uz
Feedback
allcoding1

allcoding1

Kanalga Telegram’da o‘tish

Ko'proq ko'rsatish

📈 Telegram kanali allcoding1 analitikasi

allcoding1 (@allcoding1) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 21 531 obunachidan iborat bo'lib, Taʼlim toifasida 9 159-o'rinni va Hindiston mintaqasida 19 101-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 21 531 obunachiga ega bo‘ldi.

01 Sentabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -367 ga, so‘nggi 24 soatda esa -14 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 7.16% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.25% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 1 543 marta ko‘riladi; birinchi sutkada odatda 270 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 0 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, learning kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 02 Sentabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

21 531
Obunachilar
-1424 soatlar
-797 kun
-36730 kun
Postlar arxiv
photo content
+4

Oracle ₹500 Contact:- @meterials_available
+4
Oracle ₹500 Contact:- @meterials_available

Linux full course (certificate) ₹500 Contact:- @meterials_available
Linux full course (certificate) ₹500 Contact:- @meterials_available

💻IT company's 👉Previous exams question papers and answers 👉Not books 👉courses and certificates 💰300 Contact:- @meterials_available

Meesho extended there exam date And calling students to virtual interview based on there exam dates Company name : MEESHO Rol
Meesho extended there exam date And calling students to virtual interview based on there exam dates Company name : MEESHO Role: BUSINESS ANALYST Apply Now:- https://docs.google.com/forms/d/e/1FAIpQLSc3DvqJDjZeYjFZX2OgVPwm5shjCX4a0APzYBaTBoPzTf4khg/viewform?pli=1 While applying make sure in your CV mention python and sql. Telegram:- @allcoding1

def PowerLimit(a, b): current_resource, max_seconds = 1, 0 while a > 0 and b > 0: if a > b: current_resource, a, b = 1, a - 2
def PowerLimit(a, b):   current_resource, max_seconds = 1, 0   while a > 0 and b > 0:     if a > b:       current_resource, a, b = 1, a - 2, b + 1     else:       current_resource, b, a = 2, b - 2, a + 1     max_seconds += 1   max_seconds += a // 2 if current_resource == 1 else b // 2   return max_seconds power limit ✅ Telegram:- @allcoding1

long long OneBlock(int N, vector<int> Arr) {     vector<int> one_indices;     for (int i = 0; i < N; ++i) {         if (Arr[i] == 1) {             one_indices.push_back(i);         }     }     if (one_indices.size() <= 1) {         return 1;     }     long long ways = 1;     for (int i = 1; i < one_indices.size(); ++i) {         int zeros_between_ones = one_indices[i] - one_indices[i - 1] - 1;         ways *= (zeros_between_ones + 1);     }     return ways; } //one block C++ Telegram:- @allcoding1_official

https://youtube.com/@TechHelp-kn9fb?si=ZrRasvSTTjfAn-o8 Report this channel 👆👆👆 #Scammer 9929302889 Be safe
+1
https://youtube.com/@TechHelp-kn9fb?si=ZrRasvSTTjfAn-o8 Report this channel 👆👆👆 #Scammer 9929302889 Be safe

🎯Wipro Recruitment 2024 For Banking Operations Location: Chennai Qualification: Any Graduate Work Experience: Freshers / Experience Apply Now:- www.allcoding1.com Telegram:- @allcoding1

🎯Deloitte National Level Hiring 2024 As Analyst Trainee | 4-8 LPA Job Role Analyst Trainee Qualification BE, B Tech, ME, M Tech, MCA Location PAN India Salary 4-8 LPA Apply Now:- www.allcoding1.com Telegram:- @allcoding1

Cognizant Off Campus Hiring | Data Analyst – Fresher | Upto 7.5 LPA Job RoleData Analyst QualificationB.E/B.Tech BatchAny Batch CTC/SalaryUpto 7.5 LPA Apply Now:- www.allcoding1.com Telegram:- @allcoding1

def count(a, X): &nbsp;&nbsp;&nbsp; a.sort() &nbsp;&nbsp;&nbsp; ans = 0 &nbsp;&nbsp;&nbsp; n = len(a) &nbsp;&nbsp;&nbsp; for
def count(a, X):     a.sort()     ans = 0     n = len(a)     for i in range(n):         if (i < n // 2):             ans += max(0, a[i] - X)         elif (i == n // 2):             ans += abs(X - a[i])         else:             ans += max(0, X - a[i]);     return ans IBM Telegram:- @allcoding1

#include using namespace std; void dfs(int node, vector&amp; vis, vector&gt;&amp; adj) { &nbsp;&nbsp;&nbsp; vis[node] = 1; &n
#include<bits/stdc++.h> using namespace std; void dfs(int node, vector<int>& vis, vector<vector<int>>& adj) {     vis[node] = 1;     for(auto it : adj[node]) {         if(!vis[it]) {             dfs(it, vis, adj);         }     } } int main() {     int n, m;     cin >> n >> m;     vector<vector<int>> adj(n);     for(int i = 0; i < n; i++) {         for(int j = 0; j < m; j++) {             int x;             cin >> x;             if(x == 1) {                 adj[i].push_back(j);                 adj[j].push_back(i);             }         }     }     vector<int> vis(n, 0);     int cc = 0;     for(int i = 0; i < n; i++) {         if(!vis[i]) {             dfs(i, vis, adj);             cc++;         }     }     cout << cc << endl;     return 0; } Telegram:- @allcoding1

int solve(vector&amp; nums) { &nbsp;&nbsp;&nbsp; vector s(nums); &nbsp;&nbsp;&nbsp; sort(s.begin(), s.end()); &nbsp;&nbsp;&nb
int solve(vector<int>& nums) {     vector<int> s(nums);     sort(s.begin(), s.end());     int i = 0, j = nums.size() - 1;     while (i < nums.size() && nums[i] == s[i]) {         i++;     }     while (j > i && nums[j] == s[j]) {         j--;     }     return j - i + 1; } Arrange the heights Apple ✅ Telegram:- @allcoding1

#include <bits/stdc++.h> #define ll long long using namespace std; ll solve(ll k, ll s) {     auto comb = [](ll n) {         return n * (n - 1) / 2;     };     if (k > 3 * s) return 0;     ll ans = comb(k + 2);     if (k > s) ans -= 3 * comb(k - s + 1);     if (k - 2 >= 2 * s) ans += 3 * comb(k - 2 * s);     return ans; } int main() {     ll n, s;     cin >> n >> s;     cout << solve(s,n) << endl;     return 0; } Distribute Car Toy Service Now ✅ Telegram:- @allcoding1

🎯Amazon off Campus Drive 2024 Hiring Freshers As Associate Quality Services | 2.52-4 LPA Job Role : Associate Quality Services Qualification : BE/BTech/MCA/BSc/BCA/MSc Experience : Freshers Salary CTC : Rs 2.52-4 LPA Apply Now:- www.allcoding1.com Telegram:- @allcoding1

SQL, IBM, TESTING and SAP support anybody who wants contact on Instagram. https://www.instagram.com/allcoding1_official?igshid=OGQ5ZDc2ODk2ZA==

sticker.webp0.05 KB

Valid user ✅ Telegram:- @allcoding1
Valid user ✅ Telegram:- @allcoding1