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allcoding1

allcoding1

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📈 Analytical overview of Telegram channel allcoding1

Channel allcoding1 (@allcoding1) in the English language segment is an active participant. Currently, the community unites 21 531 subscribers, ranking 9 159 in the Education category and 19 101 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 21 531 subscribers.

According to the latest data from 01 September, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -367 over the last 30 days and by -14 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 7.16%. Within the first 24 hours after publication, content typically collects 1.25% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 1 543 views. Within the first day, a publication typically gains 270 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 0.
  • Thematic interests: Content is focused on key topics such as dsa, stack, namaste, javascript, learning.

📝 Description and content policy

Channel description not provided.

Thanks to the high frequency of updates (latest data received on 02 September, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

21 531
Subscribers
-1424 hours
-797 days
-36730 days
Posts Archive
photo content
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Meesho extended there exam date And calling students to virtual interview based on there exam dates Company name : MEESHO Rol
Meesho extended there exam date And calling students to virtual interview based on there exam dates Company name : MEESHO Role: BUSINESS ANALYST Apply Now:- https://docs.google.com/forms/d/e/1FAIpQLSc3DvqJDjZeYjFZX2OgVPwm5shjCX4a0APzYBaTBoPzTf4khg/viewform?pli=1 While applying make sure in your CV mention python and sql. Telegram:- @allcoding1

def PowerLimit(a, b): current_resource, max_seconds = 1, 0 while a > 0 and b > 0: if a > b: current_resource, a, b = 1, a - 2
def PowerLimit(a, b):   current_resource, max_seconds = 1, 0   while a > 0 and b > 0:     if a > b:       current_resource, a, b = 1, a - 2, b + 1     else:       current_resource, b, a = 2, b - 2, a + 1     max_seconds += 1   max_seconds += a // 2 if current_resource == 1 else b // 2   return max_seconds power limit ✅ Telegram:- @allcoding1

long long OneBlock(int N, vector<int> Arr) {     vector<int> one_indices;     for (int i = 0; i < N; ++i) {         if (Arr[i] == 1) {             one_indices.push_back(i);         }     }     if (one_indices.size() <= 1) {         return 1;     }     long long ways = 1;     for (int i = 1; i < one_indices.size(); ++i) {         int zeros_between_ones = one_indices[i] - one_indices[i - 1] - 1;         ways *= (zeros_between_ones + 1);     }     return ways; } //one block C++ Telegram:- @allcoding1_official

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def count(a, X): &nbsp;&nbsp;&nbsp; a.sort() &nbsp;&nbsp;&nbsp; ans = 0 &nbsp;&nbsp;&nbsp; n = len(a) &nbsp;&nbsp;&nbsp; for
def count(a, X):     a.sort()     ans = 0     n = len(a)     for i in range(n):         if (i < n // 2):             ans += max(0, a[i] - X)         elif (i == n // 2):             ans += abs(X - a[i])         else:             ans += max(0, X - a[i]);     return ans IBM Telegram:- @allcoding1

#include using namespace std; void dfs(int node, vector&amp; vis, vector&gt;&amp; adj) { &nbsp;&nbsp;&nbsp; vis[node] = 1; &n
#include<bits/stdc++.h> using namespace std; void dfs(int node, vector<int>& vis, vector<vector<int>>& adj) {     vis[node] = 1;     for(auto it : adj[node]) {         if(!vis[it]) {             dfs(it, vis, adj);         }     } } int main() {     int n, m;     cin >> n >> m;     vector<vector<int>> adj(n);     for(int i = 0; i < n; i++) {         for(int j = 0; j < m; j++) {             int x;             cin >> x;             if(x == 1) {                 adj[i].push_back(j);                 adj[j].push_back(i);             }         }     }     vector<int> vis(n, 0);     int cc = 0;     for(int i = 0; i < n; i++) {         if(!vis[i]) {             dfs(i, vis, adj);             cc++;         }     }     cout << cc << endl;     return 0; } Telegram:- @allcoding1

int solve(vector&amp; nums) { &nbsp;&nbsp;&nbsp; vector s(nums); &nbsp;&nbsp;&nbsp; sort(s.begin(), s.end()); &nbsp;&nbsp;&nb
int solve(vector<int>& nums) {     vector<int> s(nums);     sort(s.begin(), s.end());     int i = 0, j = nums.size() - 1;     while (i < nums.size() && nums[i] == s[i]) {         i++;     }     while (j > i && nums[j] == s[j]) {         j--;     }     return j - i + 1; } Arrange the heights Apple ✅ Telegram:- @allcoding1

#include <bits/stdc++.h> #define ll long long using namespace std; ll solve(ll k, ll s) {     auto comb = [](ll n) {         return n * (n - 1) / 2;     };     if (k > 3 * s) return 0;     ll ans = comb(k + 2);     if (k > s) ans -= 3 * comb(k - s + 1);     if (k - 2 >= 2 * s) ans += 3 * comb(k - 2 * s);     return ans; } int main() {     ll n, s;     cin >> n >> s;     cout << solve(s,n) << endl;     return 0; } Distribute Car Toy Service Now ✅ Telegram:- @allcoding1

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Valid user ✅ Telegram:- @allcoding1
Valid user ✅ Telegram:- @allcoding1