ga, so‘nggi 24 soatda esa -6 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 5.99% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.25% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 1 353 marta ko‘riladi; birinchi sutkada odatda 283 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 2 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, learning kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 13 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

22 575
Obunachilar
-624 soatlar
-967 kunlar
-43730 kunlar
Postlar arxiv
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Work
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📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources English , 🇫🇷 All courses (100 rupees) Contact:- @meterials_available

int solve(vector tc) {     int n = tc.size();     vector p(n), s(n);     p[0] =
int solve(vector tc) {     int n = tc.size();     vector p(n), s(n);     p[0] = tc[0];     for (int i = 1; i < n; ++i) {         p[i] = p[i - 1] + tc[i];     }     s[n - 1] = tc[n - 1];     for (int i = n - 2; i >= 0; --i) {         s[i] = s[i + 1] + tc[i];     }     int m = max(p[0], s[0]);     for (int i = 1; i < n; ++i) {         m = max(m, max(p[i], s[i]));     }     return m; } Amazon

#include #include #include using namespace std; long getkRepValue(string user_history, long k) { &nbsp;&nbsp;&nbsp; long n =
#include <iostream> #include <string> #include <unordered_map> using namespace std; long getkRepValue(string user_history, long k) {     long n = user_history.size();     unordered_map<char, long> count;     long left = 0, right = 0, ans = 0;     while (right < n) {         count[user_history[right]]++;         while (count[user_history[right]] >= k && left <= right) {             ans += n - right;             count[user_history[left]]--;             left++;         }         right++;     }     return ans; }  Machine learning Amazon

📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Work
+8
📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources English , 🇫🇷 All courses (100 rupees) Contact:- @meterials_available

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class Message(object): def init(self, message: str, sender: int, receiver: int) -> None: self.message = message self.sender =
class Message(object):     def init(self, message: str, sender: int, receiver: int) -> None:         self.message = message         self.sender = sender         self.receiver = receiver     def str(self) -> str:         return self.message     def eq(self, other: object) -> bool:         if not isinstance(other, Message):             return False         return self.message == other.message Message Objects

#include <iostream> #include <sstream> #include <string> #include <vector> std::string stemmer(const std::string& text) {     std::stringstream ss(text);     std::string word;     std::vector<std::string> stemmed_words;     while (ss >> word) {         if (word.size() > 2 && (word.substr(word.size() - 2) == "ed" word.substr(word.size() - 2) == "ly" word.substr(word.size() - 3) == "ing")) {             word = word.substr(0, word.size() - 2);         }         if (word.size() > 8) {             word = word.substr(0, 8);         }         stemmed_words.push_back(word);     }     std::string result;     for (const std::string& stemmed_word : stemmed_words) {         result += stemmed_word + " ";     }     result.pop_back();     return result; } int main() {     std::string text = "an extremely dangerous dog is barking";     std::cout << stemmer(text) << std::endl;  // Output: "an extreme dangerou dog is bark"     return 0; } Suffix stripping stemmer Telegram:- @allcoding1

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heights = [int(i) for i in input().split()] freq_dict = {} for h in heights: if h in freq_dict: freq_dict[h] += 1 else: freq_
heights = [int(i) for i in input().split()] freq_dict = {} for h in heights: if h in freq_dict:   freq_dict[h] += 1 else:   freq_dict[h] = 1 for h in sorted(freq_dict): print(h, freq_dict[h])

#include <iostream> #include <string> #include <vector> using namespace std; int numDecodings(string msg) {     int MOD = 1000000007;     int n = msg.size();         vector<long long> dp(n + 1, 0);     dp[0] = 1;         if (msg[0] == '0')         dp[1] = 0;     else if (msg[0] == '*')         dp[1] = 9;     else         dp[1] = 1;         for (int i = 2; i <= n; ++i) {         if (msg[i - 1] == '0') {                         if (msg[i - 2] == '1' || msg[i - 2] == '2')                 dp[i] += dp[i - 2];             else if (msg[i - 2] == '*')                 dp[i] += 2 * dp[i - 2];         } else if (msg[i - 1] >= '1' && msg[i - 1] <= '9') {                   dp[i] += dp[i - 1];                         if (msg[i - 2] == '1' || (msg[i - 2] == '2' && msg[i - 1] <= '6'))                 dp[i] += dp[i - 2];             else if (msg[i - 2] == '*') {                                 if (msg[i - 1] <= '6')                     dp[i] += 2 * dp[i - 2];                 else                     dp[i] += dp[i - 2];             }         } else if (msg[i - 1] == '*') {             dp[i] += 9 * dp[i - 1];                         if (msg[i - 2] == '1')                 dp[i] += 9 * dp[i - 2];             else if (msg[i - 2] == '2')                 dp[i] += 6 * dp[i - 2];             else if (msg[i - 2] == '*')                 dp[i] += 15 * dp[i - 2];         }                 dp[i] %= MOD;     }         return dp[n]; } Number of ways decode

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import re a = int(input().strip()) b = set() c = r'\b[A-Za-z0-9._%+-]+@[A-Za-z0-9.-]+\.[A-Z|a-z]{2,}\b' for _ in range(a): li
import re a = int(input().strip()) b = set() c = r'\b[A-Za-z0-9._%+-]+@[A-Za-z0-9.-]+\.[A-Z|a-z]{2,}\b' for _ in range(a):     line = input().strip()     b.update(re.findall(c, line)) print(';'.join(sorted(b)))

int solve(int k, vector&amp; s) { &nbsp;&nbsp;&nbsp; sort(s.rbegin(), s.rend()); &nbsp;&nbsp;&nbsp; int c = 0; &nbsp;&nbsp;&n
int solve(int k, vector<int>& s) {     sort(s.rbegin(), s.rend());     int c = 0;     for (int i = 0; i < s.size(); i++) {         if (i < k && s[i] > 0) {             c++;         } else if (s[i] == s[i - 1] && s[i] > 0) {             c++;         } else {             break;         }     }     return c; } Competitive Gaming Accenture exam Telegram:- @allcoding1

#include <iostream> #include <vector> #include <algorithm> using namespace std; int findLIS(vector<int>& s) {     vector<int> tails;     for (int x : s) {         auto it = lower_bound(tails.begin(), tails.end(), x);         if (it == tails.end()) {             tails.push_back(x);         } else {             *it = x;         }     }     return tails.size(); }   Swiggy LIS