allcoding1

🎯Qualcomm Off Campus Recruitment Job Position:- IT Software Developer (UX/UI/Fullstack) Job ID: 3058496 Qualification:- B.Tech Batch:- 2019/2020/2021 Job Location:- Hyderabad, India Department: Software Engineering Salary Package:- As per Company Standards Job Type:- Full-time Last Date:- ASAP Apply Now:- https://www.allcoding1.com/2024/02/qualcomm-off-campus-recruitment-2024.html?m=1 Telegram:- @allcoding1

500 TB Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources ( English🏴󐁧󐁢󐁥󐁮󐁧󐁿 , French🇨🇵 , German🇩🇪 ) ₹50 Contact:- @meterials_available

All this 300 rupees only Contact:-  @meterials_available

int main() { ll N; cin >> N; vector<ll> w(N); for(ll i = 0; i < N; ++i) { cin >> w[i]; } vector<ll> s(N, 15); for(ll i = N-2; i >= 0; --i) { for(ll j = i+1; j < N; ++j) { if(w[i] < w[j]) { s[i] = 10; for(ll k = j+1; k < N; ++k) { if(w[j] > w[k]) { s[i] = 5; break; } } break; } } } ll g = 0; for(ll sc : s) { g += sc; } cout << g << endl; return 0; } chair manufacture @allcoding1

int main() { ll N; cin >> N; vector<ll> u(N); for(ll i = 0; i < N; ++i) { cin >> u[i]; } ll M, X; cin >> M >> X; vector<vector<ll>> a(N); for(ll i = 0; i < M; ++i) { ll x, y; cin >> x >> y; a[x].push_back(y); a[y].push_back(x); } vector<bool> v(N, false); queue<ll> q; q.push(0); v[0] = true; ll m = 0; while(!q.empty()) { ll s = q.size(); ll us = 0; for(ll i = 0; i < s; ++i) { ll n = q.front(); q.pop(); us += u[n]; for(ll nb : a[n]) { if(!v[nb]) { q.push(nb); v[nb] = true; } } } m = max(m, us); } cout << m << endl; return 0; } apartment @allcoding1

class TreeNode:     def init(self, val):         self.val = val         self.children = [] def build_tree(units, relationships):     nodes = {i: TreeNode(units[i]) for i in range(len(units))}     for rel in relationships:         parent, child = rel         nodes[parent].children.append(nodes[child])     return nodes[0]  def max_electricity_per_floor(root):     max_electricity = 0     floor_electricity = {}         def dfs(node, level):         nonlocal max_electricity         if level not in floor_electricity:             floor_electricity[level] = 0         floor_electricity[level] += node.val         max_electricity = max(max_electricity, floor_electricity[level])         for child in node.children:             dfs(child, level + 1)         dfs(root, 0)     return max_electricity num = int(input()) units = list(map(int, input().split())) numRel, memConnect = map(int, input().split()) relationships = [tuple(map(int, input().split())) for _ in range(numRel)] root = build_tree(units, relationships) result = max_electricity_per_floor(root) print(result) Apartment one @allcoding1

All this 300 rupees only Contact:-  @meterials_available

All this 300 rupees only Contact:-  @meterials_available

X(1), (2) int count; // Line 1 Antint i) { count 1) int getcount () {return count) // Line 5 public class Book public static void main(String[] args) System.out.println(AB.X.count + AB.Y.count); // Line 10 Ans)Compile time error at "// Line 10" @allcoding1_official

Which of the statement(s) given below is/are correct? 1)Routers can be static or dynamic 2)Routers connect two or more separate networks, Ans) both 1 and 2 @allcoding1_official

In MS Word, how can a document be split into multiple parts such that each part can have different formats and layouts Ans)By creating sections @allcoding1_official

How many pairs of letters are there in the word "DYNASTY" which has as many letters between them (from both the sides) as in the alphabets from A to Z? A) 2 @allcoding1_official

50 @allcoding1_official

33/50 @allcoding1_official

2:1 @allcoding1_official

B @allcoding1_official

Rs:- 1200 @allcoding1_official

Mostly, it is students from English mediun schools who appear in this competition @allcoding1_official

CBEDA @allcoding1_official