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allcoding1 (@allcoding1) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 21 578 obunachidan iborat bo'lib, Taʼlim toifasida 9 062-o'rinni va Hindiston mintaqasida 19 025-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 21 578 obunachiga ega bo‘ldi.

29 Avgust, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -360 ga, so‘nggi 24 soatda esa -8 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 5.78% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.10% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 1 247 marta ko‘riladi; birinchi sutkada odatda 238 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 0 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, learning kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 30 Avgust, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

21 578
Obunachilar
-824 soatlar
-787 kunlar
-36030 kunlar
Postlar arxiv
#include <iostream> #include <vector> #include <climits> #include <algorithm> using namespace std; int minimum_energy_cost_recursive(int index,int idxy, int left_consecutive, int right_consecutive, int N, int X, int Y, int El, int Er, vector<int>& weights) {     // Base case: if we have reached the end of bags     if (index > idxy) {         return 0;     }         // Calculate the cost of picking from the left and the right     int cost_left = weights[index] * X + (left_consecutive ? El : 0) +                     minimum_energy_cost_recursive(index + 1,idxy, 1, 0, N, X, Y, El, Er, weights);     int cost_right = weights[idxy] * Y + (right_consecutive ? Er : 0) +                      minimum_energy_cost_recursive(index ,idxy-1, 0, 1, N, X, Y, El, Er, weights);         // Return the minimum of both choices     return min(cost_left, cost_right); } int main() {     int N, X, Y, El, Er;     cin >> N >> X >> Y >> El >> Er;         vector<int> weights(N);     for (int i = 0; i < N; ++i) {         cin >> weights[i];     }         cout << minimum_energy_cost_recursive(0,N-1, 0, 0, N, X, Y, El, Er, weights) << endl;         return 0; } Amazon Hackon exam

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