allcoding1
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📈 Analytical overview of Telegram channel allcoding1
Channel allcoding1 (@allcoding1) in the English language segment is an active participant. Currently, the community unites 21 545 subscribers, ranking 9 078 in the Education category and 18 983 in the India region.
📊 Audience metrics and dynamics
Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 21 545 subscribers.
According to the latest data from 31 August, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -369 over the last 30 days and by -5 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 6.77%. Within the first 24 hours after publication, content typically collects N/A% reactions from the total number of subscribers.
- Post reach: On average, each post receives 1 460 views. Within the first day, a publication typically gains 0 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 0.
- Thematic interests: Content is focused on key topics such as dsa, stack, namaste, javascript, learning.
📝 Description and content policy
Channel description not provided.
Thanks to the high frequency of updates (latest data received on 01 September, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.
21 545
Subscribers
-524 hours
-817 days
-36930 days
Posts Archive
21 545
Repost from allcoding1
🎯Qualcomm Off Campus Recruitment
Job Position:- IT Software Developer (UX/UI/Fullstack)
Job ID: 3058496
Qualification:- B.Tech
Batch:- 2019/2020/2021
Job Location:- Hyderabad, India
Department: Software Engineering
Salary Package:- As per Company Standards
Job Type:- Full-time
Last Date:- ASAP
Apply Now:- https://www.allcoding1.com/2024/02/qualcomm-off-campus-recruitment-2024.html?m=1
Telegram:- @allcoding1
21 545
500 TB Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
🔹Artificial Intelligence
🔹AWS Certified
🔹Cloud
🔹BIG DATA
🔹Data Analytics
🔹BI
🔹Google Cloud Platform
🔹IT Training
🔹MBA
🔹Machine Learning
🔹Deep Learning
🔹Ethical Hacking
🔹SPSS
🔹Statistics
🔹Data Base
🔹Learning language resources ( English🏴 , French🇨🇵 , German🇩🇪 )
₹50
Contact:- @meterials_available
21 545
![int main() { ll N; cin >> N; vector w(N); for(ll i = 0; i < N; ++i) { cin >> w[i]; } vector s(N, 15); for(ll i](https://cdn.tlmtr.io/_next/static/media/empty-channel.35ed232f.svg)
int main() {
ll N;
cin >> N;
vector<ll> w(N);
for(ll i = 0; i < N; ++i) {
cin >> w[i];
}
vector<ll> s(N, 15);
for(ll i = N-2; i >= 0; --i) {
for(ll j = i+1; j < N; ++j) {
if(w[i] < w[j]) {
s[i] = 10;
for(ll k = j+1; k < N; ++k) {
if(w[j] > w[k]) {
s[i] = 5;
break;
}
}
break;
}
}
}
ll g = 0;
for(ll sc : s) {
g += sc;
}
cout << g << endl;
return 0;
}
chair manufacture
@allcoding1
21 545
int main() {
ll N;
cin >> N;
vector<ll> u(N);
for(ll i = 0; i < N; ++i) {
cin >> u[i];
}
ll M, X;
cin >> M >> X;
vector<vector<ll>> a(N);
for(ll i = 0; i < M; ++i) {
ll x, y;
cin >> x >> y;
a[x].push_back(y);
a[y].push_back(x);
}
vector<bool> v(N, false);
queue<ll> q;
q.push(0);
v[0] = true;
ll m = 0;
while(!q.empty()) {
ll s = q.size();
ll us = 0;
for(ll i = 0; i < s; ++i) {
ll n = q.front();
q.pop();
us += u[n];
for(ll nb : a[n]) {
if(!v[nb]) {
q.push(nb);
v[nb] = true;
}
}
}
m = max(m, us);
}
cout << m << endl;
return 0;
}
apartment
@allcoding1
21 545
class TreeNode:
def init(self, val):
self.val = val
self.children = []
def build_tree(units, relationships):
nodes = {i: TreeNode(units[i]) for i in range(len(units))}
for rel in relationships:
parent, child = rel
nodes[parent].children.append(nodes[child])
return nodes[0]
def max_electricity_per_floor(root):
max_electricity = 0
floor_electricity = {}
def dfs(node, level):
nonlocal max_electricity
if level not in floor_electricity:
floor_electricity[level] = 0
floor_electricity[level] += node.val
max_electricity = max(max_electricity, floor_electricity[level])
for child in node.children:
dfs(child, level + 1)
dfs(root, 0)
return max_electricity
num = int(input())
units = list(map(int, input().split()))
numRel, memConnect = map(int, input().split())
relationships = [tuple(map(int, input().split())) for _ in range(numRel)]
root = build_tree(units, relationships)
result = max_electricity_per_floor(root)
print(result)
Apartment one
@allcoding1
21 545
Repost from allcoding1_official
X(1), (2)
int count;
// Line 1
Antint i) { count 1)
int getcount () {return count)
// Line 5
public class Book
public static void main(String[] args)
System.out.println(AB.X.count + AB.Y.count); // Line 10
Ans)Compile time error at "// Line 10"
@allcoding1_official
21 545
Repost from allcoding1_official
Which of the statement(s) given below is/are correct?
1)Routers can be static or dynamic
2)Routers connect two or more separate networks,
Ans) both 1 and 2
@allcoding1_official
21 545
Repost from allcoding1_official
In MS Word, how can a document be split into multiple parts such that each part can have different formats and layouts
Ans)By creating sections
@allcoding1_official
21 545
Repost from allcoding1_official
How many pairs of letters are there in the word "DYNASTY" which has as many letters between them (from both the sides) as in the alphabets from A to Z?
A) 2
@allcoding1_official
21 545
Repost from allcoding1_official
Mostly, it is students from English mediun schools who appear in this competition
@allcoding1_official
